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Chapter 1 · ગણ

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  • [section] index section 'સ્વાધ્યાય 1.1' (1.3) has no matching region in the chapter — verify its questions were captured
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  • Q#57 (Multiple Choice Questions (MCQs)): [mcq-as-sub] question carries an option-marker run (A/B/C/D) but the answer has no per-part answers — options merged into the stem?
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  • … and 11 more
⚠ 2 MCQ(s) need an answer — review & set the correct option, or log an error
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S match 50% type: 19 Q ⤓ Export ZIP
#1 SUB

Question

Mk{efhý x2 + x – 2 = 0Lkk Wfu÷økýLku ÞkËeLke heíku ÷¾ku.

Answer

ynª, x2 + x – 2 = 0
∴ (x + 2) (x – 1) = 0
∴ x + 2 = 0 yÚkðk x – 1 = 0
∴ x = –2 yÚkðk x = 1
∴ Wfu÷økýLku ÞkËeLke heíku {–2, 1} ðzu ËþkoðkÞ Au.
#2 SUB

Question

øký {x : x yu ÄLk ÃkqýkOf MktÏÞk Au yLku x2 < 40} Lku ÞkËeLke heíku ÷¾ku.

Answer

ynª, ykÃkýu yuðe ÄLk ÃkqýkOf MktÏÞk þkuÄðe Au su{Lkku ðøko 40 fhíkk LkkLkku nkuÞ.
su{ fu, 1, 2, 3, 4, 5, 6 Lkku ðøko 40 fhíkkt LkkLkku nkuÞ. íkuÚke ykÃku÷ økýLku {1, 2, 3, 4, 5, 6} ðzu ËþkoðkÞ Au.
#3 FB 1M

Question

øký A = {1, 4, 9, 16, 25, .....} Lku økwýÄ{oLke heíku ÷¾ku.

Answer

ynª, ykÃkýLku øký A {kt «kf]ríkf MktÏÞkLkk ðøko ykÃku÷k Au. {kxu ykÃku÷k økýLku,
A = {x : x yu «kf]ríkf MktÏÞkLkku ðøko Au.}
yÚkðk
A = {x : x = n2, n ∈ N} ðzu Ãký ÷¾e þfkÞ Au.
#4 SUB 🖼 3

Question

øký Lku økwýÄ{oLke heíku Ëþkoðku.

Answer

ynª, òuE þfkÞ Au fu Ëhuf ½xfLkku ytþ íkuLkk AuËÚke 1 sux÷ku LkkLkku Au íkÚkk ytþ ykuAk{kt ykuAku 1 yLku ðÄw{kt ðÄw 6 Au. {kxu ykÃku÷ økýLku,
{x : x = , n ∈ N, 1 < n < 6} ðzu Ëþkoðe þfkÞ.
#5 SUB

Question

Lke[uLkk{ktÚke fÞk Mk{qn øký Ëþkoðu Au ? ík{khku sðkçk [fkMkku.
(i) J Úke þY Úkíkk ytøkúuS fì÷uLzhLkk ð»koLkk ík{k{ {rnLkkykuLkku Mk{qn.

Answer

yk Mk{qn øký Ëþkoðu Au fkhý fu J Úke þY Úkíkk ytøkúuS fì÷uLzhLkk {rnLkkyku January, June yLku July Au. yk{, yk Mk{qn MkwÔÞkÏÞkrÞík Au.
(ii) ¼khíkLkk ËMk yrík «rík¼kþk¤e ÷u¾fkuLkku Mk{qn.
yk Mk{qn øký Ëþkoðíkku LkÚke fkhý fu «rík¼kþk¤e ÷u¾f {kxuLkku yr¼«kÞ ÔÞÂõíkyu ÔÞÂõíkyu çkË÷kíkku nkuðkÚke íku MkwÔÞkÏÞkrÞík LkÚke.
(iii) ËwrLkÞkLkk r¢fuxLkk W¥k{ yrøkÞkh çkìxTMk{uLkkuLke xe{.
yk Mk{qn øký Ëþkoðíkku LkÚke fkhý fu W¥k{ çkìxTMk{uLk {kxuLkku yr¼«kÞ ÔÞÂõíkyu ÔÞÂõíkyu çkË÷kÞ {kxu íku MkwÔÞkÏÞkrÞík LkÚke.
(iv) ík{khk ðøkoLkk çkÄk s AkufhkykuLkku Mk{qn.
yk Mk{qn øký Au fkhý fu AkufhkykuLkku Mk{qn MkwÔÞkÏÞkrÞík Au.
(v) 100 Úke LkkLke çkÄe s «kf]ríkf MktÏÞkykuLkku Mk{qn.
yk Mk{qn øký Ëþkoðu Au fkhý fu 100 Úke LkkLke çkÄe s «kf]ríkf MktÏÞkyku MkwÔÞkÏÞkrÞík Au su{ fu 1, 2, 3, ....., 99.
(vi) ÷u¾f {wLþe «u{[tËu ÷¾u÷e çkÄe s Lkð÷fÚkkykuLkku Mk{qn.
yk Mk{qn øký Au fkhý fu {wLþe «u{[tËu ÷¾u÷e çkÄe s Lkð÷fÚkkykuLkku Mk{qn MkwÔÞkÏÞkrÞík Au.
(vii) çkÄk s Þwø{ ÃkqýkOfkuLkku Mk{qn.
yk Mk{qn øký Au fkhý fu çkÄk s Þwø{ ÃkqýkOfku MkwÔÞkÏÞkrÞík Au.
(viii) yk «fhýLkk çkÄk s «§kuLkku Mk{qn.
yk Mk{qn øký Au fkhý fu yk «fhýLkk çkÄk s «§kuLkku Mk{qn MkwÔÞkÏÞkrÞík Au.
(ix) ËwrLkÞkLkkt ¾qçk s ¼ÞkLkf «kýeykuLkku Mk{qn.
yk Mk{qn øký Ëþkoðíkku LkÚke fkhý fu ËwrLkÞkLkkt ¼ÞkLkf «kýeyku rðþuLkku yr¼«kÞ ÔÞÂõíkyu ÔÞÂõíkyu çkË÷kíkku nkuÞ Au.
#6 SUB

Question

A = {1, 2, 3, 4, 5, 6} ÷ku íkÚkk ¾k÷e søÞk{kt ÞkuøÞ Mkt¿kk ∈ yÚkðk ∉ {qfku.

Answer

(i) 5 ∈ A
(ii) 8 ∉ A
(iii) 0 ∉ A
(iv) 4 ∈ A
(v) 2 ∈ A
(vi) 10 ∉ A
#7 SUB

Question

Lke[uLkk økýkuLku ÞkËeLke heíku ÷¾ku :
(i) A = {x : x yu ÃkqýkOf Au yLku –3 < x < 7}

Answer

ynª, ykÃkýu Võík –3 yLku 7 ðå[uLke s ÃkqýkOf MktÏÞkyku ÷¾ðe Au.
∴ A = {–2, –1, 0 , 1, 2, 3, 4, 5, 6}
(ii) B = {x : x yu 6 fhíkkt LkkLke «kf]ríkf MktÏÞk Au.}
∴ B = {1, 2, 3, 4, 5}
(iii) C = {x : x yu suLkk ytfkuLkku Mkhðk¤ku 8 Úkíkku nkuÞ íkuðe çku ytfkuLke MktÏÞk Au.}
∴ C = {17, 26, 35, 44, 53, 62, 71, 80}
fkhý fu, 1 + 7 = 8, 2 + 6 = 8 ðøkuhu.
(iv) D = {x : x yu 60 Lkku ÄLk yðÞð nkuÞ íkuðe yrð¼kßÞ MktÏÞk Au.}
ynª, 60 Lkk fw÷ ÄLk yðÞð 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 Au. íku{ktÚke yrð¼kßÞ 2, 3, 5 Au.
∴ D = {2, 3, 5}
(v) E = TRIGONOMETRY þçËLkk {q¤kûkhkuLkku øký.
E = {T, R, I, G, O, N, M, E, Y}
(vi) F = BETTER þçËLkk {q¤kûkhkuLkku øký.
F = {B, E, T, R}
#8 SUB 🖼 1

Question

Lke[uLkk økýkuLku økwýÄ{oLke heíku ÷¾ku :
(i) {3, 6, 9, 12} = A

Answer

ynª, øký{kt ykÃku÷e MktÏÞkyku 3 Lke økwýf Au.
∴ A = {x : x = 3n, 1 < n < 4, n ∈ N}
(ii) B = {2, 4, 8, 16, 32}
ynª, øký{kt ykÃku÷e MktÏÞkyku 2 Lke ½kíkLkk MðYÃk{kt Au.
∴ B = {x : x = 2n, 1 < n < 5, n ∈ N}
(iii) C = {5, 25, 125, 625}
ynª, øký{kt ykÃku÷e MktÏÞkyku 5 Lke ½kíkLkk MðYÃk{kt Au. {kxu, C = {x : x = 5n, 1 < n < 4, n ∈ N}
(iv) {2, 4, 6,.....} = D
ynª, øký{kt ykÃku÷ MktÏÞkyku 2 Lke økwýf (Þwø{ «kf]ríkf MktÏÞkyku) Au íkÚkk yk yLktík MkwÄe Au.
∴ D = { : x = 2n, n ∈ N}
(v) {1, 4, 9,....., 100} = E
ynª, øký{kt ykÃku÷e MktÏÞkyku Ãkqýoðøko «kf]ríkf MktÏÞkyku Au.
su{ fu,
(1)2 = 1, (2)2 = 4, (3)2 = 9, ....., (10)2 = 100
∴ E = {x : x = n2, 1 < n < 10, n ∈ N}
#9 SUB 🖼 4

Question

Lke[uLkk økýLkk çkÄk s ½xfku ÷¾ku.
(i) A = {x : x yu yÞwø{ «kf]ríkf MktÏÞk Au.}

Answer

A = {1, 3, 5, 7, 9, .....}
(ii) B = {x : x yu ÃkqýkOf Au, < x < }
ynª, < x < Lku –0.5 < x < 4.5 ðzu Ëþkoðíkk ynª, –0.5 yLku 4.5 ðå[uLke ÃkqýkOf MktÏÞkyku ËþkoððkLke Au.
∴ B = {0, 1, 2, 3, 4}
(iii) C = {x : x yu ÃkqýkOf Au, x2 < 4}
ynª, yuðe ÃkqýkOf MktÏÞk ÷uðe Au fu su{Lkku ðøko 4 yLku 4 fhíkkt LkkLkku ÚkkÞ.
∴ C = {–2, –1, 0, 1, 2}
(iv) D = {x : x yu “LOYAL” þçËLkku {q¤kûkh Au.}
D = {L, O, Y, A}
(v) E = {x : x yu ð»koLkku 31 rËðMkLkku Lk nkuÞ íkuðku {rnLkku Au.}
E = {Vuçkúwykhe, yur«÷, sqLk, MkÃxuBçkh, LkðuBçkh}
(vi) F = {x : x yu ytøkúuS {q¤kûkhkuLke ¢{kLkwMkkh ÞkËe{kt K Ãknu÷kLkku ÔÞtsLk}
F = {b, c, d, f, g, h, j}
#10 SUB ▦ 1

Question

zkçke çkkswyu ÞkËeLke heíku Ëþkoðu÷k økýkuLku s{ýe çkkswyu íkuLkk s økwýÄ{oLke heíku Ëþkoðu÷k økýku MkkÚku Mkktf¤ku.

(i)

{1, 2, 3, 6}

(a)

{x : x yu yrð¼kßÞ MktÏÞk Au yLku 6 Lkku yðÞð Au.}

(ii)

{2, 3}

(b)

{x : x yu 10 fhíkkt LkkLke yÞwø{ «kf]ríkf MktÏÞk Au.}

(iii)

{M, A, T, H, E, I, C, S}

(c)

{x : x yu «kf]ríkf MktÏÞk Au yLku 6Lkku yðÞð Au.}

(iv)

{1, 3, 5, 7, 9}

(d)

{x : x yu

MATHEMATICS

þçËLkku {q¤kûkh Au.}

Answer

sðkçkku : (i) → (c) (ii) → (a)
(iii) → (d) (iv) → (b)
su øký yuf Ãký ½xf Ähkðíkku Lk nkuÞ íku{Lku ¾k÷e øký yÚkðk rhõík øký fnu Au.
¾k÷e økýLku Mktfuík{kt φ yÚkðk {} ðzu ËþkoðkÞ Au.
WËknhý : øký A = Éý «kf]ríkf MktÏÞkykuLkku øký.
ynª, fkuE Ãký «kf]ríkf MktÏÞk nt{uþkt ÄLk s nkuÞ {kxu fkuE Éý «kf]ríkf MktÏÞkLkwt yÂMíkíð LkÚke. {kxu yk øký{kt fkuE MkÇÞ Lk nkuðkÚke íku ¾k÷e øký Au.
su øký{kt MkÇÞkuLke MktÏÞk rLkrùíkÃkýu økýe þfkÞ íkuðe nkuÞ yÚkðk su øký ¾k÷e Lk nkuÞ íkuLku yrhõík MkkLík øký fnu Au.
WËknhý : ¼khík{kt ykðu÷k ík{k{ IIT Lkku øký yu MkkLík øký Au.
MkkLík Lk nkuÞ íkuðk økýLku yLktík øký fnu Au. yLktík øký{kt MkÇÞ MktÏÞk Mker{ík LkÚke. íkuÚke yLktík økýLku ÞkËeLke heíku Ëþkoððk {kxu íku øký{kt ykðíkk y{wf MkÇÞku ÷¾eLku ºký xÃkfkt (...) {qfðk{kt ykðu Au.
WËknhý : øký : A = Ãkqýo MktÏÞkykuLkku øký
∴ A = {0, 1, 2, 3,...}
òu çku øký A yLku B çktLkuLkk ½xfku Mk{kLk nkuÞ
(¢{Lkwt {n¥ð LkÚke) íkku íkuðk økýLku Mk{kLk økýku
fnu Au.
íku{Lku Mktfuík{kt A = B ðzu ËþkoðkÞ Au.
WËknhý : A = {a, e, i, o, u},
B = {e, i, a, o, u} ynª, A = B Au.
#11 SUB 🖼 1

Question

Lke[uLkk økýku{ktÚke fÞk MkkLík yLku fÞk yLktík øký Au íku Lk¬e fhku.
(i) {x : x ∈ N yLku (x – 1) (x – 2) = 0}

Answer

ynª, (x – 1) (x – 2) = 0
∴ x – 1 = 0 yÚkðk x – 2 = 0
∴ x = 1 yÚkðk x = 2
∴ ykÃku÷ øký = {1, 2} su MkkLík øký Au.
(ii) {x : x ∈ N yLku x2 = 4}
ynª, x2 = 4
∴ x = ± 2 Ãkhtíkw x ∈ N nkuðkÚke x = 2 ÚkkÞ.
∴ ykÃku÷ øký = {2} su MkkLík øký Au.
(iii) {x : x ∈ N yLku 2x – 1 = 0}
ynª, 2x – 1 = 0 ∴ 2x = 1 ∴ x = ∉ N
Ãkhtíkw x ∈ N nkuðkÚke ykÃku÷ku øký ¾k÷e øký Au. su MkkLík øký Au.
(iv) {x : x ∈ N yLku x yrð¼kßÞ MktÏÞk Au.}
yk øký{kt Ëhuf yrð¼kßÞ MktÏÞkykuLkku Mk{kðuþ Úkíkku nkuðkÚke íku yLktík øký Au.
(v) {x : x ∈ N yLku x yÞwø{ ÃkqýkOf Au.}
yk øký{kt Ëhuf yÞwø{ ÃkqýkOf MktÏÞkykuLkku Mk{kðuþ Úkíkku nkuðkÚke íku yLktík øký Au.
#12 SUB

Question

Mk{kLk økýkuLke òuze þkuÄku (òu nkuÞ íkku). ík{khk W¥kh {kxu fkhý ykÃkku.
A = {0}, B = {x : x > 15 yLku x < 5},
C = {x : x – 5 = 0}, D = {x : x2 = 25},
E = {x : x yu Mk{efhý x2 – 2x – 15 = 0 Lkwt ÄLk ÃkqýkOf çkes Au.}

Answer

ynª, A = {0}, B = φ, C = {5}, D = {–5, 5}, E = {5}
ynª, Võík C = E Au.
#13 SUB 🖼 2

Question

Lke[uLkk{ktÚke fE òuzeLkk øký Mk{kLk Au ? ík{khk sðkçkLke ÞÚkkÚkoíkk [fkMkku.
(i) “ALLOY” Lkk {q¤kûkhkuLkku øký X yLku “LOYAL” Lkk {q¤kûkhkuLkku øký B Au.

Answer

ynª, X = {A, L, O, Y} Úkþu íkÚkk B = {L, O, Y, A} su Mk{kLk Au. {kxu X = B Úkþu.
(ii) A = {n : ∈ Z yLku n2 < 4}, B = {x : x ∈ R yLku x2 – 3x + 2 = 0}
ynª, A = {–2, –1, 0, 1, 2} íkÚkk B = {2, 1} ynª, A ≠ B nkuðkÚke Mk{kLk øký LkÚke.
#14 SUB

Question

Lke[uLkk{ktÚke fÞk øký ¾k÷e økýLkkt WËknhý Au ?
(i) 2 ðzu rð¼kßÞ yÞwø{ «kf]ríkf MktÏÞkykuLkku øký.

Answer

2 ðzu rð¼kßÞ nkuÞ íkuðe Ëhuf «kf]ríkf MktÏÞkyku nt{uþkt Þwø{ s nkuÞ.
∴ ykÃku÷ku øký ¾k÷e øký Au.
(ii) Þwø{ yrð¼kßÞ «kf]ríkf MktÏÞkykuLkku øký.
2 yu Þwø{ yrð¼kßÞ «kf]ríkf MktÏÞk nkuðkÚke ykÃku÷ku øký ¾k÷e øký LkÚke.
(iii) {x : x yu «kf]ríkf MktÏÞk Au, x < 5 yLku x > 7}
fkuE «kf]ríkf MktÏÞk 5 fhíkkt LkkLke nkuÞ yLku 7 fhíkkt {kuxe nkuÞ íku yufMkkÚku þõÞ LkÚke. {kxu ykÃku÷ øký ¾k÷e øký Au.
(iv) {y : y yu çku r¼LLk Mk{ktíkh hu¾kykuLkwt Mkk{kLÞ ®çkËw Au.}
fkuE çku r¼LLk Mk{ktíkh hu¾kyku õÞkhuÞ yufçkeòLku AuËu Lknª. {kxu íku{Lkwt Mkk{kLÞ ®çkËw {¤u Lknª. {kxu ykÃku÷ øký ¾k÷e øký Au.
#15 SUB

Question

Lke[uLkk{ktÚke fÞk øký MkkLík øký yLku fÞk øký yLktík øký Au ?
(i) ð»koLkk {rnLkkykuLkku øký

Answer

ynª, ð»koLkk {rnLkkyku 12 rLkrùík nkuðkÚke íku MkkLík øký Au.
(ii) {1, 2, 3,.....}
ykÃku÷ku øký «kf]ríkf MktÏÞk øký nkuðkÚke íku yLktík øký Au.
(iii) {1, 2, 3,....., 99, 100}
ykÃku÷ku øký yu 1 Úke 100 MkwÄeLke «kf]ríkf MktÏÞkykuLkku Mk{kðuþ fhu Au su rLkrùík nkuðkÚke MkkLík øký Au.
(iv) 100 fhíkkt {kuxk ÄLk ÃkqýkOfkuLkku øký.
ykÃku÷k øký{kt 100 fhíkkt {kuxk nkuÞ íkuðk ík{k{ ÄLk ÃkqýkOfkuLkku Mk{kðuþ Úkíkku nkuðkÚke MkÇÞkuLke MktÏÞk yrLkrùík Au. {kxu ykÃku÷ku øký yLktík øký Au.
(v) 99 fhíkkt LkkLke yrð¼kßÞ MktÏÞkykuLkku øký.
ykÃku÷k øký{kt 99 fhíkkt LkkLke ík{k{ yrð¼kßÞ MktÏÞkykuLkku Mk{kðuþ Úkíkku nkuðkÚke íku{kt MkÇÞkuLke MktÏÞk rLkrùík Au. {kxu ykÃku÷ku øký MkkLík øký Au.
#16 SUB

Question

Lke[uLkk økýku{ktÚke fÞk øký MkkLík yLku fÞk øký yLktík Au íku þkuÄku.
(i) X - yûkLku Mk{ktíkh hu¾kykuLkku øký.

Answer

X - yûkLku Mk{ktíkh nkuÞ íkuðe yLktík hu¾kyku Ëkuhe þfkíke nkuðkÚke ykÃku÷ku øký yLktík øký Au.
(ii) ytøkúuS {q¤kûkhkuLkku øký.
ytøkúuSLkk fw÷ 26 {q¤kûkhku nkuðkÚke ykÃku÷ku øký MkkLík Au.
(iii) 5 Lke økwrýík MktÏÞkykuLkku øký.
ynª, {5, 10, 15, 20,.....} su yLktík øký Ëþkoðu Au.
(iv) Ãk]Úðe Ãkh ðMkíkk «kýeykuLkku øký.
Ãk]Úðe Ãkh økýe þfkÞ íkux÷e MktÏÞk{kt «kýeyku ðMku Au. {kxu ykÃku÷ku øký MkkLík øký Au.
(v) Wøk{®çkËw (0, 0) {ktÚke ÃkMkkh Úkíkkt ðíkwo¤kuLkku øký.
Wøk{®çkËw{ktÚke ÃkMkkh Úkíkk nkuÞ íkuðk yLktík ðíkwo¤ku Ëkuhe þfkÞ. {kxu ykÃku÷ku øký yLktík øký Au.
#17 SUB

Question

Lke[uLkk{ktÚke Lk¬e fhku fu A = B Au fu Lknª.
(i) A = {a, b, c, d}, B = {d, c, b, a}

Answer

ynª, çktLku øký{kt Mk{kLk MkÇÞku nkuðkÚke çktLku øký Mk{kLk Au. {kxu A = B ÚkkÞ.
(ii) A = {4, 8, 12, 16}, B = {8, 4, 16, 18}
ynª, çktLku øký{kt y÷øk MkÇÞku nkuðkÚke A ≠ B.
(iii) A = {2, 4, 6, 8, 10}, B = {x : x yu Þwø{ ÄLk ÃkqýkOf Au yLku x < 10}
ynª, øký B = {2, 4, 6, 8, 10} su øký A Lku Mk{kLk Au. {kxu A = B Au.
(iv) A = {x : x yu 10 Lkku økwrýík Au.}
B = {10, 15, 20, 25, 30,.....}
A = {10, 20, 30, 40,.....} ynª A yLku B çktLku økýLkk MkÇÞku y÷øk nkuðkÚke A ≠ B.
#18 SUB

Question

Lke[u ykÃku÷e òuzeykuLkk øký Mk{kLk Au ? fkhý ykÃkku.
(i) A = {2, 3}, B = {x : x yu x2 + 5x + 6 = 0 Lkku Wfu÷ Au.}

Answer

ynª, Mk{efhý x2 + 5x + 6 = 0
∴ x2 + 3x + 2x + 6 = 0
∴ x (x + 3) + 2 (x + 3) = 0
∴ (x + 3) (x + 2) = 0
∴ x + 3 = 0 yÚkðk x + 2 = 0
∴ x = –3 yÚkðk x = –2
{kxu, B = {–3, –2} íkÚkk A = {2, 3} ykÃku÷ Au.
∴ A ≠ B.
(ii) A = {x : x yu FOLLOW þçËLkku {q¤kûkh Au.}
B = {y : y yu WOLF þçËLkku {q¤kûkh Au.}
A = {F, O, L, W} íkÚkk
B = {W, O, L, F}.
ynª, çktLku øký{kt Mk{kLk MkÇÞku nkuðkÚke A = B Úkþu.
#19 SUB

Question

Lke[u ykÃku÷k øký{ktÚke Mk{kLk øký ÃkMktË fhku.
A = {2, 4, 8, 12}, B = {1, 2, 3, 4}, C = {4, 8, 12, 14},
D = {3, 1, 4, 2}, E = {–1, 1}, F = {0, a},
G = {1, –1}, H = {0, 1}

Answer

ynª, B = {1, 2, 3, 4} yLku D = {3, 1, 4, 2} yu Mk{kLk økýLke òuz Au.
ynª, E = {–1, 1} yLku G = {1, –1} yu Mk{kLk økýLke òuz Au.
òu øký A Lkku «íÞuf ½xf yu øký B Lkku Ãký ½xf nkuÞ íkku øký A Lku øký B Lkku WÃkøký fnuðkÞ Au.
WÃkøkýLku Mktfuík{kt ‘⊂’ ðzu ËþkoðkÞ Au.
ßÞkhu a ∈ A nkuÞ íÞkhu a ∈ B nkuÞ íkku A ⊂ B ÚkkÞ.
òu A yu B Lkku WÃkøký Lk nkuÞ íkku íkuLku A ⊄ B ðzu ËþkoðkÞ Au.
WÃkøkýLke ÔÞkÏÞk ÃkhÚke fne þfkÞ fu, “Ëhuf øký yu ÃkkuíkkLkku WÃkøký Au.”
¾k÷e øký (φ) yu Ëhuf økýLkku WÃkøký Au.
yk{ fne þfkÞ fu, ¾k÷e øký rMkðkÞLkk Ëhuf økýLku ykuAk{kt ykuAk çku WÃkøký íkku nkuÞ s. (a) ¾k÷e øký yLku (b) íku øký Ãkkuíku s.
ynª, MÃkü heíku fne þfkÞ fu,
N ⊂ Z ⊂ Q ⊂ R.
ynª, yMkt{uÞ MktÏÞkøkýLku T ðzu ËþkoðkÞ Au.
T = {x : x ∈ R, x ∉ Q}
∴ T ⊂ R Ãký N ⊄ T.
çku øký A yLku B {kxu òu A ⊂ B yLku A ≠ B íkku A Lku B Lkku Wr[ík WÃkøký fnu Au yLku B Lku A Lkku yrÄøký fnu Au.
òu øký A {kt yuf s MkÇÞ nkuÞ íkku A Lku yufkfe øký (Singleton) fnu Au.
òu øký A {kt MkÇÞkuLke MktÏÞk m nkuÞ íkku íkuLkk fw÷ WÃkøkýkuLke MktÏÞk 2m ÚkkÞ, m > 1, m ∈ N.
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#1 FB 1M

Question

øký φ, A = {1, 3}, B = {1, 5, 9}, C = {1, 3, 5, 7, 9} ykÃku÷kt Au. Lke[u Ëþkoðu÷e Ëhuf økýLke òuzeyku ðå[u Mkt¿kk ⊂ yÚkðk ⊄ Mk{krðü fhku.
(i) φ.....B (ii) A.....B (iii) A.....C (iv) B.....C

Answer

sðkçk : (i) φ yu Ëhuf økýLkku WÃkøký nkuðkÚke,
φ ⊂ B Úkþu.
(ii) A Lkku ½xf 3 yu B {kt Lk nkuðkÚke,
A ⊄ B Úkþu.
(iii) A Lkk çktLku ½xfku C {kt nkuðkÚke,
A ⊂ C Úkþu.
(iv) B Lkk Ëhuf ½xf C {kt nkuðkÚke,
B ⊂ C Úkþu.
#2 SUB

Question

A = {a, e, i, o, u}, B = {a, b, c, d} ÷ku. A yu B Lkku WÃkøký Au ? Lkk. (þk {kxu ?) B yu A Lkku WÃkøký Au ? Lkk. (þk {kxu ?)

Answer

ynª, A Lkku ½xf e yu B {kt LkÚke {kxu A yu B Lkku WÃkøký LkÚke. íkuðe s heíku øký B Lkku ½xf b yu A {kt LkÚke {kxu B yu A Lkku WÃkøký LkÚke.
#3 SUB 🖼 1

Question

A, B yLku C ºký øký Au. òu A ∈ B yLku B ⊂ C íkku A ⊂ C Mkk[wt Au ? òu ík{khku W¥kh Lkk nkuÞ íkku WËknhý ykÃkku.

Answer

‘Lkk.’
Äkhku fu, A = {a},
B = {{a}, b},
C = {{a}, b, c} {kxu
ynª, A Lkku ½xf ‘a’ yu øký C Lkku ½xf LkÚke.
{kxu A ⊄ C ÚkkÞ.
#4 FB 1M

Question

Lke[uLkkt rðÄkLkku MkíÞ çkLku íku heíku ¾k÷e søÞk{kt Mkt¿kk ⊂ yÚkðk ⊄ Ãkqhku :
(i) {2, 3, 4}.....{1, 2, 3, 4, 5}

Answer

⊂
(ii) {a, b, c}.....{b, c, d}
⊄
(iii) {x : x yu ík{khe þk¤kLkku Äkuhý XI Lkku rðãkÚkeo Au.} ..... {x : x yu ík{khe þk¤kLkku rðãkÚkeo Au.}
⊂
(iv) {x : x yu Mk{ík÷{kt ðíkwo¤ Au.} ..... {x : x yu yk s Mk{ík÷Lkwt 1 yuf{ rºkßÞkðk¤wt ðíkwo¤ Au.}
⊄
(v) {x : x yu Mk{ík÷{kt rºkfkuý Au} ..... {x : x yu yk Mk{ík÷{kt ÷tçk[kuhMk Au.}
⊄
(vi) {x : x yu Mk{ík÷{kt Mk{çkksw rºkfkuý Au.} ..... {x : x yu yk s Mk{ík÷Lkku rºkfkuý Au.}
⊂
(vii) {x : x yu Þwø{ «kf]ríkf MktÏÞk Au.} ..... {x : x yu ÃkqýkOf MktÏÞk Au.}
⊂
#5 SUB

Question

Lke[uLkkt rðÄkLkku MkíÞ Au fu yMkíÞ íkuLke [fkMkýe fhku.
(i) {a, b} ⊄ {b, c, a}

Answer

{a, b} ⊂ {b, c, a} nkuðkÚke yMkíÞ Au.
(ii) {a, e} ⊂ {x : x yu ytøkúuS {q¤kûkh ÃkifeLkku yuf Mðh Au.}
MkíÞ Au.
(iii) {1, 2, 3} ⊂ {1, 3, 5}
ynª, 2 ∉ {1, 3, 5} {kxu yMkíÞ Au.
(iv) {a} ⊂ {a, b, c}
MkíÞ Au.
(v) {a} ∈ {a, b, c}
yMkíÞ Au.
(vi) {x : x yu 6 fhíkkt LkkLke Þwø{ «kf]ríkf MktÏÞk Au.} ⊂ {x : x yu 36 Lkku yðÞð nkuÞ íkuðe «kf]ríkf MktÏÞk Au.}
ynª, «Úk{ øký {2, 4} íkÚkk rîíkeÞ øký {1, 2, 3, 4, 6, 9, 12, 18, 36} Au. {2, 4} ⊂ {1, 2, 3, 4, 6, 9, 12, 18, 36} nkuðkÚke ykÃku÷wt rðÄkLk MkíÞ Au.
#6 SUB

Question

A = {1, 2, {3, 4}, 5} íkku Lke[uLkkt rðÄkLkku Ãkife fÞkt rðÄkLkku yMkíÞ Au yLku þk {kxu ?
(i) {3, 4} ⊂ A

Answer

ynª {3, 4} yu øký A Lkku MkÇÞ Au. ykÚke {3, 4} ∈ A ÚkkÞ {kxu ykÃku÷wt rðÄkLk yMkíÞ Au.
(ii) {3, 4} ∈ A
{3, 4} yu øký A Lkku ½xf nkuðkÚke ykÃku÷wt rðÄkLk MkíÞ Au.
(iii) {{3, 4}} ⊂ A
ynª, {3, 4} yu øký A Lkku ½xf nkuðkÚke øký {{3, 4}} yu øký A Lkku WÃkøký fnuðkÞ. {kxu rðÄkLk MkíÞ Au.
(iv) 1 ∈ A
1 yu øký A Lkku MkÇÞ nkuðkÚke ykÃku÷wt rðÄkLk MkíÞ Au.
(v) 1 ⊂ A
1 yu øký A Lkku MkÇÞ nkuðkÚke {1} ⊂ A ÚkkÞ {kxu ykÃku÷wt rðÄkLk yMkíÞ Au.
(vi) {1, 2, 5} ⊂ A
ynª, 1, 2, 5 yu øký A Lkk ½xfku nkuðkÚke ykÃku÷wt rðÄkLk MkíÞ Au.
(vii) {1, 2, 5} ∈ A
ykÃku÷wt rðÄkLk yMkíÞ Au fkhý fu {1, 2, 5} ⊂ A Au.
(viii) {1, 2, 3} ⊂ A
ynª, 3 yu øký A Lkku ½xf Lk nkuðkÚke ykÃku÷wt rðÄkLk yMkíÞ Au.
(ix) φ ∈ A
ynª, φ yu øký A Lkku MkÇÞ Lk nkuðkÚke ykÃku÷wt rðÄkLk yMkíÞ Au.
(x) φ ⊂ A
¾k÷e øký yu Ëhuf økýLkku WÃkøký nkuðkÚke ykÃku÷wt rðÄkLk MkíÞ Au.
(xi) {φ} ⊂ A
ykÃku÷wt rðÄkLk yMkíÞ Au fkhý fu φ ⊂ A Au.
#7 SUB

Question

Lke[u ykÃku÷k økýkuLkk ík{k{ WÃkøkýku ÷¾ku.
(i) {a}

Answer

φ, {a}
(ii) {a, b}
φ, {a, b}, {a}, {b}
(iii) {1, 2, 3}
φ, {1, 2, 3}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}
(iv) φ
φ
#8 SUB

Question

Lke[uLkkLku ytíkhk÷ MðYÃku Ëþkoðku :
(i) {x : x ∈ R, –4 < x < 6}

Answer

(–4, 6]
(ii) {x : x ∈ R, –12 < x < –10}
(–12, –10)
(iii) {x : x ∈ R, 0 < x < 7}
[0, 7)
(iv) {x : x ∈ R, 3 < x < 4}
[3, 4]
#9 SUB

Question

Lke[u ykÃku÷k ytíkhk÷kuLku økwýÄ{oLke heíku ÷¾ku :
(i) (–3, 0)

Answer

{x : x ∈ R, –3 < x < 0}
(ii) [6, 12]
{x : x ∈ R, 6 < x < 12}
(iii) (6, 12]
{x : x ∈ R, 6 < x < 12}
(iv) [–23, 5)
{x : x ∈ R, –23 < x < 5}
#10 SUB

Question

Lke[uLkkt rðÄkLkku {kxu ík{u fÞk økýLku Mkkðorºkf øký íkhefu ÃkMktË fhþku ?
(i) fkxfkuý rºkfkuýkuLkku øký

Answer

ynª, ‘Mk{ík÷{kt ykðu÷k ík{k{ rºkfkuýkuLkk Mk{qn’Lku Mkkðorºkf øký íkhefu ÃkMktË fhe þfkÞ.
(ii) Mk{rî¼ws rºkfkuýkuLkku øký
ynª, ‘Mk{ík÷{kt ykðu÷k ík{k{ rºkfkuýkuLkk Mk{qn’Lku Mkkðorºkf øký íkhefu ÃkMktË fhe þfkÞ.
#11 SUB 🖼 1

Question

A = {1, 3, 5}, B = {2, 4, 6}, C = {0, 2, 4, 6, 8} ykÃku÷ku øký Au. yk ºký øký A, B yLku C {kxu Lke[uLkk{ktÚke fÞk økýLku Mkkðorºkf øký íkhefu ÷E þfkÞ ?
(i) {0, 1, 2, 3, 4, 5, 6}
(ii) φ
(iii) {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
(iv) {1, 2, 3, 4, 5, 6, 7, 8}

Answer

ynª, ykÃku÷k ºkýuÞ øký A, B, C Lkku Mk{kðuþ (iii) {kt ÚkkÞ Au. {kxu (iii) Lku Mkkðorºkf øký íkhefu ÷E þfkÞ Au.
økýku ðå[uLkk ½ýk¾hk MktçktÄkuLku ykf]ríkyku îkhk hsq fhðk{kt ykðu Au. íku{Lku ðuLk ykf]rík fnuðkÞ Au.
ytøkúuS íkfoþkMºke John Venn Lkk Lkk{ ÃkhÚke ðuLk ykf]rík Lkk{ ykÃkðk{kt ykÔÞwt.
Mkk{kLÞ heíku ynª, Mkkðorºkf økýLku (U) ÷tçk[kuhMk ðzu yLku íku{ktÚke çkLkíkk çkeò økýLku ÷tçk[kuhMkLke ytËh ðíkwo¤ku îkhk Ëþkoððk{kt ykðu Au.
(A) Þkuøkøký : fkuE çku øký A yLku B {kxu, A yLku B Lkku Þkuøkøký (Union Set) yux÷u A Lkk ík{k{ ½xfku yLku B Lkk ík{k{ ½xfku y™u íku{Lkk Mkk{kLÞ ½xfkuLku Võík yuf ð¾ík ÷uðkÚke çkLkíkku øký. ÞkuøkøkýLku Mktfuík{kt ‘∪’ ðzu ËþkoðkÞ Au.
∴ A ∪ B = {x : x ∈ A yÚkðk x ∈ B}
Þkuøkøký (∪) {kxu ‘yÚkðk’Lkku Ëk¾÷k{kt WÃkÞkuøk fhðku.
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#1 SUB 🖼 2

Question

A = {2, 4, 6, 8}, B = {6, 8, 10, 12}, íkku A ∪ B {u¤ðku.

Answer

A ∪ B = {2, 4, 6, 8, 10, 12}

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#1 SUB 🖼 7

Question

(i) A = {a, b, c}

Answer

{kxu, A' = U – A = {d, e, f, g, }
(ii) B = {d, e, f, g}
{kxu, B' = {a, b, c, h}
(iii) C = {a, c, e, g}
{kxu, C' = {b, d, f, h}
(iv) D = {f, g, h, a}
{kxu, D' = {b, c, d, e}
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#1 MCQ 1M

Question

çku MkkLík økýLku yLkw¢{u m yLku n ½xf Au. «Úk{ økýLku rîíkeÞ øký fhíkkt 56 sux÷k ðÄw WÃkøký nkuÞ, íkku m = ________, n = ________.

Options

  1. (A) 7, 6
  2. (B) 6, 3
  3. (C) 5, 1
  4. (D) 8, 7

Answer

(B) 6, 3

#2 MCQ 1M

Question

A = {64n : n ∈ N}, B = {32n + 2 – 8n – 9, n ∈ N} íkku...

Options

  1. (A) A = B
  2. (B) A ⊂ B
  3. (C) B ⊂ A
  4. (D) yuf Ãký Lknª

Answer

(C) B ⊂ A

ynª, A = {64n : n ∈ N},
n = 1, 2, 3, ... {qfíkkt,
∴ A = {64, 128, 192, 256, ...}
B = {32n + 2 – 8n – 9, n ∈ N},
n = 1, 2, 3, ... {qfíkkt,
B = {64, 704, 6528, ...}
= {64, 64 × 11, 64 × 102, ...}
∴ MÃkü Au fu, B ⊂ A.
#3 MCQ 1M

Question

Lke[uLkk Ãkife fÞku øký ¾k÷e øký Au ?

Options

  1. (A) {x | x2 – 1 = 0, x ∈ R}
  2. (B) {x | x2 + 1 = 0, x ∈ R}
  3. (C) {x | x2 – 9 = 0, x ∈ R}
  4. (D) {x | x2 = x + 2, x ∈ R}

Answer

(B) {x | x2 + 1 = 0, x ∈ R}

ynª, rðfÕÃk B : x2 + 1 = 0
∴ x2 = –1 su þõÞ LkÚke.
x ∈ R {kxu,
∴ rðfÕÃk B yu ¾k÷e øký Au.
#4 MCQ 1M

Question

X = {4n – 3n – 1, n ∈ N}, Y = {9(n – 1), n ∈ N}, íkku X ∪ Y = ________.

Options

  1. (A) X
  2. (B) Y
  3. (C) N
  4. (D) N – {1}

Answer

(B) Y

ynª, X = {4n – 3n – 1, n ∈ N},
n = 1, 2, 3, ... {qfíkkt,
X = {0, 9, 54, 243, ...} íkÚkk
Y = {9(n – 1), n ∈ N},
n = 1, 2, 3, ... {qfíkkt,
Y = {0, 9, 18, 27, ...} {¤u.
yk{, MÃkü Au fu, X ⊂ Y.
íkuÚke X ∪ Y = Y ÚkkÞ.
#5 MCQ 1M 🖼 1

Question

U = {x | x5 – 6x4 + 11x3 – 6x2 = 0, x ∈ R}, A = {x | x2 – 5x + 6 = 0, x ∈ R}, B = {x | 2 – 3x + 2 = 0, x ∈ R}, íkku (A ∩ B)' = ________.

Options

  1. (A) {1 , 3}
  2. (B) {1, 2, 3}
  3. (C) {0, 1, 3}
  4. (D) {0, 1, 2, 3}

Answer

(C) {0, 1, 3}

A : x2 – 5x + 6 = 0
∴ (x – 3) (x – 2) = 0
∴ x = 3, x = 2
∴ A = {2, 3}
B : x2 – 3x + 2 = 0
∴ (x – 2) (x – 1) = 0
∴ x = 2, x = 1
∴ B = {1, 2}
U : x5 – 6x4 + 11x3 – 6x2 = 0
∴ x2{x3 – 6x2 + 11x – 6} = 0
∴ x2 = 0, x3 – 6x2 + 11x – 6 = 0
∴ x = 0,
nðu, x3 – 6x2 + 11x – 6{kt
x = 1 {qfíkkt íkuLkwt Mk{kÄkLk ÚkkÞ Au.
yk{, (x – 1) yuf yðÞð çkLkþu íkÚkk
x3 – 6x2 + 11x – 6Lkk çkeò yðÞð
þkuÄðk {kxu Lke[u {wsçkLke heíkLkku
WÃkÞkuøk fheyu.
1 1 –6 11 –6
0 1 –5 6
1 –5 6 0
∴ çkeòu yðÞð :
(x2 – 5x + 6) Úkþu.
∴ (x – 2) (x – 3) Úkþu.
yk{, x3 – 6x2 + 11x – 6 = 0
∴ (x – 1) (x – 2) (x – 3) = 0 Úkþu.
∴ x = 1, x = 2, x = 3
∴ U = {0, 1, 2, 3}
nðu, A ∩ B = {2}
∴ (A ∩ B)' = {0, 1, 3}
#6 MCQ 1M

Question

øký A yLku øký BLku yLkw¢{u 3 yLku 6 ½xfku Au, íkku A ∪ B{kt hnu÷ ykuAk{kt ykuAk ½xfkuLke MktÏÞk ?

Options

  1. (A) 3
  2. (B) 9
  3. (C) 6
  4. (D) yuf Ãký Lknª

Answer

(C) 6

øký A yLku B {kxu yuf þõÞíkk,
A = {1, 2, 3},
B = {1, 2, 3, 4, 5, 6} ÷uíkkt,
A ∪ B = {1, 2, 3, 4, 5, 6} ÚkkÞ
yLku çkeS þõÞíkk,
A = {1, 2, 3},
B = {2, 3, 4, 5, 6, 7} ÷uíkkt,
A ∪ B = {1, 2, 3, 4, 5, 6, 7} ÚkkÞ.
ykðe yLkuf þõÞíkkyku rð[khe þfkÞ.
yk{, MÃkü Au fu, A ∪ B{kt
ykuAk{kt ykuAk 6 MkÇÞku nkuÞ s.
#7 MCQ 1M

Question

òu Na = {an : n ∈ N}, íkku N6 ∩ N8 = ________.

Options

  1. (A) N6
  2. (B) N8
  3. (C) N24
  4. (D) N44

Answer

(C) N24

ynª, Na = {aN : n ∈ N}
∴ N6 ∩ N8 = {6n ∩ 8n}, n ∈ N
ynª, 6 yLku 8Lkku ÷.Mkk.y. 24 ÚkkÞ.
∴ N6 ∩ N8 = N24
#8 MCQ 1M

Question

A = {x | x yu 4Lkku økwrýík Au.}, B = {x | x yu 6Lkku økwrýík Au.} íkku A ∩ B yu __________ Lkk çkÄk økwrýíkkuLku Mk{kðu Au.

Options

  1. (A) 16
  2. (B) 12
  3. (C) 8
  4. (D) 4

Answer

(B) 12

ynª, A ∩ B þkuÄðk {kxu 4 yLku 6 Lkku ÷.Mkk.y. ÷uíkkt su 12 ÚkkÞ, {kxu A ∩ B yu 12Lkk økwrýíkkuLkku Mk{kðuþ fhu Au.
#9 MCQ 1M 🖼 13

Question

A = {x : x ∈ R, x > 2}, B = {x : x ∈ R, x < 4}, íkku A ∩ B = ________.

Options

  1. (A) {x : x ∈ R, x < 4}
  2. (B) {x : x ∈ R, 2 < x < 4}
  3. (C) B
  4. (D) A

Answer

(B) {x : x ∈ R, 2 < x < 4}

A : x > 2, x ∈ [2, ∞)
B : x < 4, x ∈ (–∞, 4)
ykÃku÷ WÃkhLke çktLku MktÏÞkhu¾kyku{kt
AuËøký ÷uíkkt,
∴ [2, 4) {¤u.
∴ {x : x ∈ R, 2 < x < 4}
= 2n(A ∪ B) = K ÷uíkkt,
∴ n(A) = , n(B) = ,
n(A ∪ B) = ÚkkÞ.
íkÚkk n(A ∪ B) = n(A) + n(B)
– n(A ∩ B) ÃkhÚke,
∴ n(A ∪ B) =
∴ n(A ∪ B) =
∴ n(A ∪ B) = 90
∴ = + – 15
∴ = – 15
∴ =
∴ 6K = 7K – 180
∴ K = 180
#10 MCQ 1M

Question

çku yrhõík øký A yLku B {kxu, n(A ∩ B) = 15 nkuÞ íkÚkk 4n(A) = 3n(B) = 2n(A ∪ B), íkku n(A ∪ B) = ________.

Options

  1. (A) 90
  2. (B) 180
  3. (C) 135
  4. (D) 45

Answer

(A) 90

#11 MCQ 1M 🖼 8

Question

òu A = {(x, y) : x2 + y2 = 25}, B = {(x, y) : x2 + 9y2 = 144} íkku A ∩ B{kt ½xfkuLke MktÏÞk ________ Au.

Options

  1. (A) 1
  2. (B) 2
  3. (C) 3
  4. (D) 4

Answer

(D) 4

A : x2 + y2 = 25,
B : x2 + 9y2 = 144
÷kuÃkLke heíkLkku WÃkÞkuøk fhíkkt,
x2 + 9y2 = 144
x2 + y2 = 25
– – –
8y2 = 119
∴ y2 =
∴ y = ±
→ x2 + y2 = 25 ÃkhÚke,
∴ x2 = 25 – y2
∴ x2 = 25 –
∴ x2 =
x2 =
∴ x = ±
∴ fw÷ òuz ,
,
yLku
{¤u.
∴ Mkk{kLÞ ½xfkuLke MktÏÞk 4 Au.
∴ n(A ∩ B) = 4
#12 MCQ 1M 🖼 1

Question

A = {x : x2 – 2x + 2 > 0}, B = {x : x2 – 4x + 3 < 0} íkku A ∩ B = ?

Options

  1. (A) [1, ∞)
  2. (B) [1, 3]
  3. (C) (–∞, 3]
  4. (D) (–∞, 1) ∪ (3, ∞)

Answer

(B) [1, 3]

A : x2 – 2x + 2 > 0
ynª, x2 – 2x + 2 yu fkuE Ãký
x ∈ R {kxu ÄLk nkuÞ
∴ A = (–∞, ∞) yÚkðk R.
B : x2 – 4x + 3 < 0
∴ (x – 3) (x – 1) < 0
∴ x ∈ [1, 3] : B
∴ A ∩ B = (–∞, ∞) ∩ [1, 3]
= [1, 3]
#13 MCQ 1M

Question

A = {x : xyu 240Lkk yrð¼kßÞ yðÞð Au.},
B = {x : xyu 240Lkk fkuE Ãký çku yrð¼kßÞ yðÞðLkku Mkhðk¤ku} nkuÞ íkku...

Options

  1. (A) 5∉ A ∩ B
  2. (B) 7∈ A ∩ B
  3. (C) 8∈ A ∩ B
  4. (D) 8∈ A ∪ B

Answer

(D) 8∈ A ∪ B

240 = 24 × 10
= 3 × 2 × 2 × 2 × 5 × 2
= 24 × 3 × 5
\ A = {2, 3, 5}
B = {5, 8, 7}
( 2 + 3 = 5,
3 + 5 = 8,
2 + 5 = 7)
nðu, A ∩ B = {5},
A ∪ B = {2, 3, 5, 7, 8}
yk{, rðfÕÃk [D] MkíÞ Au.
#14 MCQ 1M

Question

òu A, B, C yu yLkw¢{u Student, Progress yLku Congruent þçËLkk {q¤kûkhkuLkku øký nkuÞ íkku n[A ∪ (B ∩ C)] = ________

Options

  1. (A) 8
  2. (B) 9
  3. (C) 10
  4. (D) 11

Answer

(B) 9

A = {S, T, U, D, E, N}
B = {P, R, O, G, E, S}
C = {C, O, N, G, R, U, E, T}
nðu, B ∩ C = {R, O, G, E}
íkÚkk, A ∪ (B ∩ C)
= {S, T, U, D, E, N, R, O, G}
\ n[A ∪ (B ∩ C)] = 9
#15 MCQ 1M

Question

òu n(A) = 25, n(B) = 20, n(C) = 27, n(A ∩ B) = 5, n(A ∩ C) = 7, (B ∩ C) = φ íkku n(A ∪ B ∪ C) = ________.

Options

  1. (A) 65
  2. (B) 60
  3. (C) 68
  4. (D) 72

Answer

(B) 60

ynª, B ∩ C = φ nkuðkÚke,
n(B ∩ C) = 0 ÚkkÞ.
nðu, n(A ∪ B ∪ C)
= n(A) + n(B) + n(C)
– n(A ∩ B) – n(B ∩ C)
– n(C ∩ A) + n(A ∩ B ∩ C)
ÃkhÚke,
∴ n(A ∪ B ∪ C)
= 25 + 20 + 27 – 5 – 7 – 0 + 0
= 60
( B ∩ C = φ
∴ A ∩ B ∩ C = A ∩ φ = φ ÚkkÞ.
∴ n(A ∩ B ∩ C) = 0 ÚkkÞ.)
#16 MCQ 1M

Question

ºký y÷øk øký A, B yLku C {kxu òu n(A) = 10,
n(B) = 6 yLku n(C) = 5, íkku n(A ∪ B ∪ C) = ?

Options

  1. (A) 21
  2. (B) 11
  3. (C) 1
  4. (D) 9

Answer

(A) 21

ynª, ºkýuÞ øký A, B, C ÃkhMÃkh y÷øk øký nkuðkÚke, A ∩ B = φ, B ∩ C = φ, C ∩ A = φ íkÚkk A ∩ B ∩ C = φ ÚkkÞ.
∴ n(A ∪ B ∪ C) = n(A) + n(B)
+ n(C) ÚkkÞ.
∴ n(A ∪ B ∪ C) = 10 + 6 + 5
= 21 ÚkkÞ.
#17 MCQ 1M 🖼 5

Question

{(a, b) : 2a2 + 3b2 = 35, a, b ∈ Z} íkku øký{kt ykðu÷k MkÇÞkuLke MktÏÞk ________ Au.

Options

  1. (A) 2
  2. (B) 4
  3. (C) 8
  4. (D) 12

Answer

(C) 8

ynª, a, b ∈ Z nkuðkÚke ykÃku÷ Mk{efhý{kt bLke y÷øk y÷øk ÃkqýkOf ®f{íkku {qfe aLke y÷øk y÷øk ÃkqýkOf ®f{íkku þkuÄíkkt,
2a2 + 3b2 = 35 ÃkhÚke,
∴ 2a2 = 35 – 3b2
∴ a2 =
→ b = 1 ÷uíkkt,
∴ a2 =
∴ a2 = 16
∴ a = ± 4
yk{, (4, 1), (–4, 1) {¤u.
→ b = 3 ÷uíkkt,
a2 =
∴ a2 = 4
∴ a = ± 2
yk{, (2, 3), (–2, 3) {¤u.
→ b = –1 ÷uíkkt,
∴ a2 =
∴ a2 = 16
∴ a = ± 4
yk{, (4, –1), (–4, –1) {¤u.
→ b = –3 ÷uíkkt,
a2 =
∴ a2 = 4
∴ a = ± 2
yk{, (2, –3), (–2, –3) {¤u.
yk{, fw÷ (a, b)Lke 8 òuz {¤u.
#18 MCQ 1M

Question

A = {x : x yu x2 – 1 = 0Lkwt çkes nkuÞ},
B = {x : x yu x2 – 2x + 1 = 0Lkwt çkes nkuÞ} íkku...

Options

  1. (A) A ∩ B = B
  2. (B) A ∩ B = A
  3. (C) A ∪ B = A
  4. (D) A ∩ B = φ

Answer

(C) A ∪ B = A

ynª, A {kxu,
x2 – 1 = 0
∴ (x – 1) (x + 1) = 0 ∴ x = 1, –1 ∴ A = {1, –1}
∴ B ⊂ C
B {kxu,
x2 – 2x + 1 = 0
∴ (x – 1)2 = 0 ∴ x = 1 ∴ B = {1}
∴ A ∪ B = A
#19 MCQ 1M 🖼 4

Question

øký A = {x : x ∈ R, x4 – x3 – 2x2 + 2 = 0},
B = {x : x ∈ N, 2x2 – 1 < 7}, íkku...

Options

  1. (A) A = B
  2. (B) A ⊂ B
  3. (C) B ⊂ A
  4. (D) A ∩ B = φ

Answer

(C) B ⊂ A

øký A {kxu,
x2 – x3 – 2x2 + 2x = 0
∴ x(x3 – x2 – 2x + 2) = 0
∴ x(x2(x – 1) – 2(x – 1)) = 0
∴ x(x – 1) (x2 – 2) = 0
∴ x = 0, x = 1, x = ±
∴ A = {0, 1, , –}
øký B {kxu,
∴ 2x2 + < 7
∴ 2x2 < 8
∴ x2 < 4
∴ x = 1 ( x ∈ N)
∴ B = {1}
yk{, MÃkü Au fu B ⊂ A.
#20 MCQ 1M 🖼 1

Question

òu U yu Mkkðorºkf øký nkuÞ íkÚkk A ∪ B ∪ C = U, íkku [(A – B) ∪ (B – C) ∪ (C – A)]' = ________.

Options

  1. (A) A ∪ B ∪ C
  2. (B) A ∩ B ∩ C
  3. (C) A ∪ (B ∩ C)
  4. (D) A ∩ (B ∪ C)

Answer

(B) A ∩ B ∩ C

(A – B) ∪ (B – C) ∪ (C – A)
ðuLk ykf]rík ÃkhÚke MÃkü Au fu,
[(A – B) ∪ (B – C) ∪ (C – A)]'
= A ∩ B ∩ C
#21 MCQ 1M 🖼 1

Question

çku MkkLík økýkuLku yLkw¢{u m yLku n MkÇÞku Au (m > n) íkÚkk «Úk{ økýLkk WÃkøkýkuLke MktÏÞk yu çkeò økýLkk WÃkøkýkuLke MktÏÞk fhíkkt 112 sux÷e ðÄkhu nkuÞ, íkku mn = ?

Options

  1. (A) 46
  2. (B) 36
  3. (C) 28
  4. (D) 18

Answer

(C) 28

ynª, 2m = 2n + 112
∴ 2m – 2n = 112
∴ 2n(2m – n – 1) = 24 × 7
∴ 2n(2m – n – 1)
= 24 × (23 – 1)
∴ n = 4 yLku m – n = 3
∴ m – 4 = 3
∴ m = 7
∴ mn = 4 × 7
= 28
#22 MCQ 1M

Question

yMk{íkk x4 – 29x2 + 100 < 0Lkwt Mk{kÄkLk fhíke xLke _______ ®f{íkku {¤u. (ßÞkt, x ∈ Z)

Options

  1. (A) 8
  2. (B) 6
  3. (C) 4
  4. (D) 2

Answer

(C) 4

#23 MCQ 1M

Question

òu n(A) = 10, n(B) = 15, n(A ∪ B) = x, íkku...

Options

  1. (A) 15 < x < 25
  2. (B) 5 < x < 15
  3. (C) 15 < x < 25
  4. (D) 5 < x < 25

Answer

(A) 15 < x < 25

#24 MCQ 1M

Question

òu U = {x : x ∈ N, 2 < x < 12}, A = {x | x yu çkufe yrð¼kßÞ MktÏÞk Au.} B = {x : x yu 12Lkk yðÞð nkuÞ}, íkku Lke[uLkk{ktÚke fÞwt MkíÞ LkÚke ?

Options

  1. (A) A – B = φ
  2. (B) A – B = B ∩ A'
  3. (C) A' – B' = B – A
  4. (D) (A ∩ B)' = A' ∪ B'

Answer

(B) A – B = B ∩ A'

A = {2}
B = {1, 3, 4, 2, 6, 12}
ykÃkýu òýeyu Aeyu fu,
A – B = A ∩ B'
∴ (B) yu MkíÞ LkÚke.
#25 SUB 1M

Question

(i) A – f = _______ . (ii) f – A = ________.
(a) U
(b) A'
(c) f
(d) A

Answer

ÔÞkÏÞk ÃkhÚke,
A – f = {x | x ∈ A yLku x ∉ f}
ÃkhÚke f Lku fkuE MkÇÞ LkÚke.
∴ A – f = {x | x ∈ A} = A
f – A = {x | x ∈ f yLku x ∉ A}
ÃkhÚke f Lku fkuE MkÇÞ LkÚke.
∴ f – A = f
#26 MCQ 1M

Question

A ∪ f = _______ .

Options

  1. (A) A
  2. (B) A'
  3. (C) U
  4. (D) f

Answer

(A) A

A ∪ f = {x | x ∈ A yLku x ∉ f}
= {x | x ∈ A}
= A
#27 MCQ 1M

Question

A ⊂ B ⇔ A – B = ________ .

Options

  1. (A) U
  2. (B) f
  3. (C) A
  4. (D) B

Answer

(B) f

A – B = {x | x ∈ A yLku x ∉ B}
nðu, A ⊂ B
∴ øký ALkku Ëhuf MkÇÞ
øký B{kt Au.
∴ A – B = f
( A{kt nkuÞ yLku B{kt Lk nkuÞ
íkuðk fkuE MkÇÞ Lk {¤u.)
A ⊂ B ⇒ A – B = f
A – B = f
nðu, A – B
= {x | x ∈ A yLku x ∉ B} = f
∴ yuðku fkuE MkÇÞ LkÚke su
øký A{kt nkuÞ yLku
øký B{kt Lk nkuÞ.
∴ A ⊂ B
A – B = f ⇒ A ⊂ B
∴ A ⊂ B ⇔ A – B = f
#28 MCQ 1M

Question

A – B = B – A = f ⇔ ________ .

Options

  1. (A) A ≠ B ≠ f
  2. (B) A ≠ B
  3. (C) A ⊂ B
  4. (D) A = B

Answer

(D) A = B

A – B = {x | x ∈ A yLku x ∉ B}
B – A = {x | x ∈ B yLku x ∉ A}
A – B = B – A
∴ {x | x ∈ A yLku x ∉ B}
= {x | x ∈ B yLku x ∉ A}
∴ zk.çkk. x ∈ A
Ãký s.çkk. x ∉ A yLku
zk.çkk. x ∉ B
Ãký s.çkk. x ∈ B.
∴ òu A = B = f nkuÞ íkku yLku
íkku s {kºk íku þõÞ Au.
#29 MCQ ⚠ needs answer review 1M ▦ 1

Question

Míkt¼ A{kt øký ÞkËeLke heíku yLku Míkt¼ B{kt økwýÄ{oLke heíku Ëþkoðu÷ Au :
Lke[u ÃkifeLke fE òuz ÞkuøÞ Au ?

(A)

(B)

(1)

{L, A, T}

(A)

{x | x yu 4Úke LkkLke «kf]ríkf MktÏÞk Au.}

(2)

{–2, –1, 0, 1, 2}

(B)

{x | x yu LATA þçËLkku {q¤kûkh Au.}

(3)

{1, 2, 3}

(C)

{x | x ∈ Z, x2 < 5}

Answer

not detected

#30 MCQ 1M

Question

A = 100Úke LkkLke Þwø{ MktÏÞkykuLkku Mk{qn
B = 20{e MkËeLkk h{íkðehkuLkku Mk{qn
C = W{kþtfh òu»keyu ÷¾u÷ frðíkkykuLkku Mk{qn
Lke[uLkkt Ãkife fÞwt rðÄkLk MkíÞ Au ?

Options

  1. (A) A yLku B øký Au.
  2. (B) B yu øký LkÚke.
  3. (C) A yLku C øký LkÚke.
  4. (D) A, B yLku C øký Au.

Answer

(B) B yu øký LkÚke.

B yu øký LkÚke.
#31 MCQ 1M

Question

A = {x | x ∈ Z, x4 – 16 = 0} nkuÞ, íkku

Options

  1. (A) A = {– 2, 2}
  2. (B) A = {2}
  3. (C) A = {– 4}
  4. (D) A = {– 4, 4, – 2, 2}

Answer

(A) A = {– 2, 2}

x4 – 16 = 0
\ x4 = 16
\ x = 2, – 2
A = {– 2, 2}
#32 MCQ 1M

Question

òu A = {y | y ∈ N, y3 – 27 = 0} nkuÞ, íkku fÞwt rðÄkLk MkíÞ Au ?

Options

  1. (A) 9 ∈ A
  2. (B) – 3 ∈ A
  3. (C) 3 ∈ A
  4. (D) – 9 ∈ A

Answer

(C) 3 ∈ A

y3 – 27 = 0
\ y3 = 27
\ y = 3
\ A = {3}
#33 MCQ 1M

Question

òu B = {x | x ∈ Z, x2 – 16 = 0} nkuÞ, íkku ¾hwt rðÄkLk ÃkMktË fhku.

Options

  1. (A) 4 ∈ B
  2. (B) – 4 ∉ A
  3. (C) 2 ∉ B
  4. (D) 2 ∈ B

Answer

(A) 4 ∈ B

#34 MCQ 1M

Question

òu B = {f} nkuÞ, íkku

Options

  1. (A) B ¾k÷e øký Au.
  2. (B) B MkkLík øký Au.
  3. (C) B yLktík øký Au.
  4. (D) B yu øký LkÚke.

Answer

(B) B MkkLík øký Au.

B = {f}
B yufkfe øký Au.
íkuÚke B MkkLík øký Au.
#35 MCQ 1M

Question

A = {x | x ∈ N, x2 + 4 = 0} nkuÞ, íkku

Options

  1. (A) A = {– 2, 2}
  2. (B) A = {2}
  3. (C) A = f
  4. (D) A = {f}

Answer

(C) A = f

x2 + 4 = 0
∴ x2 = – 4
su þõÞ LkÚke.
fkuE Ãký «kf]ríkf MktÏÞkLkku ðøko
nt{uþkt ÄLk nkuÞ Au.
∴ A = f
#36 MCQ 1M

Question

a = {x | x yu ALPHA þçËLkku {q¤kûkh Au.}
b = {x | x yu ALPA þçËLkku {q¤kûkh Au.}
g = {L, P, A, H} íkku yMkíÞ rðÄkLk ÃkMktË fhku.

Options

  1. (A) a = g
  2. (B) b = {A, L, P}
  3. (C) a = b
  4. (D) b ∩ g ≠ f

Answer

(C) a = b

a = {A, L, P, H}
b = {A, L, P}
g = {L, P, A, H}
#37 MCQ ⚠ needs answer review 1M ▦ 1

Question

Míkt¼ A{kt y{wf øký ykÃku÷k Au yLku Míkt¼ B{kt WÃkøkýku ykÃku÷k Au.
òu Míkt¼ A{ktLkk ºký økýLku Míkt¼ B{kt íkuLkk WÃkøký MkkÚku òuzeyu íkku Lke[uLkkt{ktÚke fE òuze ÞkuøÞ Au ?

Míkt¼ A

Míkt¼ B

(1)

{1, 3, 5, 7....}

(A)

{1, 19, 21}

(2)

{2, 4, 6, 8....}

(B)

{2, 5, 6, 8, 19}

(3)

{1, 2, 3, 4....}

(C)

{8, 28, 38}

Answer

not detected

(1) {1, 3, 5, 7....}
yufe «kf]ríkf MktÏÞkyku Au.
{1, 19, 21} yufe MktÏÞkyku Au.
\ {1, 19, 21} ⊂ {1, 3, 5, 7...}
\ (1) – (A)
(2) {2, 4, 6, 8....}
çkufe «kf]ríkf MktÏÞkyku Au.
{8, 28, 38} çkufe MktÏÞkyku Au.
\ {8, 28, 38} ⊂ {2, 4, 6, 8...}
\ (2) – (C)
íkuÚke (3) – (B)
#38 MCQ 1M

Question

ðkMíkrðf MktÏÞk øký R {kxu Lke[uLkk Ãkife fÞwt rðÄkLk Mkk[wt LkÚke ?

Options

  1. (A) N ⊂ R
  2. (B) (a, b) ⊂ R; a < b
  3. (C) π ∉ R
  4. (D) f ⊂ R

Answer

(C) π ∉ R

π ∉ R
#39 MCQ 1M

Question

A = {1, 5, 7}, B = {1, 10}, C = {11, 12, ..., 20}
fÞk økýLkk WÃkøký Au ?

Options

  1. (A) {1, 2, 3, ..., 20}
  2. (B) {1, 3, 5, ..., 21}
  3. (C) f
  4. (D) {1, 11, 111, 1111}

Answer

(A) {1, 2, 3, ..., 20}

{1, 2, 3, ..., 20}
#40 MCQ 1M

Question

A = {1, 2, 3, 4}, B = {– 1, 1, 0, – 2, 2},
C = {1, 3, 4}
fÞk økýLkk WÃkøký Au ?

Options

  1. (A) [1, 4]
  2. (B) [– 1, 4]
  3. (C) [– 2, 2]
  4. (D) [– 2, 4]

Answer

(D) [– 2, 4]

[– 2, 4]
#41 MCQ 1M 🖼 9

Question

ytíkhk÷ (– 1, 1] {kxu Lke[uLkk Ãkife fÞwt rðÄkLk Mkk[wt Au ?
42. fE ðuLk ykf]ríkLkku htøkeLk «Ëuþ ¼køk A ∩ B Ëþkoðu Au ?
43. Lke[uLke ðuLk ykf]rík {kxu ¾hwt rðÄkLk ÃkMktË fhku.
A
4
7
1
3
2
6
5
B
U
44. Lke[uLke ðuLk ykf]rík {kxu fÞwt rðÄkLk ¾hwt LkÚke.
a
b
c
d
A
f
g
B
e
U

Options

  1. (A) A = {c, d, f, g}
  2. (B) B = f
  3. (C) U = {a, b, c, d, e, f, g}
  4. (D) A ∪ B = {c, d, f, g}

Answer

(B) B = f

0 ∈ (– 1, 1]
42.
43. U = {1, 2, ..., 7}
44. B = f
#42 MCQ 1M

Question

A = {x | x yu 8 fhíkkt LkkLke «kf]ríkf MktÏÞk Au.}
B = {x | x yu 5 fhíkkt {kuxe yLku 18 fhíkkt LkkLke «kf]ríkf MktÏÞk Au.}, íkku
46. Lke[u Ãkife fÞwt rðÄkLk ¾hwt Au ? (A ≠ φ)
47. Lke[uLkkt Ãkife fÞwt rðÄkLk ¾hwt Au ? (A ≠ B)

Options

  1. (A) (A ∩ B) ⊂ A
  2. (B) (A ∪ B) ⊂ A
  3. (C) (A ∪ B) ∩ B = A
  4. (D) (A ∪ B) ⊂ B

Answer

(A) (A ∩ B) ⊂ A

A = {1, 2, 3, 4, 5, 6, 7}
B = {6, 7, 8, 9, 10, ... 17}
A ∪ B = {1, 2, 3, ... 17}
= {x | x yu 18Úke LkkLke
«kf]ríkf MktÏÞk Au.}
46. A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)
47. (A ∩ B) ⊂ A
#43 MCQ 1M

Question

òu A ⊂ B nkuÞ, íkku

Options

  1. (A) A ∩ B = f
  2. (B) A ∩ B = A
  3. (C) A ∩ B = B
  4. (D) A ∪ B = A

Answer

(B) A ∩ B = A

A ∩ B = A
#44 MCQ 1M

Question

U = {x | x ∈ N, x ≤ 10}, A = {1, 3, 5, 7, 9},
B = {2, 4, 6, 8, 10}, íkku (A ∪ B)' = _______

Options

  1. (A) U
  2. (B) {2}
  3. (C) f
  4. (D) {1, 4, 7, 8}

Answer

(C) f

A ∪ B = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
(A ∪ B)' = f
#45 MCQ 1M

Question

ðkMíkrðf MktÏÞkykuLkk øký R Lku Mkkðorºkf øký ÷Eyu íkku Q' = ______

Options

  1. (A) N
  2. (B) Z
  3. (C) T
  4. (D) R

Answer

(C) T

Q' = {x | x ∈ R, x ∉ Q}
= T (yMkt{uÞ MktÏÞkykuLkku øký)
#46 MCQ 1M 🖼 5

Question

«kf]ríkf MktÏÞkykuLkk økýLku Mkkðorºkf øký ÷Eyu yLku A = {x | x – 8 = 3}, A' = ______
52. U = {x | x ∈ R, 1 < x < 5},
A = {x | x ∈ N, x2 – 6x + 5 = 0} nkuÞ,
íkku A' = ______
53. U = [1, 2], A = {x | x ∈ N, x2 + x – 2 = 0} nkuÞ, íkku A' = ______
54. Lke[u Ãkife fE ðuLk ykf]rík{kt htøkeLk ¼køk (A ∩ B)' Ëþkoðu Au.
55. A = {a, b, d, e}, B = {c, d, f, l, m} yLku
C = {a, l, m, o} nkuÞ, íkku C ∩ (A ∪ B) = ______
56. òu A yLku B çku økýku nkuÞ, íkku A ∩ (A ∪ B) = ______
57. òu A = {1, 2, 3}, B = {3, 4}, C = {4, 5, 6} íkku A ∪ (B ∩ C) = ______
58. òu øký A yLku øký B{kt yLkw¢{u 8 íkÚkk 6 MkÇÞku nkuÞ, íkku A ∪ B {kt ykuAk{kt ykuAk ____ MkÇÞku nkuÞ.
59. Lke[uLkkt Ãkife fÞku øký ¾k÷e øký Au ?
60. çku MkkLík øký{kt yLkw¢{u m yLku n MkÇÞku Au. «Úk{ økýLkkt WÃkøkýkuLke MktÏÞk çkeò økýLkk WÃkøkýkuLke MktÏÞk fhíkkt 56 ðÄkhu Au, íkku m íkÚkk nLke ®f{ík yLkw¢{u ______ Au.
61. òu X yLku Y çku økýku nkuÞ, íkku X ∩ (Y ∪ X)' = ______

Options

  1. (A) X
  2. (B) Y
  3. (C) f
  4. (D) U

Answer

(D) U

x – 8 = 3
x = 11
A = {11}
A' = N – {11}
52. A = {x | x ∈ N, x2 – 6x + 5 = 0}
x2 – 6x + 5 = 0
\ (x – 5)(x – 1) = 0
\ x = 1, 5 ∈ N Au s.
\ A = {1, 5}
\ U = [1, 5]
A' = (1, 5)( A' = U – A)
53. A = {x | x ∈ N, x2 + x – 2 = 0}
x2 + x – 2 = 0
\ (x + 2)(x – 1) = 0
\ x = 1, – 2
ynª, 1 ∈ N, – 2 ∉ N
\ A = {1}
U = [1, 2] A' = (1, 2]
54.
55. ynª, A ∪ B = {a, b, c, d, e, f, l, m}
C = {a, l, m, o}
\ C ∩ (A ∪ B) = {a, l, m}
56. ykÃkýu òýeyu Aeyu fu A ⊂ A ∪ B
\ A ∩ (A ∪ B) = A
57. B ∩ C = {4}
\ A ∪ (B ∩ C) = {1, 2, 3, 4}
58. òu B ⊂ A íkku A ∪ B = A
\ A ∪ B{kt ykuAk{kt ykuAk
MkÇÞku 8 nkuÞ.
òu A ∩ B = f,
íkku n(A ∪ B) = 14 ÚkkÞ.
\ 8 ≤ n(A ∪ B) ≤ 14
#47 MCQ 1M

Question

òu A = {1, 3, 5, 7, 9, 11, 13, 15, 17},
B = {2, 4, 6, 8, .... 18}, N = U, íkku
A' ∪ ((A ∪ B) ∩ B') = ______
63. òu A = {x | x yu 3 Lkku økwýktf Au},
B = {x | x yu 5 Lkku økwýktf Au}, íkku A ∩ B = _____
64. Lke[uLkkt Ãkife fÞku øký MkkLíkøký Au ?

Options

  1. (A) A = {x | x ∈ Z yLku x2 Þwø{ Au.}
  2. (B) B = {x | x ∈ N x > 5}
  3. (C) C = {x | x ∈ R, 0 < x < 1}}
  4. (D) D = {x | x ∈ Z, x2 – 5x + 6 = 0}

Answer

(B) B = {x | x ∈ N x > 5}

(A ∪ B) ∩ B' = A – (A ∩ B)
ynª, A ∩ B = f Au.
\ A' ∪ ((A ∪ B) ∩ B')
= A' ∪ A = N
63. x ∈ A ∩ B
\ x ∈ A yLku x ∈ B
\ x yu 3 Lkku økwýktf Au yLku
x yu 5Lkku økwýktf Au.
\ x yu 15Lkku økwýktf Au.
\ A ∩ B
= {x | x yu 15 Lkku økwýktf Au}
= {15, 30, 45, ...}
64. ynª, x2 – 5x + 6 = 0
\ (x – 3)(x – 2) = 0
\ x = 3, 2 ∈ Z
\ D = {2, 3}
øký D MkkLík øký Au.
#48 MCQ 1M

Question

Äkhku fu U = N. A = Þwø{ «kf]ríkf MktÏÞkykuLkku øký íkku A' = ______.

Options

  1. (A) yÞwø{ «kf]ríkf MktÏÞkykuLkku øký
  2. (B) yrð¼kßÞ MktÏÞkykuLkku øký
  3. (C) Þwø{ MktÏÞkykuLkku øký
  4. (D) N

Answer

(A) yÞwø{ «kf]ríkf MktÏÞkykuLkku øký

U = N = {1, 2, 3, ...}
A = Þwø{ «kf]ríkf MktÏÞkykuLkku øký
A = {2, 4, 6, ...}
∴ A' = {1, 3, 5, ...}
= yÞwø{ «kf]ríkf
MktÏÞkykuLkku øký
#49 MCQ 1M

Question

øký A = {x | x ∈ R, x2 = 16 yLku 2x = 6} yu ________ Au.

Options

  1. (A) φ
  2. (B) (4, –4)
  3. (C) {4, –4, 3}
  4. (D) {3}

Answer

(A) φ

øký A = {x | x ∈ R, x2 = 16
yLku 2x = 6}
= {x | x ∈ R, x = ±4
yLku x = 3}
∴ A = {–4, 3, 4} yLku
AuË {–4, 4} ∩ {3}
= φ
#50 MCQ 1M 🖼 1

Question

òu A, B, C ºký yrhõíkøkýku nkuÞ íkku,
(A ∩ B) ∩ (B ∩ C) ∩ (C ∩ A) ______

Options

  1. (A) A ∪ B ∪ C
  2. (B) A ∩ B ∩ C
  3. (C) φ
  4. (D) U

Answer

(B) A ∩ B ∩ C

ðuLk ykf]rík ÃkhÚke,
yrhõík økýku A, B, C {kxu
(A ∩ B) ∩ (B ∩ C) ∩ (C ∩ A)
= A ∩ B ∩ C ÚkkÞ.
#51 MCQ 1M

Question

Éý ðkMíkrðf MktÏÞkykuLkku øký

Options

  1. (A) (–∞, 0]
  2. (B) (–∞, 0)
  3. (C) {..., –3, –2, –1)
  4. (D) {x | x ∈ Q, x < 0}

Answer

(B) (–∞, 0)

ynª (–∞, 0)
yu Éý ðkMíkrðf MktÏÞkykuLkku øký ÚkkÞ.
#52 MCQ 1M

Question

yLk]ý ðkMíkrðf MktÏÞkykuLkku øký

Options

  1. (A) [0, ∞)
  2. (B) (0, ∞)
  3. (C) (–∞, 0)
  4. (D) N

Answer

(A) [0, ∞)

yLk]ý ðkMíkrðf MktÏÞkyku yux÷u Éý Lk nkuÞ íkuðe ðkMíkrðf MktÏÞkyku ÚkkÞ.
0 yu ÄLk fu Éý LkÚke.
∴ [0, ∞) {kxu,
∀ x ∈ [0, ∞) x > 0 ÚkkÞ.
#53 MCQ 1M

Question

ytíkhk÷ [5, ∞) Lke ÷tçkkE ______.

Options

  1. (A) 5
  2. (B) 4
  3. (C) Lk {¤u
  4. (D) 0

Answer

(C) Lk {¤u

Lk {¤u
#54 MCQ 1M

Question

B = {2, 3, 4}, C = {2, 3, 5}, X ⊂ B, X ≠ B, X ⊄ C þhíkkuLkwt Ãkk÷Lk fhíkkt ík{k{ X = ______.

Options

  1. (A) {4}, {2, 4}, {3, 4}
  2. (B) {4}, {2, 5}, {3, 4}
  3. (C) {2}, {3}, {2, 3}
  4. (D) {4}

Answer

(A) {4}, {2, 4}, {3, 4}

B = {2, 3, 4},
C = {2, 3, 5}, X ⊂ B,
X ≠ B, X ⊄ C
∴ X = {4},
X = {2, 4},
X = {3, 4}
∴ X = {4}, {2, 4}, {3, 4}
su þõÞ çkLku.
#55 MCQ 1M 🖼 1

Question

òu U = N, A = {x | x ∈ N, x yu 3Lkku yðÞðe}, íkku (A')' = ______.

Options

  1. (A) N
  2. (B) A
  3. (C) {x | x ∈ N, x yu 3Lkku yðÞðe Lk nkuÞ}
  4. (D) φ

Answer

(B) A

U = {1, 2, 3, 4, ...}
A = {x | x ∈ N, x yu 3Lkku yðÞðe}
= {3, 6, 9, 12, ...}
∴ (A')' = A
∴ ALkk WÃkøkýLke MktÏÞk BLkk
fw÷ WÃkøkýLke MktÏÞk fhíkkt 16
økýe nkuðkÚke,
2p = 16 × 2q
∴ = 16
∴ (2)p–q = 24
∴ p – q = 4
#56 MCQ 1M

Question

òu n(A) = p, n(B) = q yLku A Lkk fw÷ WÃkøkýkuLke MktÏÞk BLkk fw÷ WÃkøkýkuLke MktÏÞk fhíkkt 16 økýe Au, íkku p – q ______.

Options

  1. (A) 4
  2. (B) 2
  3. (C) 16
  4. (D) 8

Answer

(A) 4

#57 MCQ 1M 🖼 6

Question

òu A = {x | 3x2 – 7x – 6 = 0, x ∈ R} yLku
B = {x | 6x2 – 5x – 6 = 0, x ∈ R}
íkku A ∩ B = ______.

Options

  1. (A)
  2. (B)
  3. (C) {3}
  4. (D) φ

Answer

(B)

A = {x | 3x2 – 7x – 6 = 0, x ∈ R}
= {x | 3x2 – 9x + 2x – 6 = 0,
x ∈ R}
= {x | 3x (x – 3) + 2(x – 3) = 0,
x ∈ R}
= {x | (3x + 2) (x – 3), x ∈ R}
=
B = {x | 6x2 – 5x – 6 = 0, x ∈ R}
= {x | 6x2 – 9x + 4x – 6 = 0,
x ∈ R}
= {x | 3x(2x – 3) + 2(2x – 3) = 0,
x ∈ R}
= {x | (3x + 2) (2x – 3) = 0,
x ∈ R}
=
∴ A ∩ B =
{{íkk þ{koyu Äkuhý XILkk ðøko rþûkf Au. su{Lku ºký økýLku Lke[u {wsçk ËþkoÔÞk fu suÚke
A = {1, 3, 5, 7, 9},
B = {2, 4, 6, 8} yLku
C = {2, 3, 5, 7, 11}.
(i) A yLku CLkku AuËøký ÷¾ku.
(ii) A yLku B yu y÷øk øký Au fu Lknª íku Lk¬e fhku.
(iii) B ∩ C = ________.
(iv) A ∩ B ∩ C = ________.
Mk{sqíke :
(i) A ∩ C = {1, 3, 5, 7, 9} ∩ {2, 3, 5, 7, 11}
= {3, 5, 7}
(ii) A ∩ B = {1, 3, 5, 7, 9} ∩ {2, 4, 6, 8}
= φ
∴ A yLku B yu y÷øk øký Au.
(iii) B ∩ C = {2, 4, 6, 8} ∩ {2, 3, 5, 7, 11}
= {2}
(iv) A ∩ B ∩ C = φ ∩ C
= φ
Lke[u ykÃku÷ øký A = {1, 2, 3, 4},
B = {3, 4, 5, 6},
C = {5, 6, 7, 8} yLku
D = {7, 8, 9, 10} nkuÞ íkku,
(i) A ∪ B = ________.
(ii) B ∪ C ∪ D = ________.
(iii) A ∪ B ∪ D = ________.
(iv) B ∪ D = ________.
Mk{sqíke :
(i) A ∪ B = {1, 2, 3, 4} ∪ {3, 4, 5, 6}
= {1, 2, 3, 4, 5, 6}
(ii) B ∪ C ∪ D = {3, 4, 5, 6} ∪ {5, 6, 7, 8}
∪ {7, 8, 9, 10}
= {3, 4, 5, 6, 7, 8, 9, 10}
(iii) A ∪ B ∪ D = {1, 2, 3, 4} ∪ {3, 4, 5, 6}
∪ {7, 8, 9, 10}
= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
(iv) B ∪ D = {3, 4, 5, 6} ∪ {7, 8, 9, 10}
= {3, 4, 5, 6, 7, 8, 9, 10}
WÃkøkýLke MktÏÞk = 2n, ßÞkt, n yu øký{kt hnu÷k ½xfkuLke MktÏ[k Au.
Lke[u ykÃku÷ økýLkkt WÃkøký ÷¾ku.
(i) A = {a}
(ii) B = {a, b}
(iii) C = {1, 2, 3}
(iv) D = φ
Mk{sqíke :
(i) A = {a}
ALkk WÃkøkýLke MktÏÞk = 2'
= 2
∴ ALkk WÃkøkýku = φ, {a}
(ii) B = {a, b}
BLkk WÃkøkýLke MktÏÞk = 22
= 4
BLkk WÃkøkýku = φ, {a}, {b}, {a, b}
(iii) C = {1, 2, 3}
CLkk WÃkøkýLke MktÏÞk = 2n
= 23
= 8
CLkk WÃkøkýku = φ, {1}, {2}, {3}, {1, 2},
{1, 3}, {2, 3}, {1, 2, 3}
(iv) D = φ
DLkk WÃkøkýLke MktÏÞk = 2°
= 1
DLkk WÃkøkýku = φ
Ãkqhf øký : øký A rMkðkÞLkk Mkkðorºkf øký U{kt nkuÞ íkuðk ½xfkuÚke çkLkíkk økýLku Ãkqhf øký fnu Au.
A' = U – A
WÃkhLke {krníke ÃkhÚke Lke[uLkk «§kuLkk sðkçk ykÃkku.
(i) U = {1, 2, 3, 4, 5, 6, 7, 8, 9}
A = {1, 2, 3, 4}, B = {2, 4, 6, 8} yLku
C = {3, 4, 5, 6} nkuÞ, íkku (A ∪ C)' þkuÄku.
(ii) U = {1, 2, 3, 4, 5, 6, 7, 8, 9}
A = {1, 2, 3, 4}, B = {2, 4, 6, 8} yLku
C = {3, 4, 5, 6} nkuÞ, íkku (A')' þkuÄku.
(iii) U = {1, 2, 3, 4, 5, 6, 7, 8, 9}
A = {1, 2, 3, 4}, B = {2, 4, 6, 8} yLku
C = {3, 4, 5, 6} nkuÞ, íkku (B – C)' þkuÄku.
(iv) U = {1, 2, 3, 4, 5, 6, 7, 8, 9}
A = {1, 2, 3, 4}, B = {2, 4, 6, 8} yLku
C = {3, 4, 5, 6} nkuÞ, íkku (A ∪ B)' þkuÄku.
Mk{sqíke :
(i) A ∪ C = {1, 2, 3, 4} ∪ {3, 4, 5, 6}
= {1, 2, 3, 4, 5, 6}
(A ∪ C)' = U – (A ∪ C)
∴ (A ∪ C)' = {1, 2, 3, 4, 5, 6, 7, 8, 9}
– {1, 2, 3, 4, 5, 6}
= {7, 8, 9}
(ii) A' = U – A
= {1, 2, 3, 4, 5, 6, 7, 8, 9} – {1, 2, 3, 4}
= {5, 6, 7, 8, 9}
(A')' = U – A'
= {1, 2, 3, 4, 5, 6, 7, 8, 9} – {5, 6, 7, 8, 9}
= {1, 2, 3, 4}
= A
(iii) B – C = {2, 4, 6, 8} – {3, 4, 5, 6}
= {2, 8}
(B – C)' = U – (B – C)
= {1, 2, 3, 4, 5, 6, 7, 8, 9} – (2, 8)
= {1, 3, 4, 5, 6, 7, 9}
(iv) A ∪ B = {1, 2, 3, 4} ∪ {2, 4, 6, 8}
= {1, 2, 3, 4, 6, 8}
(A ∪ B)' = U – (A ∪ B)
= {1, 2, 3, 4, 5, 6, 7, 8, 9}
– {1, 2, 3, 4, 6, 8}
= {5, 7, 9}
½kíkøký : øký ALkk WÃkøkýkuÚke çkLkíkk økýLku øký ALkku ½kíkøký fnu Au.
suLku P(A) ðzu ËþkoðkÞ Au.
WÃkhLke {krníke ÃkhÚke Lke[uLkk «§kuLkk sðkçk ykÃkku.
(i) A = {a, b} nkuÞ, íkku P(A) {u¤ðku.
(ii) B = {1, 2, 3, 4} nkuÞ, íkku P(B) {u¤ðku.
(iii) C = {a} nkuÞ, íkku P(C) þkuÄku.
(iv) D = {a, b, c} nkuÞ, íkku P(D) þkuÄku.
Mk{sqíke :
(i) A = {a, b}
P(i) = {φ, {a}, {b}, {a, b}}
(ii) B = {1, 2, 3, 4}
P(ii) = {φ, {1}, {2}, {3}, {4}, {1, 2}, {1, 3},
{1, 4}, {2, 3}, {2, 4}, {3, 4},
{1, 2, 3}, {1, 2, 4}, {1, 3, 4},
{2, 3, 4}, {1, 2, 3, 4}}
(iii) C = {a}
P(iii) = {φ, {a}}
(iv) D = {a, b, c}
P(iv) = {φ, {a}, {b}, {c}, {a, b}, {a, c}, {b, c}, {a, b, c}}
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