{ "chapter_id": 4, "chapter_title": "Amines", "uploaded_filename": "Chapter9.zip", "uploaded_sha256": "d6ad77f3b5b3fef7cda6cdb736719c1f8f7aabf26d6de77f43cf06a38dd3eb92", "status": "confirmed", "sections": [ { "section_id": "4.2", "section_title": "Topic-wise Q & A", "heading_text": "Topic-wise Questions and Answers", "detected_type": "SUB", "match_confidence": 0.609, "questions": [ { "sequence_no": 1, "question_text": "
What are amine compounds? Explain with an example.
", "answer_text": "
Amines can be considered as derivatives of ammonia.
\n
The compounds obtained when one, two or three hydrogen atoms in ammonia are displaced by an alkyl or aryl group are called amine compounds.
\n
\te.g. CH3 – NH2, C6H5 – NH2, CH3 – NH – CH3, CH3 – N \"\" etc...
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/3.png", "position": "answer", "context": "e.g. CH 3 – NH 2 , C 6 H 5 – NH 2 , CH 3 – NH – CH 3 , CH 3 …" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "1", "original_raw_text": " What are amine compounds? Explain with an example.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 2, "question_text": "
Explain the structure of amine compounds by drawing a diagram.
", "answer_text": "
Like ammonia, nitrogen atom of amines is trivalent and carries an unshared pair of electrons.
\n
Nitrogen orbitals in amines are therefore, sp3 hybridized and the geometry of amines is pyramidal.
\n
Each of the three sp3 hybridized orbitals of nitrogen overlap with orbitals of hydrogen or carbon depending upon the composition of the amines.
\n
The fourth orbital of nitrogen in all amines contains an unshared pair of electrons.
\n
The angle C–N–E (where E is C or H) is less than 109.5°.
\n
For instance, it is 108° in case of trimethylamine as in the figure below:
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/6.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "2", "original_raw_text": " Explain the structure of amine compounds by drawing a diagram.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 3, "question_text": "
Explain the classification of amine compounds.
", "answer_text": "
Amine compounds are classified as primary (1°), secondary (2°) and tertiary (3°) depending upon the number of hydrogen atoms replaced by alkyl or aryl groups in ammonia molecule.
\n
If one hydrogen atom of ammonia is replaced by R or Ar, we get RNH2 or ArNH2, a primary amine (1°).
\n
If two hydrogen atoms of ammonia or one hydrogen atom of R–NH2 are replaced by another alkyl/aryl (R') group we get secondary amine (2°) R–NH–R'.
\n
\tThe second alkyl/aryl group may be same or different.
\n
Replacement of another hydrogen atom by alkyl/aryl group leads to the formation of tertiary amine (3°).
\n
\tNH2 → RNH2 → \"\" → \"\"
\n
\t\tPrimary (1°)\tsecondary (2°)\ttertiary (3°)
\n
Amines are said to be 'simple' when all the alkyl or aryl groups are the same, and 'mixed' when they are different.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/9.png", "position": "answer", "context": "NH 2 → RNH 2 → →" }, { "id": "img-1", "path": "Chapter9/10.png", "position": "answer", "context": "NH 2 → RNH 2 → →" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "3", "original_raw_text": " Explain the classification of amine compounds. ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 4, "question_text": "
Give IUPAC name of the following compounds.
", "answer_text": "
(i) \"\"\t(ii) CH3 – CH2 – NHCOCH3
\n
Ans.\t(i) \"\"
\n
\t\tN, N – Dimethyl propan-2-amine.
\n
\t(ii)\tCH3 – CH2 – NH – COCH3
\n
\t\tN – Ethylethanamide.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/13.png", "position": "answer", "context": "(i) (ii) CH 3 – CH 2 – NHCOCH 3" }, { "id": "img-1", "path": "Chapter9/14.png", "position": "answer", "context": "Ans. (i)" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-6", "source_number": "4", "original_raw_text": " Give IUPAC name of the following compounds.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2", "needs_review": true, "needs_boundary_review": true, "boundary_review_reason": "answer has 1 content line(s) before its answer marker ('Ans. (i)') — pre-marker content belongs to the question" } }, { "sequence_no": 5, "question_text": "
Write the IUPAC names of the compounds as shown below. If possible, write their common names and types of amines.
", "answer_text": "", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [ { "id": "tbl-1", "rows": 9, "columns": 5, "raw_html": "\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
\n

No.

\n		\n

Structure

\n		\n

IUPAC Names

\n		\n

Common Name

\n		\n

Types

\n
\n

(i)

\n		\n

\"\"

\n		\n

N-Methyl ethanamine

\n		\n

Ethyl methyl amine

\n		\n

2°

\n
\n

(ii)

\n		\n

\"\"

\n		\n

N, N–Dimethyl methanamine

\n		\n

Trimethyl amine

\n		\n

3°

\n
\n

(iii)

\n		\n

\"\"

\n		\n

N, N–Diethyl
Butan-1-amine

\n		\n

N, N–Dimethyl
butyl amine

\n		\n

3°

\n
\n

(iv)

\n		\n

\"\"

\n		\n

prop-2-en-1-amine

\n		\n

Allylamine

\n		\n

1°

\n
\n

(v)

\n		\n

NH2 – (CH2)6 – NH2

\n		\n

Hexane 1, 6-Diamine

\n		\n

Hexamethylene diamine

\n		\n

1°, 1°

\n
\n

(vi)

\n		\n

\"\"

\n		\n

Aniline OR
Benzenamine

\n		\n

Aniline

\n		\n

1°

\n
\n

(vii)

\n		\n

\"\"

\n		\n

2-Methyl Aniline

\n		\n

O-Toluidine

\n		\n

1°

\n
\n

(viii)

\n		\n

\"\"

\n		\n

N, N-Di methyl Benzenamine

\n		\n

N, N-Dimethyl
aniline

\n		\n

3°

\n
", "position": "answer", "context": "No. Structure IUPAC Names Common Name Types (i) N-Methyl eth…" } ], "metadata": { "source_class": "Quest", "source_number": "5", "original_raw_text": " Write the IUPAC names of the compounds as shown below. If possible, write their common names and types of amines.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 6, "question_text": "
Write a note on formation of amine compounds by reduction of nitro compounds.
", "answer_text": "
Nitro compounds are reduced to amines by passing hydrogen gas in the presence of finely divided nickel, palladium or platinum and also by reduction with metals in acidic medium.
\n
Nitroalkanes can also be similarly reduced to the corresponding alkanamines.
\n
\t(i)\t \"\"
\n
(ii) \"\"
\n
Reduction with iron scrap and hydrochloric acid is preferred because FeCl2 formed gets hydrolysed to release hydrochloric acid during the reaction.
\n
Fe + 2HCl → H2 + FeCl2
\n
FeCl2 + H2O → Fe(OH)2 + 2HCl
\n
Thus, only a small amount of hydrochloric acid is required to initiate the reaction.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/26.png", "position": "answer", "context": "(i)" }, { "id": "img-1", "path": "Chapter9/28.png", "position": "answer", "context": "(ii)" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "6", "original_raw_text": " Write a note on formation of amine compounds by reduction of nitro compounds.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 7, "question_text": "
Describe the formation of amine compounds by ammonolysis of alkyl halide compounds.
\n
OR
\n
\tWrite short notes on: Ammonolysis
", "answer_text": "
The carbon–halogen bond in alkyl or benzyl halides can be easily cleaved by nucleophile.
\n
Hence, an alkyl or benzyl halide on reaction with an ethanolic solution of ammonia undergoes nucleophilic substitution reaction in which
the halogen atom is replaced by an amino
(–NH2) group.
\n
This process of cleavage of the C–X bond by ammonia molecule is known as ammonolysis.
\n
The reaction is carried out in a sealed tube at 373 K.
\n
The primary amine obtained which behaves as a nucleophile and can further react with alkyl halide to form secondary and tertiary amines, and finally quaternary ammonium salt.
\n
\"\" \"\"
\n
The free amine can be obtained from the ammonium salt by treatment with a strong base:
\n
\"\"
\n
Ammonolysis has the disadvantage of yielding a mixture of primary, secondary and tertiary amines and also a quaternary ammonium salt.
\n
However, primary amine is obtained as a major product by taking large excess of ammonia.
\n
The order of reactivity of halides with amines is RI > RBr > RCl.
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/30.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/31.png", "position": "answer", "context": "" }, { "id": "img-2", "path": "Chapter9/32.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest", "source_number": "7", "marks": 3, "boundary_log": [ "or_alt→stem" ], "original_raw_text": " Describe the formation of amine compounds by ammonolysis of alkyl halide compounds.\nOR\n\tWrite short notes on: Ammonolysis ", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 8, "question_text": "
Discuss the formation of amine compounds by reduction of nitrile and amide compounds.
", "answer_text": "
Nitriles on reduction with lithium aluminium hydride (LiAlH4) or catalytic hydrogenation produce primary amines. This reaction is used for ascent of amine series, i.e., for preparation of amines containing one carbon atom more than the starting amine.
\n
\tR – C ≡ N \"\" R – CH2 – NH2
\n
e.g. \"\" \"\" \"\"
\n
The amides on reduction with lithium aluminium hydride yield amines.
\n
\"\"\"\" R – CH2 – NH2
\n
e.g. \"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/34.png", "position": "answer", "context": "R – C ≡ N R – CH 2 – NH 2" }, { "id": "img-1", "path": "Chapter9/35.png", "position": "answer", "context": "e.g." }, { "id": "img-2", "path": "Chapter9/36.png", "position": "answer", "context": "e.g." }, { "id": "img-3", "path": "Chapter9/37.png", "position": "answer", "context": "e.g." }, { "id": "img-4", "path": "Chapter9/38.png", "position": "answer", "context": "R – CH 2 – NH 2" }, { "id": "img-5", "path": "Chapter9/39.png", "position": "answer", "context": "R – CH 2 – NH 2" }, { "id": "img-6", "path": "Chapter9/40.png", "position": "answer", "context": "e.g." } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "8", "original_raw_text": " Discuss the formation of amine compounds by reduction of nitrile and amide compounds.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 9, "question_text": "
Give following conversion in three steps: Ethanoic acid into Methanol.
", "answer_text": "
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/43.png", "position": "answer", "context": "Ans." } ], "tables": [], "metadata": { "source_class": "Quest", "marks": 3, "source_number": "9", "original_raw_text": "Give following conversion in three steps: Ethanoic acid into Methanol.", "deduction_level": 0, "source_html": "Chapter9", "boundary_log": [ "leading-marker-stripped" ], "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 10, "question_text": "
Write short note on: Gabriel phthalimide synthesis.
", "answer_text": "
Gabriel synthesis is used for the preparation of primary amines. Phthalimide on treatment with ethanolic potassium hydroxide forms potassium salt of phthalimide which on heating with alkyl halide followed by alkaline hydrolysis produces the corresponding primary amine. Aromatic primary amines can not be prepared by this method because aryl halides do not undergo nucleophilic substitution with the anion formed by phthalimide.
\n
\"\"
\n
\"\"
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/45.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/46.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-22", "marks": 3, "source_number": "10", "original_raw_text": " Write short note on: Gabriel phthalimide synthesis.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 11, "question_text": "
Explain the formation of amines by Hofmann bromamide degradation reaction and state the features of this process.
\n
OR
\n
\tWrite short notes on: Hofmann's bromamide  reaction.
", "answer_text": "
Hofmann developed a method for preparation of primary amines by treating an amide with bromine in an aqueous or ethanolic solution of sodium hydroxide. In this degradation reaction, migration of an alkyl or aryl group takes place from carbonyl carbon of the amide to the nitrogen atom.
\n
The amine so formed contains one carbon less than that present in the amide.
\n
\"\"
\n
Example:(1) \"\"
\n
CH3 – NH2 + Na2CO3 + 2NaBr + 2H2O
\n
Example:(2) \"\"
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/48.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/49.png", "position": "answer", "context": "Example:(1)" }, { "id": "img-2", "path": "Chapter9/50.png", "position": "answer", "context": "Example:(2)" } ], "tables": [], "metadata": { "source_class": "Quest", "source_number": "11", "marks": 2, "boundary_log": [ "or_alt→stem" ], "original_raw_text": " Explain the formation of amines by Hofmann bromamide degradation reaction and state the features of this process.\n OR\n\tWrite short notes on: Hofmann's bromamide  reaction.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 12, "question_text": "
State the general physical properties of amine compounds.
", "answer_text": "
The lower aliphatic amines are gases with fishy odour.
\n
Primary amines with three or more carbon atoms are liquid and still higher ones are solid.
\n
Aniline and other arylamines are usually colourless but get coloured on storage due to atmospheric oxidation.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "12", "original_raw_text": " State the general physical properties of amine compounds.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 13, "question_text": "
Write note on solubility of amine compounds. Explain which of the amine and alcohol compounds has higher solubility? Why?
", "answer_text": "
Lower aliphatic amines are soluble in water because they can form hydrogen bonds with water molecule.
\n
However, solubility decreases with increase in molar mass of amines due to increase in size of the hydrophobic alkyl part.
\n
Higher amines are essentially insoluble in water.
\n
Considering the electro negativity of nitrogen of amine and oxygen of alcohol as 3.0 and 3.5 respectively, this means that since the oxygen atom is more electro negative than the nitrogen atom, alcohol compounds can form strong hydrogen bonds with water. Hence, amine compounds have lower water solubility than alcohol compounds.
\n
Amines are soluble in organic solvents like alcohol, ether and benzene.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "13", "original_raw_text": " Write note on solubility of amine compounds. Explain which of the amine and alcohol compounds has higher solubility? Why?", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 14, "question_text": "
Discuss the effect of hydrogen bonding on the boiling point of isomeric amine compounds.
", "answer_text": "
Primary and secondary amines are engaged in inter molecular association due to hydrogen bonding between nitrogen on one and hydrogen of another molecule.
\n
This intermolecular association is more in primary amines than in secondary amines as there are two hydrogen atoms available for hydrogen bond formation in it.
\n
Tertiary amines do not have intermolecular association due to the absence of hydrogen atom available for hydrogen bond formation.
\n
Therefore, the order of boiling points of isomeric amines is as follows:
\n
\tPrimary > Secondary > Tertiary
\n
\tIntermolecular hydrogen bonding in primary amines is shown in figure.
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/57.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-22", "source_number": "14", "original_raw_text": " Discuss the effect of hydrogen bonding on the boiling point of isomeric amine compounds. ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 15, "question_text": "
Explain the basic characterization of amine compounds with the process equation and state the importance of the process.
", "answer_text": "
Amines, being basic nature react with acids to form salts.
\n
\"\"
\n
Amine salts on treatment with a base like NaOH, regenerate the parent amine.
\n
Amine salts are soluble in water but insoluble in organic solvents like ether. This reaction is the basis for the separation of amines from the non basic organic compounds insoluble in water.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/61.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "15", "original_raw_text": " Explain the basic characterization of amine compounds with the process equation and state the importance of the process.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 16, "question_text": "
Arrange the following in increasing order of their basic strength.
\n
\t(i) C6H5NH2, C6H5N(CH3)2, (C2H5)2NH
\n
\t(ii) Aniline, p-nitro aniline, p-toluidine
\n
\t(iii) C6H5NH2, C6H5NHCH3, C6H5CH2NH2
", "answer_text": "
(i) C6H5NH2 < C6H5N(CH3)2 < (C2H5)2NH
\n
\t(ii) Aniline < p-nitro < p-toluidine
\n
(iii) C6H5NH2 < C6H5NHCH3 < C6H5CH2NH2
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-6", "source_number": "16", "marks": 3, "original_raw_text": " Arrange the following in increasing order of their basic strength.\n\t(i) C6H5NH2, C6H5N(CH3)2, (C2H5)2NH\n\t(ii) Aniline, p-nitro aniline, p-toluidine\n\t(iii) C6H5NH2, C6H5NHCH3, C6H5CH2NH2", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 17, "question_text": "
Explain the basicity of alkanamine compounds relative to ammonia in gaseous state based on inductive effect of the alkyl group.
", "answer_text": "
Let us consider the reaction of an alkanamine and ammonia with a proton to compare their basicity.
\n
\"\"
\n
\"\"
\n
Due to the electron releasing nature of alkyl group a pushes electrons towards nitrogen and thus makes the unshared electron pair more available for sharing with the proton of the acid.
\n
Moreover, the substituted ammonium ion formed from the amine gets stabilized due to dispersal of the positive charge by the +I effect of the alkyl group.
\n
Hence, alkylamines are stronger bases than ammonia.
\n
Thus, the basic nature of aliphatic amines should increase with increase in the number of alkyl groups.
\n
The order of basicity of amines in gaseous phase follows the expected order:
\n
\ttertiary amine > secondary amine > primary amine > ammonia
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/65.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/66.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest", "source_number": "17", "original_raw_text": " Explain the basicity of alkanamine compounds relative to ammonia in gaseous state based on inductive effect of the alkyl group.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 18, "question_text": "
State the factors that determine the basicity of alkyl amine compounds in aqueous medium and explain the order of basicity of alkyl amine compounds based on these factors.
", "answer_text": "
There is a subtle interplay of the inductive effect, solvation effect and steric hinderance of the alkyl group which decides the basic strength of alkyl amines in aqueous state.
\n
In the aqueous phase the substituted ammonium cations get stabilised not only by electron releasing effect of the alkyl group (+I) but also by solvation with water molecules.
\n
The greater the size of the ion, lesser will be the solvation and the less stabilized is the ion.
\n
The order of stability of ions are as follows:
\n
Greater is the stability of the substituted ammonium cation, stronger should be the corresponding amine as a base.
\n
Thus, the order of basicity of aliphatic amines should be primary > secondary > tertiary which is opposite to the inductive effect based order.
\n
Secondly, when the alkyl group is small like –CH3 group there is no steric hinderance to H-bonding.
\n
In case the alkyl group is bigger than CH3 group there is steric hinderance to H-bonding.
\n
Therefore, the change of nature of the alkyl group e.g. from –CH3 to –C2H5 results in change of the order of basic strength.
\n
The order of basic strength in case of methyl substituted amines and ethyl substituted amines in aqueous solution is as follows:
\n
\t(C2H5)2 NH > (C2H5)3 N > C2H5NH2 > NH3
\n
\t(CH3)2 NH > CH3NH2 > (CH3)3 N > NH3
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/69.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "marks": 2, "source_number": "18", "original_raw_text": " State the factors that determine the basicity of alkyl amine compounds in aqueous medium and explain the order of basicity of alkyl amine compounds based on these factors.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 19, "question_text": "
Describe the basic strength of aryl amine compounds relative to ammonia.
", "answer_text": "
In aniline or other arylamines, the –NH2 group is attached directly to the benzene ring. It results in the unshared electron pair on nitrogen atom to be in conjugation with the benzene ring and thus making it less available for protonation.
\n
Five resonance Hybrid structures of aniline are as following:
\n
\"\"
\n
On the other hand, anilinium cation obtained by accepting a proton can have only two resonating structures.
\n
\"\"
\n
We know that greater the number of resonating structures greater is the stability, thus aniline is more stable than anilinium ion.
\n
Hence, the proton acceptability or the basic nature of aniline or other aromatic amines would be less than that ammonia.
\n
In case of substituted aniline, it is observed that electron releasing groups like –OCH3, –CH3 increase basic strength where as electron withdrawing groups like –NO2, –SO3H, –COOH, –X decrease it.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/71.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/72.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-10", "source_number": "19", "original_raw_text": " Describe the basic strength of aryl amine compounds relative to ammonia. ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 20, "question_text": "
Explain the alkylation process of amine compounds with example.
", "answer_text": "
The primary amine can react with alkyl halide, to form secondary and tertiary amines, and finally quaternary ammonium salt.
\n
\"\"
\n
The order of reactivity of halides with amines is RI > RBr > RCI
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/76.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "20", "original_raw_text": " Explain the alkylation process of amine compounds with example.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 21, "question_text": "
Write detailed note on acylation of amine compounds. [June 2024]
\n
OR
\n
\tWrite short notes on: Acetylation.
", "answer_text": "
“Aliphatic and aromatic primary and secondary amines react with acid chlorides, anhydrides and esters by nucleophilic substitution reaction. This reaction is known as acylation.”
\n
This reaction is the replacement of hydrogen atom of –NH2 and \"\" of group by the acyl group.
\n
The reaction is carried out in the presence of a base stronger than the amine like pyridine, which removes the formed HCl and shifts the equilibrium to the right hand side.
\n
\"\"
\n
\"\"
\n
\"\"
\n
Amines also react with benzoyl chloride (C6H5COCl) this reaction is known as benzoylation.
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/78.png", "position": "answer", "context": "This reaction is the replacement of hydrogen atom of –NH 2 a…" }, { "id": "img-1", "path": "Chapter9/79.png", "position": "answer", "context": "" }, { "id": "img-2", "path": "Chapter9/80.png", "position": "answer", "context": "" }, { "id": "img-3", "path": "Chapter9/81.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Normal", "pyq": true, "source_number": "21", "marks": 3, "boundary_log": [ "or_alt→stem" ], "original_raw_text": " Write detailed note on acylation of amine compounds. [June 2024] \n OR\n\tWrite short notes on: Acetylation. ", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 22, "question_text": "
Give conversion in three steps: Nitrobenzene into chlorobenzene.
", "answer_text": "
Nitrobenzene into chlorobenzene
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/84.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest", "marks": 3, "source_number": "22", "original_raw_text": " Give conversion in three steps: Nitrobenzene into chlorobenzene.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 23, "question_text": "
Explain the carbylamine reaction of amine compounds.
\n
OR
\n
Write short notes on: carbylamine reaction.
", "answer_text": "
Aliphatic and aromatic primary amines on heating with chloroform and Ethanolic potassium hydroxide form isocyanides or carbylamines which are foul smelling substances.
\n
Secondary and tertiary amines do not show this reaction.
\n
This reaction is known as carbylamine reaction or isocyanide test and is used as a test for primary amines.
\n
R – NH2 + CHCl3 + 3KOH \"\" R – NC + 3KCl + 3H2O
\n
\te.g.\t(1)\t\"\"
\n
\t\t(2)\t\"\"
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/86.png", "position": "answer", "context": "R – NH 2 + CHCl 3 + 3KOH R – NC + 3KCl + 3H 2 O" }, { "id": "img-1", "path": "Chapter9/87.png", "position": "answer", "context": "e.g.\t(1)" }, { "id": "img-2", "path": "Chapter9/88.png", "position": "answer", "context": "(2)" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "23", "marks": 2, "boundary_log": [ "or_alt→stem" ], "original_raw_text": " Explain the carbylamine reaction of amine compounds. \nOR\n Write short notes on: carbylamine reaction.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 24, "question_text": "
Explain the reaction of primary aliphatic amine and aromatic amine compounds with nitrous acid with necessary equations.
\n
Or
\n
\tWrite the reactions of
\n
\t(i) aromatic and
\n
\t(ii) aliphatic primary amines with nitrous acid.
", "answer_text": "
(i)\tPrimary aliphatic amines react with nitrous acid to form aliphatic diazonium salts, which are unstable and quantitatively liberate nitrogen gas along with alcohols. Quantitative evolution of nitrogen is used in estimation of amino acids and proteins.
\n
R – NH2 + HNO2
\n
\t[R – N2+CI –] \"\" ROH + N2 + HCI
\n
(ii)\tAromatic amines react with nitrous acid at low temperatures to form diazonium salts.
\n
A very important class of compounds used for synthesis of a variety of aromatic compounds.

\"\"

", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/92.png", "position": "answer", "context": "[R – N 2 + CI – ] ROH + N 2 + HCI" }, { "id": "img-1", "path": "Chapter9/93.png", "position": "answer", "context": "A very important class of compounds used for synthesis of a …" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-22", "marks": 3, "source_number": "24", "boundary_log": [ "or_alt→stem" ], "original_raw_text": " Explain the reaction of primary aliphatic amine and aromatic amine compounds with nitrous acid with necessary equations.\nOr\n\tWrite the reactions of \n\t(i) aromatic and\n\t(ii) aliphatic primary amines with nitrous acid.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 25, "question_text": "
Write a note on the reaction of amine compounds with arylsulphonyl chloride and state the utility of this reaction.
\n
Or
\n
\tDescribe the method for the determination of primary, secondary and tertiary amines. Write the chemical equations involved.
\n
Or
\n
\tExplain with equations how primary, secondary and tertiary amine compounds can be separated using the Hinsberg reaction.
", "answer_text": "
The reaction of amine compounds with arylsulphonyl chloride (benzenesulphonyl chloride, C6H5SO2Cl) is known as the Hinsberg test.
\n
This test is used to distinguish and separate primary, secondary, and tertiary amines.
\n
(a)\tReaction with Primary Amine
\n
A primary amine reacts with benzenesulphonyl chloride to form N-substituted benzenesulphonamide, which is soluble in alkali.
\n
\"\"
\n
The sulphonamide formed contains a hydrogen atom attached to nitrogen, which is acidic due to the electron-withdrawing sulphonyl group.
\n
Hence, it dissolves in aqueous alkali.
\n
(b)\tReaction with Secondary Amine
\n
A secondary amine reacts with benzenesulphonyl chloride to form N, N-disubstituted benzene-sulphonamide, which is insoluble in alkali.\"\"
\n
The product does not contain any hydrogen atom attached to nitrogen, so it is not acidic and hence insoluble in alkali.
\n
(c)\tReaction with Tertiary Amine
\n
A tertiary amine does not react with benzenesulphonyl chloride.
\n
However, it dissolves in dilute acids due to the formation of an ammonium salt.
\n
The different behaviour of primary, secondary, and tertiary amines towards benzenesulphonyl chloride is useful in:
\n
\t•\tIdentifying the type of amine
\n
\t•\tSeparating mixtures of amines
\n
At present, p-toluenesulphonyl chloride is commonly used instead of benzenesulphonyl chloride.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/95.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/96.png", "position": "answer", "context": "A secondary amine reacts with benzenesulphonyl chloride to f…" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-22", "source_number": "24", "marks": 3, "boundary_log": [ "or_alt→stem" ], "original_raw_text": " Write a note on the reaction of amine compounds with arylsulphonyl chloride and state the utility of this reaction.\nOr\n\tDescribe the method for the determination of primary, secondary and tertiary amines. Write the chemical equations involved. \nOr\n\tExplain with equations how primary, secondary and tertiary amine compounds can be separated using the Hinsberg reaction.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 26, "question_text": "
Explain the bromination of Aniline. State what is done if mono substituted derivative of aniline is to be formed by this process.
", "answer_text": "
Aniline reacts with bromine water at room temperature to give a white precipitate of
2, 4, 6-tribromoaniline.
\n
\"\"
\n
Aromatic amine compounds are very reactive towards electrophilic substitution reactions.
\n
If we have to prepare monosubstituted aniline derivative than we have to control the activating effect of –NH2 group.
\n
This can be done by protecting the –NH2 group by acetylation with acetic anhydride, then carrying out the desired substitution followed by hydrolysis of the substituted amide to the substituted amine.
\n
\"\"
\n
The lone pair of electrons on nitrogen of acetanilide interacts with oxygen atom due to resonance as shown below:
\n
\"\"
\n
Hence, the lone pair of electrons on nitrogen is less available for donation to benzene ring by resonance. Therefore activating effect of –NHCOCH3 group is less than that of amino group.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/98.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/99.png", "position": "answer", "context": "" }, { "id": "img-2", "path": "Chapter9/100.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest", "marks": 3, "source_number": "26", "original_raw_text": " Explain the bromination of Aniline. State what is done if mono substituted derivative of aniline is to be formed by this process. ", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 27, "question_text": "
Explain nitration of aniline. Explain what is done by this process to obtain the para nitro derivative as the major product.
", "answer_text": "
Direct nitration of aniline yields tarry oxidation products in addition to the nitro derivatives. Moreover in the strongly acidic medium, aniline is protonated to form the anilinium ion which is meta directing. That is why besides the ortho and para derivatives, significant amount of meta derivative is also formed.
\n
However by protecting the –NH2 group by acetylation reaction with acetic anhydride, the nitration reaction can be controlled and the P-nitro derivative can be obtained as the major product.
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/103.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "marks": 3, "source_number": "27", "original_raw_text": " Explain nitration of aniline. Explain what is done by this process to obtain the para nitro derivative as the major product.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 28, "question_text": "
Short note: Sulphonation of Aniline.
", "answer_text": "
Aniline reacts with concentrated sulphuric acid to form anilinium hydrogensulphate which on heating with sulphuric acid of 453–473K produces P-amino benzene sulphonic acid commonly known as sulphanilic acid as the major product.
\n
\"\"
\n
Diazonium Salts
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/105.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest", "source_number": "28", "original_raw_text": " Short note: Sulphonation of Aniline. ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 29, "question_text": "
Give the general formula of diazonium salt. State the possible negative ions present in this salt and explain with an example how diazonium salts are named.
", "answer_text": "
The diazonium salts have the general formula RN2+X–, where R stands for an aryl group and X– ion may be Cl–, Br–, HSO4–, BF4– etc.
\n
They are named by suffixing diazonium to the name of the parent hydrocarbon from which they are formed, followed by the name of anion such as chloride, hydrogensulphate, etc.
\n
The \"\" group is called diazonium group.
\n
For example, \"\" is named as benzene diazonium chloride and \"\" is known as benzenediazonium hydrogen sulphate.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/107.png", "position": "answer", "context": "The group is called diazonium group." }, { "id": "img-1", "path": "Chapter9/108.png", "position": "answer", "context": "For example, is named as benzene diazonium chloride and is k…" }, { "id": "img-2", "path": "Chapter9/109.png", "position": "answer", "context": "For example, is named as benzene diazonium chloride and is k…" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "marks": 2, "source_number": "29", "original_raw_text": " Give the general formula of diazonium salt. State the possible negative ions present in this salt and explain with an example how diazonium salts are named. ", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 30, "question_text": "
Give the resonance structure of arenediazonium ion.
", "answer_text": "
\tResonance structure of arenediazonium ion is as follows.
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/111.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "marks": 2, "source_number": "30", "original_raw_text": " Give the resonance structure of arenediazonium ion.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 31, "question_text": "
Q.31 Write a note on the formation of benzene diazonium chloride. OR
\n
Write short notes on: Diazotisation
", "answer_text": "
Benzenediazonium chloride is prepared by the reaction of aniline with nitrous acid at 273-278 K.
\n
Nitrous acid is produced in the reaction
mixture by the reaction of sodium nitrite with hydrochloric acid.
\n
The conversion of primary aromatic amines into diazonium salts is known as diazotization.
\n
Due to its instability, the diazonium salt is not generally stored and is used immediately after its preparation.
\n
C6H5NH2 + NaNO2 + 2HCl \"\"
\n
C6H5N+2Cl– + NaCl + 2H2O
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/114.png", "position": "answer", "context": "C 6 H 5 NH 2 + NaNO 2 + 2HCl" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "marks": 2, "original_raw_text": "Q.31 Write a note on the formation of benzene diazonium chloride. OR\n Write short notes on: Diazotisation", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2", "needs_review": true, "needs_layout_review": true, "layout_review_reason": "question body contains an embedded question heading ('Q.31 Write a note on the formation') — a separate question merged in" } }, { "sequence_no": 32, "question_text": "
Describe the physical properties of benzenediazonium salts.
", "answer_text": "
Benzene diazonium chloride is a colourless crystaline solid.
\n
It is readily soluble in water and is stable in cold but reacts with water when warmed.
\n
It decomposes easily in the dry state.
\n
Benzene diazonium fluoroborate is water insoluble and stable at room temperature.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "32", "original_raw_text": " Describe the physical properties of benzenediazonium salts.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 33, "question_text": "
State the types of chemical reaction of diazonium salts.
", "answer_text": "
The reactions of diazonium salts can be broadly divided into two categories:
\n
\t(A)\tReactions involving displacement of nitrogen, and
\n
\t(B)\tReactions involving retention of diazo group.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "33", "original_raw_text": " State the types of chemical reaction of diazonium salts. ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 34, "question_text": "
Explain the displacement equation of diazonium group of benzene diazonium salt by iodide ion and chloride ion.
", "answer_text": "
Replacement by iodide ion: Iodine is not easily introduced into the benzene ring directly, but when the diazonium salt solution is treated with potassium iodide, iodo benzene is formed.
\n
\tAr\"\"2C\"\" + KI → ArI + KCl + N2
\n
Replacement by fluoride ion: When arenediazonium chloride is treated with fluoroboric acid, arene diazonium fluoroborate is precipitated which on heating decomposes to yield aryl fluroide.
\n
Ar\"\"2C\"\" + HBF4 → Ar-\"\"2B\"\"4 \"\" Ar-F + BF3 + N2
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/EQ-0728-141224.png", "position": "answer", "context": "Ar 2 C + KI → ArI + KCl + N 2" }, { "id": "img-1", "path": "Chapter9/EQ-0728-141304.png", "position": "answer", "context": "Ar 2 C + KI → ArI + KCl + N 2" }, { "id": "img-2", "path": "Chapter9/EQ-0728-141224.png", "position": "answer", "context": "Ar 2 C + HBF 4 → Ar- 2 B 4 Ar-F + BF 3 + N 2" }, { "id": "img-3", "path": "Chapter9/EQ-0728-141304.png", "position": "answer", "context": "Ar 2 C + HBF 4 → Ar- 2 B 4 Ar-F + BF 3 + N 2" }, { "id": "img-4", "path": "Chapter9/EQ-0728-141224.png", "position": "answer", "context": "Ar 2 C + HBF 4 → Ar- 2 B 4 Ar-F + BF 3 + N 2" }, { "id": "img-5", "path": "Chapter9/EQ-0728-141524.png", "position": "answer", "context": "Ar 2 C + HBF 4 → Ar- 2 B 4 Ar-F + BF 3 + N 2" }, { "id": "img-6", "path": "Chapter9/120.png", "position": "answer", "context": "Ar 2 C + HBF 4 → Ar- 2 B 4 Ar-F + BF 3 + N 2" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "34", "original_raw_text": " Explain the displacement equation of diazonium group of benzene diazonium salt by iodide ion and chloride ion.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 35, "question_text": "
Explain the displacement of diazonium group of benzene diazonium salt by hydrogen with equation. OR
\n
\tExplain the reduction process of benzene diazonium salt by giving an equation.
", "answer_text": "
Certain mild reducing agents like hypophosphorous acid (phosphinic acid) or ethanol reduce diazonium salts to arenes and themselves get oxidised to phosphorous acid and ethanol, respectively.
\n
Ar\"\"2C\"\" + H3PO2 + H2O → ArH + N2 + H3PO3 + HCl
\n
Ar\"\"2C\"\" + CH3CH2OH → ArH + N2 + CH3CHO + HCl
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/EQ-0728-1412241.png", "position": "answer", "context": "Ar 2 C + H 3 PO 2 + H 2 O → ArH + N 2 + H 3 PO 3 + HCl" }, { "id": "img-1", "path": "Chapter9/EQ-0728-141304.png", "position": "answer", "context": "Ar 2 C + H 3 PO 2 + H 2 O → ArH + N 2 + H 3 PO 3 + HCl" }, { "id": "img-2", "path": "Chapter9/EQ-0728-1412242.png", "position": "answer", "context": "Ar 2 C + CH 3 CH 2 OH → ArH + N 2 + CH 3 CHO + HCl" }, { "id": "img-3", "path": "Chapter9/EQ-0728-141304.png", "position": "answer", "context": "Ar 2 C + CH 3 CH 2 OH → ArH + N 2 + CH 3 CHO + HCl" } ], "tables": [], "metadata": { "source_class": "Quest", "source_number": "35", "marks": 2, "original_raw_text": " Explain the displacement of diazonium group of benzene diazonium salt by hydrogen with equation. OR\n\tExplain the reduction process of benzene diazonium salt by giving an equation. ", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 36, "question_text": "
Explain the displacement of diazonium group of benzene diazonium salt by halide or cyanide ion with equation. OR
\n
\tShort note on: Sandmeyer reaction and Gattermann reaction.
", "answer_text": "
Replacement by halide or cyanide ion:
\n
The Cl–, Br– and CN– nucleophiles can easily be introduced in benzene ring in the presence of Cu(I) ion.
\n
This reaction is called Sandmeyer reaction.
\n
\"\"
\n
Alternatively, chlorine or bromine can also be introduced in the benzene ring by treating the diazonium salt solution with corresponding halogen acid in the presence of copper powder. This is referred as Gattermann reaction.
\n
\"\"
\n
The yield in Sandmeyer reaction is found to be better than Gattermann reaction.
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/123.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/124.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "36", "original_raw_text": " Explain the displacement of diazonium group of benzene diazonium salt by halide or cyanide ion with equation. OR\n\tShort note on: Sandmeyer reaction and Gattermann reaction.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 37, "question_text": "
Explain the displacement equation of the diazonium group of benzene diazonium salt by the hydroxyl group as well as by the nitro group.
", "answer_text": "
Replacement by hydroxyl group:
\n
If the temperature of the diazonium salt solution is allowed to rise upto 283 K, the salt gets hydrolyzed to phenol.
\n
\tAr\"\"2C\"\" + H2O → ArOH + N2 + HCl
\n
Replacement by nitrogroup: When diazonium fluroborate is heated with aqueous sodium nitrite solution in the presence of copper, the diazonium group is replaced by –NO2 group.
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/EQ-0728-141224.png", "position": "answer", "context": "Ar 2 C + H 2 O → ArOH + N 2 + HCl" }, { "id": "img-1", "path": "Chapter9/EQ-0728-141304.png", "position": "answer", "context": "Ar 2 C + H 2 O → ArOH + N 2 + HCl" }, { "id": "img-2", "path": "Chapter9/126.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "marks": 3, "source_number": "37", "original_raw_text": " Explain the displacement equation of the diazonium group of benzene diazonium salt by the hydroxyl group as well as by the nitro group.", "deduction_level": 0, "source_html": "Chapter9", "boundary_log": [ "leading-marker-stripped" ], "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 38, "question_text": "
Explain the coupling processes of benzene diazonium chloride with equation.
\n
OR
\n
\tWrite short notes on: Coupling reactions.
", "answer_text": "
The azo products obtained have an extended conjugate system having both the aromatic rings joined through the –N = N– bond.
\n
These compounds are often coloured and are used as dyes.
\n
Benzene diazonium chloride reacts with phenol in which the phenol molecule at its para position is coupled with the diazonium salt to form p-Hydroxyazo benzene.
\n
This type of reaction is known as coupling reaction. Similarly, the reaction of diazonium salt with aniline yields p-Aminoazobenzene. This is an example of electrophilic substitution reaction.
\n
\"\"
\n
\"\"
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/128.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/129.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-17", "source_number": "38", "marks": 3, "boundary_log": [ "or_alt→stem" ], "original_raw_text": " Explain the coupling processes of benzene diazonium chloride with equation. \nOR\n\tWrite short notes on: Coupling reactions. ", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 39, "question_text": "
Identify X, Y, Z from the following reactions (Write formula)
", "answer_text": "", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest", "marks": 3, "source_number": "39", "original_raw_text": "Identify X, Y, Z from the following reactions (Write formula) ", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2", "needs_review": true, "missing_answer": true } }, { "sequence_no": 40, "question_text": "
State the importance of diazonium salts in the synthesis of aromatic compounds.
", "answer_text": "
The diazonium salts are very good intermediates for the introduction of –F, –Cl, –Br, –I, –CN,
–OH, –NO2 groups into the aromatic ring.
\n
Aryl fluorides and iodides can not be prepared by direct halogenation. The cyano group can not be introduced by nucleophilic substitution of chlorine in chlorobenzene but cyanobenzene can be easily obtained from diazonium salt.
\n
Thus, the replacement of diazo group by other groups is helpful in preparing those substituted aromatic compounds which can not be prepared by direct substitution in benzene or substituted benzene.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "marks": 2, "source_number": "40", "original_raw_text": " State the importance of diazonium salts in the synthesis of aromatic compounds.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2" } }, { "sequence_no": 41, "question_text": "
Give the structures of A and B in the following reactions.
", "answer_text": "
(i) CH3CH2Br \"\" A \"\" B (ii) C6H5NO2 \"\" A \"\" B
\n
Ans.\t(i) CH3CH2Br \"\" CH3CH2CN \"\" CH3CH2CHO
\n
\t\t Bromo ethane\tPropane nitrile\tPropanal
\n
\t(ii) C6H5NO2 \"\" C6H5NH2 \"\" \"\"
\n
\t\tNitrobenzene\tAniline\tN - Phenylethanamide
\n
Class 12 Chemistry (Part 2) 016
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/EQ-0222-145649.png", "position": "answer", "context": "(i) CH 3 CH 2 Br A B (ii) C 6 H 5 NO 2 A …" }, { "id": "img-1", "path": "Chapter9/EQ-0222-145708.png", "position": "answer", "context": "(i) CH 3 CH 2 Br A B (ii) C 6 H 5 NO 2 A …" }, { "id": "img-2", "path": "Chapter9/EQ-0222-145719.png", "position": "answer", "context": "(i) CH 3 CH 2 Br A B (ii) C 6 H 5 NO 2 A …" }, { "id": "img-3", "path": "Chapter9/EQ-0222-145727.png", "position": "answer", "context": "(i) CH 3 CH 2 Br A B (ii) C 6 H 5 NO 2 A …" }, { "id": "img-4", "path": "Chapter9/9_2_Std._12_Sci_EM_CHEMISTRY_Chapter_9_Que_&_Ans_Anis-0228-002.png", "position": "answer", "context": "Ans. (i) CH 3 CH 2 Br CH 3 CH 2 CN CH 3 CH 2 CHO" }, { "id": "img-5", "path": "Chapter9/9_2_Std._12_Sci_EM_CHEMISTRY_Chapter_9_Que_&_Ans_Anis-0228-001.png", "position": "answer", "context": "Ans. (i) CH 3 CH 2 Br CH 3 CH 2 CN CH 3 CH 2 CHO" }, { "id": "img-6", "path": "Chapter9/9_2_Std._12_Sci_EM_CHEMISTRY_Chapter_9_Que_&_Ans_Anis-0228-003.png", "position": "answer", "context": "(ii) C 6 H 5 NO 2 C 6 H 5 NH 2" }, { "id": "img-7", "path": "Chapter9/9_2_Std._12_Sci_EM_CHEMISTRY_Chapter_9_Que_&_Ans_Anis-0228-004.png", "position": "answer", "context": "(ii) C 6 H 5 NO 2 C 6 H 5 NH 2" }, { "id": "img-8", "path": "Chapter9/137.png", "position": "answer", "context": "(ii) C 6 H 5 NO 2 C 6 H 5 NH 2" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-10", "marks": 4, "source_number": "41", "original_raw_text": " Give the structures of A and B in the following reactions.", "deduction_level": 0, "source_html": "Chapter9", "section": "Topic-wise Q & A", "section_id": "4.2", "needs_review": true, "needs_boundary_review": true, "boundary_review_reason": "answer has 1 content line(s) before its answer marker ('Ans. (i) CH 3 CH 2 Br CH 3 CH ') — pre-marker content belongs to the question" } } ] }, { "section_id": "", "section_title": "NCERT Intext Questions and Answers", "heading_text": "NCERT Intext Questions and Answers", "detected_type": "SUB", "match_confidence": 0.542, "questions": [ { "sequence_no": 42, "question_text": "
Classify the following amines as primary, secondary or tertiary:
\n
(i) \"\"
\n
(ii) \"\"
\n
(iii)\t(C2H5)2CHNH2\t\t\t
\n
(iv)\t(C2H5)2NH
", "answer_text": "
(i) \"\" primary (1°)
\n
\t(ii) \"\" tertiary (3°)
\n
\t(iii)\t(C2H5)2CHNH2\tprimary (1°)
\n
(iv)\t(C2H5)2NH secondary (2°)
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/139.png", "position": "stem", "context": "(i)" }, { "id": "img-1", "path": "Chapter9/140.png", "position": "stem", "context": "(ii)" }, { "id": "img-2", "path": "Chapter9/142.png", "position": "answer", "context": "Ans. (i) primary (1 ° )" }, { "id": "img-3", "path": "Chapter9/143.png", "position": "answer", "context": "(ii) tertiary (3 ° )" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-22", "source_number": "1", "original_raw_text": " Classify the following amines as primary, secondary or tertiary:\n (i) \n (ii) \n (iii)\t(C2H5)2CHNH2\t\t\t\n (iv)\t(C2H5)2NH", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Intext Questions and Answers", "section_id": "" } }, { "sequence_no": 43, "question_text": "
(i)\tWrite structures of different isomeric amines corresponding to the molecular formula, C4H11N.
\n
(ii)\tWrite IUPAC names of all the isomers.
\n
\t(iii)\tWhat type of isomerism is exhibited by different pairs of amines?
", "answer_text": "
There are total 8 isomeric amines forming which have molecular formula C4H11N.
\n
\t(i)\t\"\"
\n
\t(ii)\t\"\"
\n
\t(iii)\t\"\"
\n
\t(iv)\t\"\"
\n
\t(v)\t\"\"
\n
\t(vi)\t\"\"
\n
\t(vii)\t\"\"
\n
\t(viii) \"\"
\n
Isomerism exhibited by pairs of different amine compounds:
\n
Chain Isomerism:
\n
(i) and (ii);\t(iii) and (iv);
\n
\t(i) and (iv)\t(i) and (iii)
\n
Position Isomerism:
\n
\t(i) and (iii);\t(ii) and (iv)
\n
Metamers:
\n
(v) and (vi);\t(vii) and (v)
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/145.png", "position": "answer", "context": "(i)" }, { "id": "img-1", "path": "Chapter9/146.png", "position": "answer", "context": "(ii)" }, { "id": "img-2", "path": "Chapter9/147.png", "position": "answer", "context": "(iii)" }, { "id": "img-3", "path": "Chapter9/148.png", "position": "answer", "context": "(iv)" }, { "id": "img-4", "path": "Chapter9/149.png", "position": "answer", "context": "(v)" }, { "id": "img-5", "path": "Chapter9/150.png", "position": "answer", "context": "(vi)" }, { "id": "img-6", "path": "Chapter9/151.png", "position": "answer", "context": "(vii)" }, { "id": "img-7", "path": "Chapter9/152.png", "position": "answer", "context": "(viii)" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-22", "source_number": "2", "original_raw_text": " (i)\tWrite structures of different isomeric amines corresponding to the molecular formula, C4H11N.\n (ii)\tWrite IUPAC names of all the isomers.\n\t(iii)\tWhat type of isomerism is exhibited by different pairs of amines? ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Intext Questions and Answers", "section_id": "" } }, { "sequence_no": 44, "question_text": "
Classify the following amines as primary, secondary or tertiary:
\n
(i)\tBenzene into aniline\t\t\t
\n
\t(ii)\tBenzene into N, N-dimethylaniline
\n
\t(iii)\tCl – (CH2)4 – Cl into hexan-1, 6-Diamine?\t\t
", "answer_text": "
(i)\t\"\"
\n
(ii)\t\"\"
\n
(iii)\t\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/154.png", "position": "answer", "context": "(i)" }, { "id": "img-1", "path": "Chapter9/155.png", "position": "answer", "context": "(ii)" }, { "id": "img-2", "path": "Chapter9/156.png", "position": "answer", "context": "(iii)" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "3", "original_raw_text": " Classify the following amines as primary, secondary or tertiary:\n (i)\tBenzene into aniline\t\t\t\n\t(ii)\tBenzene into N, N-dimethylaniline\n\t(iii)\tCl – (CH2)4 – Cl into hexan-1, 6-Diamine?\t\t", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Intext Questions and Answers", "section_id": "" } }, { "sequence_no": 45, "question_text": "
Arrange the following in increasing order of their basic strength:
\n
(i)\tC2H5NH2, C6H5NH2, NH3, C6H5CH2NH2 and (C2H5)2 NH
\n
(ii)\tC2H5NH2, (C2H5)2NH, (C2H5)3N, C6H5NH2
\n
(iii)\tCH3NH2, (CH3)2NH, (CH3)3N, C6H5NH2, C6H5CH2NH2
", "answer_text": "
(i)\tC6H5NH2 < NH3 < C6H5CH2NH2 < C2H5NH2 < (C2H5)2NH
\n
(ii)\tC6H5NH2 < C2H5NH2 < (C2H5)3N < (C2H5)2NH
\n
(iii)\tC6H5NH2 < C6H5CH2NH2 < (CH3)3N < CH3NH2 < (CH3)2NH
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "4", "original_raw_text": " Arrange the following in increasing order of their basic strength: \n (i)\tC2H5NH2, C6H5NH2, NH3, C6H5CH2NH2 and (C2H5)2 NH\n (ii)\tC2H5NH2, (C2H5)2NH, (C2H5)3N, C6H5NH2\n (iii)\tCH3NH2, (CH3)2NH, (CH3)3N, C6H5NH2, C6H5CH2NH2", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Intext Questions and Answers", "section_id": "" } }, { "sequence_no": 46, "question_text": "
Complete the following acid base reactions and name the products:
\n
(i) CH3CH2CH2NH2+HCl→
\n
\t(ii) (C2H5)3N + HCl →
", "answer_text": "
(i)\t
\n
(ii)\t\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/160.png", "position": "answer", "context": "(ii)" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-22", "source_number": "5", "original_raw_text": " Complete the following acid base reactions and name the products:\n (i) CH3CH2CH2NH2+HCl→ \n\t(ii) (C2H5)3N + HCl → ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Intext Questions and Answers", "section_id": "" } }, { "sequence_no": 47, "question_text": "
Write reactions of the final alkylation product of aniline with excess of methyl iodide in the presence of sodium carbonate solution.
", "answer_text": "
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/162.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-22", "source_number": "6", "original_raw_text": " Write reactions of the final alkylation product of aniline with excess of methyl iodide in the presence of sodium carbonate solution. ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Intext Questions and Answers", "section_id": "" } }, { "sequence_no": 48, "question_text": "
Write chemical reaction of aniline with benzoyl chloride and write the name of the product obtained.
", "answer_text": "
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/164.png", "position": "answer", "context": "Ans." } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "7", "original_raw_text": " Write chemical reaction of aniline with benzoyl chloride and write the name of the product obtained.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "boundary_log": [ "leading-marker-stripped" ], "section": "NCERT Intext Questions and Answers", "section_id": "" } }, { "sequence_no": 49, "question_text": "
Write structures of different isomers corresponding to the molecular formula, C3H9N. Write IUPAC names of the isomers which will liberate nitrogen gas on treatment with nitrous acid.
", "answer_text": "
Total 4 structures of different isomers corresponding to the molecular formula C3H9N given below.
\n
Primary (1°):
\n
\"\"
\n
Secondary (2°):
\n
\"\"
\n
Tertiary (3°):
\n
\"\"
\n
Only primary amine compounds will react with nitrous acid and liberate nitrogen gas, their IUPAC names are Propan-1-amine, Propan-2-amine
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/166.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/167.png", "position": "answer", "context": "" }, { "id": "img-2", "path": "Chapter9/168.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "8", "original_raw_text": " Write structures of different isomers corresponding to the molecular formula, C3H9N. Write IUPAC names of the isomers which will liberate nitrogen gas on treatment with nitrous acid.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Intext Questions and Answers", "section_id": "" } }, { "sequence_no": 50, "question_text": "
Convert:
\n
\t(i) 3-Methylaniline into 3-nitrotoluene\t\t(ii) Aniline into 1, 3, 5 tribromo benzene.
", "answer_text": "
(i)\t\"\"
\n
\"\"
\n
\t(ii)\t\"\"
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/171.png", "position": "answer", "context": "Ans. (i)" }, { "id": "img-1", "path": "Chapter9/172.png", "position": "answer", "context": "" }, { "id": "img-2", "path": "Chapter9/173.png", "position": "answer", "context": "(ii)" }, { "id": "img-3", "path": "Chapter9/174.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-22", "source_number": "9", "original_raw_text": " Convert: \n\t(i) 3-Methylaniline into 3-nitrotoluene\t\t(ii) Aniline into 1, 3, 5 tribromo benzene.", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Intext Questions and Answers", "section_id": "" } } ] }, { "section_id": "4.5", "section_title": "NCERT Textbook Exercise Q & A", "heading_text": "NCERT Textbook Exercise Questions And Answers", "detected_type": "SUB", "match_confidence": 0.75, "questions": [ { "sequence_no": 51, "question_text": "
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
\n
\t(i) (CH3)2CHNH2\t(ii) CH3(CH2)2NH2\t(iii) CH3NHCH(CH3)2\t(iv) (CH3)3CNH2
\n
(v) C6H5NHCH3\t(vi) (CH3CH2)2NCH3\t(vii) m-BrC6H4NH2
", "answer_text": "", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [ { "id": "tbl-1", "rows": 8, "columns": 4, "raw_html": "\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
\n

S.N.

\n		\n

Structure

\n		\n

IUPAC Name

\n		\n

Types

\n
\n

(i)

\n		\n

(CH3)2CHNH2

\n		\n

Propan 2-amine

\n		\n

1°

\n
\n

(ii)

\n		\n

CH3(CH2)2NH2

\n		\n

Propan 1-amine

\n		\n

1°

\n
\n

(iii)

\n		\n

CH3NHCH(CH3)2

\n		\n

N-Methyl propan-2-amine

\n		\n

2°

\n
\n

(iv)

\n		\n

(CH3)3CNH2

\n		\n

2-Methyl propan-2-amine

\n		\n

1°

\n
\n

(v)

\n		\n

C6H5NHCH3

\n		\n

N-Methyl benzenamine

\n		\n

2°

\n
\n

(vi)

\n		\n

(CH3CH2)2NCH3

\n		\n

N-Ethyl, N-Methyl Ethanamine

\n		\n

3°

\n
\n

(vii)

\n		\n

m-BrC6H4NH2

\n		\n

3-bromo benzenamine

\n		\n

1°

\n
", "position": "answer", "context": "S.N. Structure IUPAC Name Types (i) (CH 3 ) 2 CHNH 2 Propan …" } ], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "marks": 1, "source_number": "1", "original_raw_text": " Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.\n\t(i) (CH3)2CHNH2\t(ii) CH3(CH2)2NH2\t(iii) CH3NHCH(CH3)2\t(iv) (CH3)3CNH2\n (v) C6H5NHCH3\t(vi) (CH3CH2)2NCH3\t(vii) m-BrC6H4NH2", "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 52, "question_text": "
Give one chemical test to distinguish between the following pairs of compounds.
\n
(i)\tMethylamine and dimethylamine\t\t(ii)\tSecondary and tertiary amines
\n
\t(iii)\tEthylamine and aniline\t\t(iv)\tAniline and benzylamine
\n
\t(v)\tAniline and N-methylaniline
", "answer_text": "
(i) \tMethylamine and dimethylamine: Methylamine and dimethylamine can be distinguished by carbyl amine test.
\n
\tCH3NH2 + CHCl3 + 3 KOH \"\" \"\"
\n
\t(CH3)2NH + CHCl3 + 3 KOH \"\" no reaction
\n
(ii)\tSecondary and tertiary amines: Secondary amines give Libermann nitrosoamine test while 3° amines do not give 2° amines on treatment with HNO2.
It gives yellow coloured oily N-nitroso amine.
\n
\"\"
\n
(iii)\tEthylamine and aniline: Ethylamine and aniline can be distinguished by azo dye test.
\n
\tCH3CH2NH2 + HO – N = O \"\"
CH3CH2N2+ Cl – \"\" CH3CH2OH
\n
\t\t(unstable)
\n
\tC6H5NH2 + NaNO2 + 2HCl \"\" C6H5N+2 Cl – + NaCl + 2H2O
\n
\t\t(stable)
\n
\"\"
\n
(iv)\tAniline and Benzylamine: Aniline and benzylamine can be distinguished by nitrous acid test.
\n
\tC6H5CH2NH2 \"\" C6H5CH2N2+ Cl –
\n
\"\" C6H5CH2OH
\n
\t\t\t(unstable)
\n
\tC6H5NH2 + NaNO2 + 2HCl \"\" C6H5N+2 Cl – + NaCl + 2H2O
\n
(stable)
\n
(v)\tAniline and N-methylaniline: Aniline and N-methyl aniline can be distinguished by carbyl amine test.
\n
\tC6H5NH2 + CHCl3 + 3 KOH \"\"
\n
C6H5NC + 3KCl + 3H2O
\n
\t\t\t \t\t (foul smell)
\n
\tC6H5 – NH – CH3 + CHCl3 + 3 KOH \"\" no reaction
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/177.png", "position": "answer", "context": "CH 3 NH 2 + CHCl 3 + 3 KOH" }, { "id": "img-1", "path": "Chapter9/178.png", "position": "answer", "context": "CH 3 NH 2 + CHCl 3 + 3 KOH" }, { "id": "img-2", "path": "Chapter9/177.png", "position": "answer", "context": "(CH 3 ) 2 NH + CHCl 3 + 3 KOH no reaction" }, { "id": "img-3", "path": "Chapter9/180.png", "position": "answer", "context": "" }, { "id": "img-4", "path": "Chapter9/181.png", "position": "answer", "context": "CH 3 CH 2 NH 2 + HO – N = O CH 3 CH 2 N 2 + Cl – CH 3 CH 2 O…" }, { "id": "img-5", "path": "Chapter9/182.png", "position": "answer", "context": "CH 3 CH 2 NH 2 + HO – N = O CH 3 CH 2 N 2 + Cl – CH 3 CH 2 O…" }, { "id": "img-6", "path": "Chapter9/183.png", "position": "answer", "context": "C 6 H 5 NH 2 + NaNO 2 + 2HCl C 6 H 5 N + 2 Cl – + NaCl + 2H …" }, { "id": "img-7", "path": "Chapter9/184.png", "position": "answer", "context": "" }, { "id": "img-8", "path": "Chapter9/185.png", "position": "answer", "context": "C 6 H 5 CH 2 NH 2 C 6 H 5 CH 2 N 2 + Cl –" }, { "id": "img-9", "path": "Chapter9/186.png", "position": "answer", "context": "C 6 H 5 CH 2 OH" }, { "id": "img-10", "path": "Chapter9/187.png", "position": "answer", "context": "C 6 H 5 NH 2 + NaNO 2 + 2HCl C 6 H 5 N + 2 Cl – + NaCl + 2H …" }, { "id": "img-11", "path": "Chapter9/188.png", "position": "answer", "context": "C 6 H 5 NH 2 + CHCl 3 + 3 KOH" }, { "id": "img-12", "path": "Chapter9/188.png", "position": "answer", "context": "C 6 H 5 – NH – CH 3 + CHCl 3 + 3 KOH no reaction" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-17", "source_number": "2", "original_raw_text": " Give one chemical test to distinguish between the following pairs of compounds.\n (i)\tMethylamine and dimethylamine\t\t(ii)\tSecondary and tertiary amines\n\t(iii)\tEthylamine and aniline\t\t(iv)\tAniline and benzylamine\n\t(v)\tAniline and N-methylaniline", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 53, "question_text": "
Account for the following:
\n
(i)\tpKb of aniline is more than that of methylamine.
\n
\t(ii)\tEthylamine is soluble in water, where as aniline is not.
\n
\t(iii)\tMethylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
\n
\t(iv)\tAlthough amino group is o– and p-directing in aromatic electrophilic substitution reactions, aniline m-nitro aniline.
\n
\t(v)\tAniline does not undergo friedel crafts reaction.
\n
\t(vi)\tDiazonium salts of aromatic amines are more stable than those of aliphatic amines.
\n
\t(viii)\tGabriel phthalimide synthesis is preferred for synthesising primary amines.
", "answer_text": "
(i) \tpKb of aniline is more than that of methyl amine.
\n
In aniline, the lone pair of electrons on N-atom is delocalized over the benzene ring. As a result, electron density on the nitrogen decreases. On the other hand in CH3NH2, +I effect of CH3 group increases the electron density on N-atom. Therefore, aniline is less basic than methylamine and hence, pKb of aniline is higher than that of methylamine.
\n
(ii)\tEthylamine is soluble in water where as aniline is not.
\n
Ethylamine is soluble in water due to intermolecular hydrogen bonding, where as in aniline its hydrogen bonding with water is weak due to the large hydrophobic part. So aniline is insoluble in water.
\n
(iii)\tMethyl amine in water react with ferric chloride to precipitate hydrated ferric oxide.
\n
Methylamine is more basic than water and therefore, accepts a proton from water forming OH– ions.
\n
\t(These OH – ions combine with Fe3+ ions to form brown ppt. of hydrate ferric oxide)
\n
\tFeCl3 \"\" Fe3+ + 3Cl– 2Fe3+ + 6OH –
\"\" 2Fe(OH)3 Or Fe2O3.3H2O
\n
(iv)\tAlthough amino group is o- and p-directing in aromatic electrophilic substitution reactions, aniline on nitrogen gives a substitution reactions, aniline on nitrogen gives a substantial amount of m-nitro aniline.
\n
Under strongly acidic conditions of nitration in the presence of mixture of conc. HNO3 + H2SO4, aniline. gets protonated and is converted into anilinium ion having –NH3+ group.
\n
This group is deactivating group and is m-directing.
\n
So, the nitrogen of aniline gives o, p nitro aniline (mainly p-product) while the nitration of anilinium ion gives m-nitro aniline.
\n
(v)\tAniline does not undergo Friedel crafts reaction.
\n
Aniline being a Lewis base reacts with Lewis acid such as AlCl3 to form a salt.
\n
\tC6H5NH2 + AlCl3 → C6H5NH2+ AlCl3–
\n
As a result, N of aniline acquires +ve charge and hence, it acts as a strong deactivating group for electrophilic substitution reaction.
\n
Hence, aniline does not undergo Friedel crafts reaction.
\n
(vi)\tDiazonium salts of aromatic amines are more stable than those of aliphatic amines.
\n
The diazonium salts of aromatic amines are more stable than those of aliphatic amines because of dispersal of positive charge on the benzene ring due to resonance.
\n
This type of resonance stability is not possible in alkyl diazonium salts.
\n
\"\"
\n
(vii)\tGabriel phthalimide synthesis is preferred for synthesising primary amines.
\n
Gabriel phthalimide reaction gives pure 1° amines without any impurity of 2° or 3° amines.
\n
Therefore, it is preferred for the synthesis of
1° amines.
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/192.png", "position": "answer", "context": "FeCl 3 Fe 3+ + 3Cl – 2Fe 3+ + 6OH – 2Fe(OH) 3 Or Fe 2 O 3 .3…" }, { "id": "img-1", "path": "Chapter9/193.png", "position": "answer", "context": "FeCl 3 Fe 3+ + 3Cl – 2Fe 3+ + 6OH – 2Fe(OH) 3 Or Fe 2 O 3 .3…" }, { "id": "img-2", "path": "Chapter9/195.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-17", "source_number": "3", "original_raw_text": " Account for the following:\n (i)\tpKb of aniline is more than that of methylamine.\n\t(ii)\tEthylamine is soluble in water, where as aniline is not.\n\t(iii)\tMethylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.\n\t(iv)\tAlthough amino group is o– and p-directing in aromatic electrophilic substitution reactions, aniline m-nitro aniline.\n\t(v)\tAniline does not undergo friedel crafts reaction.\n\t(vi)\tDiazonium salts of aromatic amines are more stable than those of aliphatic amines.\n\t(viii)\tGabriel phthalimide synthesis is preferred for synthesising primary amines. ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "boundary_log": [ "leading-marker-stripped" ], "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 54, "question_text": "
Arrange the following:
\n
\t(i)\tIn decreasing order of the pKb values:
\n
C2H5NH2, C6H5NHCH3, (C2H5)2NH and C6H5NH2
\n
\t(ii)\tIn increasing order of basic strength:
\n
C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2
\n
\t(iii)\tIn increasing order of basic strength:
\n
(a) Aniline, p-nitroaniline and p-toluidine\t
\n
(b) C6H5NH2, C6H5NHCH3, C6H5CH2NH2
\n
\t(iv)\tIn decreasing order of basic strength in gas phase:
\n
C2H5NH2, (C2H5)2NH, (C2H5)3N and NH3
\n
\t(v)\tIn increasing order of boiling point:
\n
C2H5OH, (CH3)2NH, C2H5NH2
\n
\t(vi)\tIn increasing order of solubility in water:
\n
C6H5NH2, (C2H5)2NH, C2H5NH2
", "answer_text": "
(i)\tIn C6H5NH2 only one –C2H5 group is present while in (C2H5)2NH, two –C2H5 groups are present. Thus, the + I effect is more in
(C2H5)2NH than in C2H5NH2. Therefore, the electron density over the N-atom is more in (C2H5)2NH than in C2H5NH2. Hence, (C2H5)2NH is more basic than C2H5NH2. Also, both C6H5NHCH3 and C6H5NH2 are less basic than (C2H5)2NH and C2H5NH2 due to the delocalization of the lone pair in the former two. Further among C6H5NHCH3 and C6H5NH2, the former will be more basic due to +I effect of –CH3 group. Hence the order of increasing basicity of the given compounds is as follows:
\n
\tC6H5NH2 < C6H5NHCH3 < C2H5NH2 < (C2H5)2NH we know that the higher the basic strength, the lower is the pkb values.
\n
\tC6H5NH2 > C6H5NHCH3 > C2H5NH2 > (C2H5)2NH
\n
(ii)\tC6H5N (CH3)2 is more basic than C6H5 NH2 due to the presence of the +I effect of two
–CH3 groups in C6H5N(CH3)2. Further, CH3NH2 contains one –CH3 group while (C2H5)2NH contains two –C2H5 groups. Thus (C2H5)2NH is more basic than CH3NH2. Now C6H5N(CH3)2 is less basic than CH3 NH2 because of the –R effect of –C6H5 group. Hence the increasing order of the basic strengths of the given compounds is as follows:
\n
C6H5 NH2 < C6H5 N (CH3)2 < CH3 NH2 < (C2H5)2 NH
\n
(iii)
\n
(a) In p-toluidine, the presence of electron donating –CH3 group increases the electron density on the N atom. Thus, p-toluidine is more basic than aniline. On the other hand, the presence of electron withdrawing –NO2 group decreases the electron density over the N-atom in p-nitro aniline. Thus, p-nitroaniline is less basic than aniline. Hence, the increasing order of the basic strengths of the given compounds is as follows:
\n
p-nitroaniline < aniline < p-toluidine
\n
(b) \tC6H5NHCH3 is more basic than C6H5NH2 due to the presence of electron donating –CH3 group in C6H5NHCH3. Again in C6H5 NHCH3 the –R effect of –C6H5 group decreases the electron density over the N-atom. Therefore; C6H5CH2NH2 is more basic than C6H5NHCH3. Hence, the increasing order of the basic strengths of the given compounds is as follows:
\n
\t\tC6H5NH2 < C6H5NHCH3 < C6H5CH2NH2.
\n
(iv)\tIn the gas phase, there is no solvation effect. As a result, the basic strength mainly depends upon the +I effect. The higher the +I effect, the stronger is the base. Also the greater the number of Alkyl groups, the higher is the +I effect. So, the given compounds can be arranged in the decreasing order of their basic strengths in the gas phase as follows:
\n
\t(C2H5)3N > (C2H5)2 NH > C2H5NH2 > NH3
\n
(v)\tThe boiling points of compounds depend on the extent of H bonding present in that compound. The more extensive the H–bonding in the compound, the higher is the boiling point. (CH3)2NH contains only one H-atom where as C2H5NH2 contains two H-atoms. Then C2H5NH2 undergoes more extensive H-bonding than (CH3)2 NH. Hence the boiling point of C2H5NH2 is higher than that of (CH3)2 NH. Further O is more electronegative than N. Thus C2H5OH forms stronger H-bonds than C2H5NH2. As a result, the boiling point of C2H5OH is higher than that of C2H5NH2 and (CH3)2NH. Increasing order of boiling point:
\n
\t(CH3)2NH < C2H5NH2 < C2H5OH
\n
(vi)\tThe solubility of amines decreases with increase in the molecular mass. This is because the molecular mass of amines increases with an increase in size of the hydrophobic part. The molecular mass of C6H5NH2 is greater than that of C2H5NH2 and (C2H5)2NH. Hence the increasing order of their solubility in water is as follows:
\n
C6H5NH2 < (C2H5)2NH < C2H5NH2
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-89", "source_number": "4", "original_raw_text": " Arrange the following:\n\t(i)\tIn decreasing order of the pKb values:\n C2H5NH2, C6H5NHCH3, (C2H5)2NH and C6H5NH2\n\t(ii)\tIn increasing order of basic strength:\n C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2\n\t(iii)\tIn increasing order of basic strength:\n (a) Aniline, p-nitroaniline and p-toluidine\t\n (b) C6H5NH2, C6H5NHCH3, C6H5CH2NH2\n\t(iv)\tIn decreasing order of basic strength in gas phase:\n C2H5NH2, (C2H5)2NH, (C2H5)3N and NH3\n\t(v)\tIn increasing order of boiling point:\n C2H5OH, (CH3)2NH, C2H5NH2\n\t(vi)\tIn increasing order of solubility in water:\n C6H5NH2, (C2H5)2NH, C2H5NH2", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 55, "question_text": "
How will you convert:
\n
(i)\tEthanoic acid into methanamine\t\t(ii)\tHexane nitrile into 1-amino pentane
\n
\t(iii)\tMethanol to ethanoic acid\t\t(iv)\tEthanamine into methanamine
\n
\t(v)\tEthanoic acid into propanoic acid\t\t(vi)\tMethanamine into ethanamine
\n
\t(vii)\tNitro methane into dimethylamine\t\t(viii)\tPropanoic acid into ethanoic acid?
", "answer_text": "
(i)\tEthanoic acid into methanamine
\n
\tCH3COOH \"\" CH3COCl \"\" CH3CONH2 \"\" CH3NH2
\n
Ethanoic acid Ethanoyl Chloride Ethanamide Methanamine
\n
(ii)\tHexane nitrile into 1-amino pentane
\n
(iii)\tMethanol to ethanoic acid
\n
CH3OH \"\" CH3Cl \"\" CH3CN \"\" CH3COOH
\n
Methanol Chloromethane Ethane nitrile Ethanoic Acid
\n
(iv)\tEthanamine into methanamine
\n
\"\"
\n
(v)\tEthanoic acid into propanoic acid
\n
\"\"
\n
(vi)\tMethanamine into ethanamine
\n
\"\"
\n
(vii)\tNitro methane into dimethylamine
\n
CH3NO2 \"\" CH3NH2 \"\" CH3NC \"\" CH3NHCH3
\n
Nitromethane Methanamine \tMethyl Dimethyl amine
\n
\t\t \tIsocyanide
\n
(viii)\tPropanoic acid into ethanoic acid
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/EQ-0728-164740.png", "position": "answer", "context": "CH 3 COOH CH 3 COCl CH 3 CONH 2 CH 3 NH 2" }, { "id": "img-1", "path": "Chapter9/201.png", "position": "answer", "context": "CH 3 COOH CH 3 COCl CH 3 CONH 2 CH 3 NH 2" }, { "id": "img-2", "path": "Chapter9/EQ-0214-172006.png", "position": "answer", "context": "CH 3 COOH CH 3 COCl CH 3 CONH 2 CH 3 NH 2" }, { "id": "img-3", "path": "Chapter9/EQ-0728-165603.png", "position": "answer", "context": "CH 3 OH CH 3 Cl CH 3 CN CH 3 COOH" }, { "id": "img-4", "path": "Chapter9/EQ-0728-165638.png", "position": "answer", "context": "CH 3 OH CH 3 Cl CH 3 CN CH 3 COOH" }, { "id": "img-5", "path": "Chapter9/EQ-0728-165704.png", "position": "answer", "context": "CH 3 OH CH 3 Cl CH 3 CN CH 3 COOH" }, { "id": "img-6", "path": "Chapter9/203.png", "position": "answer", "context": "" }, { "id": "img-7", "path": "Chapter9/204.png", "position": "answer", "context": "" }, { "id": "img-8", "path": "Chapter9/205.png", "position": "answer", "context": "" }, { "id": "img-9", "path": "Chapter9/EQ-0214-172434.png", "position": "answer", "context": "CH 3 NO 2 CH 3 NH 2 CH 3 NC CH 3 NHCH 3" }, { "id": "img-10", "path": "Chapter9/EQ-0728-172302.png", "position": "answer", "context": "CH 3 NO 2 CH 3 NH 2 CH 3 NC CH 3 NHCH 3" }, { "id": "img-11", "path": "Chapter9/EQ-0728-172331.png", "position": "answer", "context": "CH 3 NO 2 CH 3 NH 2 CH 3 NC CH 3 NHCH 3" }, { "id": "img-12", "path": "Chapter9/206.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-86", "source_number": "5", "original_raw_text": " How will you convert: \n (i)\tEthanoic acid into methanamine\t\t(ii)\tHexane nitrile into 1-amino pentane\n\t(iii)\tMethanol to ethanoic acid\t\t(iv)\tEthanamine into methanamine\n\t(v)\tEthanoic acid into propanoic acid\t\t(vi)\tMethanamine into ethanamine\n\t(vii)\tNitro methane into dimethylamine\t\t(viii)\tPropanoic acid into ethanoic acid?", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "boundary_log": [ "leading-marker-stripped" ], "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 56, "question_text": "
Describe a method for the identification of primary, secondary, and tertiary amines. Also write chemical equations of the reactions involved.
\n
OR
\n
Write a note on the reaction of amine compounds with aryl sulphonyl chloride and explain the usefulness of this process.
\n
OR
\n
Explain with equation how primary, secondary, and tertiary amine compounds can be separated using Hinsberg's reagent.
", "answer_text": "
Benzenesulphonyl chloride (C6H5SO2Cl) which is also known as Hinsberg's reagent, reacts with primary and secondary amines to form sulphonamides.
\n
(a) \tThe reaction of benzene sulphonylchloride with primary amine yields N-ethyl benzenesulphonamide.
\n
The hydrogen attached to nitrogen in sulphonamide is strongly acidic due to the presence of strong electron withdrawing sulphonyl group. Hence it is soluble in alkali.
\n
(b)\tIn the reaction with secondary amine, N, N-diethyl benzene sulphonamide is formed.
\n
Since, N, N-diethylbenzene sulphonamide does not contain any hydrogen atom attached to nitrogen atom, it is not acidic and hence, it insoluble in alkali.
\n
(c)\tTertiary amines do not react with benzenesulphonyl chloride. This property of amines reacting with benzenesulphonyl chloride in a different manner is used for the distinction of primary, secondary, and tertiary amines and also for the separation of a mixture of amines. However these days benzenesulphonyl chloride is replaced by p-toluenesulphonyl chloride. (PTS)
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-56", "source_number": "6", "marks": 3, "boundary_log": [ "or_alt→stem" ], "original_raw_text": " Describe a method for the identification of primary, secondary, and tertiary amines. Also write chemical equations of the reactions involved.\n OR\n Write a note on the reaction of amine compounds with aryl sulphonyl chloride and explain the usefulness of this process. \n OR\n Explain with equation how primary, secondary, and tertiary amine compounds can be separated using Hinsberg's reagent.", "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 57, "question_text": "
Write short notes on the following:
\n
\t(i) Carbylamine reaction
\n
\t(ii) Diazotisation
\n
\t(iii) Hofmann’s bromamide reaction
\n
\t(iv) Coupling reaction
\n
\t(v) Ammonolysis
\n
\t(vi) Acetylation
\n
\t(vii) Gabriel phthalimide synthesis.
", "answer_text": "
(i) Refer Que. no.\t23\tPage no.\t248
\n
(ii)\tRefer Que. no.\t31\tPage no.\t251
\n
(iii)\tRefer Que. no.\t11\tPage no.\t244
\n
(iv)\tRefer Que. no.\t38\tPage no.\t252
\n
(v)\tRefer Que. no.\t7\tPage no.\t242
\n
(vi)\tRefer Que. no.\t21\tPage no.\t247
\n
(vii)\tRefer Que. no.\t10\tPage no.\t244
", "type": "SN", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-17", "source_number": "7", "marks": 3, "original_raw_text": " Write short notes on the following:\n\t(i) Carbylamine reaction \n\t(ii) Diazotisation\n\t(iii) Hofmann’s bromamide reaction\n\t(iv) Coupling reaction\n\t(v) Ammonolysis\n\t(vi) Acetylation\n\t(vii) Gabriel phthalimide synthesis.", "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 58, "question_text": "
Accomplish the following conversions:
\n
(i)\tNitrobenzene to benzoic acid
\n
\t(ii)\tBenzene to m-bromophenol
\n
\t(iii)\tBenzoic acid to aniline
\n
\t(iv)\tAniline to 2, 4, 6-tribromofluorobenzene
\n
\t(v)\tBenzyl chloride to 2-phenyl ethanamine
\n
\t(vi)\tChlorobenzene to p-chloro aniline
\n
\t\t(vii)\tAniline to p-bromoaniline\t
\n
\t(viii)\tBenzamide to toluene
\n
\t(ix)\tAniline to benzyl alcohol
", "answer_text": "
(i)\tNitrobenzene to benzoic acid
\n
\"\"
\n
(ii)\tBenzene to m-bromophenol
\n
\"\"
\n
(iii)\tBenzoic acid to aniline
\n
(iv)\tAniline to 2, 4, 6-tribromofluro benzene
\n
\"\"
\n
(v)\tBenzyl chloride to 2-phenyl ethanamine
\n
(vi)\tChloro benzene to p-chloro aniline
\n
\"\"
\n
(vii)\tAniline to p-bromo aniline
\n
\"\"
\n
(viii)\tBenzamide to toluene
\n
(ix)\tAniline to benzyl alcohol
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/220.png", "position": "answer", "context": "" }, { "id": "img-1", "path": "Chapter9/221.png", "position": "answer", "context": "" }, { "id": "img-2", "path": "Chapter9/223.png", "position": "answer", "context": "" }, { "id": "img-3", "path": "Chapter9/225.png", "position": "answer", "context": "" }, { "id": "img-4", "path": "Chapter9/227.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-89", "source_number": "8", "original_raw_text": " Accomplish the following conversions: \n (i)\tNitrobenzene to benzoic acid\n\t(ii)\tBenzene to m-bromophenol\n\t(iii)\tBenzoic acid to aniline\n\t(iv)\tAniline to 2, 4, 6-tribromofluorobenzene\n\t(v)\tBenzyl chloride to 2-phenyl ethanamine\n\t(vi)\tChlorobenzene to p-chloro aniline\n\t\t(vii)\tAniline to p-bromoaniline\t\n\t(viii)\tBenzamide to toluene\n\t(ix)\tAniline to benzyl alcohol", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "boundary_log": [ "leading-marker-stripped" ], "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 59, "question_text": "
Give the structures of A, B and C in the following reactions:
\n
(i) CH3CH2I \"\" A \"\" B
\n
\"\" C
\n
(ii) C6H5N2Cl \"\" A B
\n
\"\" C
\n
(iii) CH3CH2Br \"\" A \"\" B
\n
\"\" C
\n
(iv) C6H5NO2 \"\" A \"\" B
\n
C
\n
(v) CH3COOH \"\" A \"\" B
\n
\"\" C
\n
(vi) C6H5NO2 \"\" A \"\" B
\n
\"\" C\t
", "answer_text": "
(i) A = CH3CH2CN, B = CH3CH2 – \"\" – NH2 and C = CH3CH2 – NH2.
\n
(ii)\tA = C6H5CN, B = C6H5COOH and
C = C6H5CONH2.
\n
(iii)\tA = CH3CH2CN, B = CH3CH2CH2NH2 and
C = CH3CH2CH2OH.
\n
(iv)\tA = C6H5NH2, B = C6H5N+=NCl – and
C = C6H5OH.
\n
(v)\tA = CH3CONH2, B = CH3NH2 and C = CH3OH.
\n
(vi)\tA = C6H5NH2, B = C6H5N+=NCl – and
\n
\tC =
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/230.png", "position": "stem", "context": "(i) CH 3 CH 2 I A B" }, { "id": "img-1", "path": "Chapter9/231.png", "position": "stem", "context": "(i) CH 3 CH 2 I A B" }, { "id": "img-2", "path": "Chapter9/232.png", "position": "stem", "context": "C" }, { "id": "img-3", "path": "Chapter9/233.png", "position": "stem", "context": "(ii) C 6 H 5 N 2 Cl A B" }, { "id": "img-4", "path": "Chapter9/235.png", "position": "stem", "context": "C" }, { "id": "img-5", "path": "Chapter9/236.png", "position": "stem", "context": "(iii) CH 3 CH 2 Br A B" }, { "id": "img-6", "path": "Chapter9/237.png", "position": "stem", "context": "(iii) CH 3 CH 2 Br A B" }, { "id": "img-7", "path": "Chapter9/238.png", "position": "stem", "context": "C" }, { "id": "img-8", "path": "Chapter9/239.png", "position": "stem", "context": "(iv) C 6 H 5 NO 2 A B" }, { "id": "img-9", "path": "Chapter9/240.png", "position": "stem", "context": "(iv) C 6 H 5 NO 2 A B" }, { "id": "img-10", "path": "Chapter9/242.png", "position": "stem", "context": "(v) CH 3 COOH A B" }, { "id": "img-11", "path": "Chapter9/243.png", "position": "stem", "context": "(v) CH 3 COOH A B" }, { "id": "img-12", "path": "Chapter9/244.png", "position": "stem", "context": "C" }, { "id": "img-13", "path": "Chapter9/245.png", "position": "stem", "context": "(vi) C 6 H 5 NO 2 A B" }, { "id": "img-14", "path": "Chapter9/246.png", "position": "stem", "context": "(vi) C 6 H 5 NO 2 A B" }, { "id": "img-15", "path": "Chapter9/247.png", "position": "stem", "context": "C" }, { "id": "img-16", "path": "Chapter9/249.png", "position": "answer", "context": "(i) A = CH 3 CH 2 CN, B = CH 3 CH 2 – – NH 2 and C = CH 3 CH…" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-89", "source_number": "9", "original_raw_text": " Give the structures of A, B and C in the following reactions: \n(i) CH3CH2I A B\n C\n(ii) C6H5N2Cl A B\n C\n(iii) CH3CH2Br A B\n C\n(iv) C6H5NO2 A B\n C\n(v) CH3COOH A B\n C\n(vi) C6H5NO2 A B\n C\t", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 60, "question_text": "
An aromatic compound 'A' on treatment with aqueous ammonia and heating forms compound 'B' which on heating with Br2 and KOH forms a compound 'C' of molecular formula C6H7N. Write the structures and IUPAC names of compounds A, B, C.
", "answer_text": "
Since the compound 'C' of molecular formula C6H7N formed from 'B' on treatment with Br2 and KOH, therefore the compound 'B' must be an amide and 'C' must be amine. The only aromatic amine having molecular formula is C6H5NH2 (Aniline). Thus, B is benzamine.
\n
Since 'B' is formed from 'A' with aqueous ammonia and heating, therefore compound 'A' must be benzoic acid.
\n
Compound A, B, C their structure and IUPAC names are as follows:
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/252.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "10", "original_raw_text": " An aromatic compound 'A' on treatment with aqueous ammonia and heating forms compound 'B' which on heating with Br2 and KOH forms a compound 'C' of molecular formula C6H7N. Write the structures and IUPAC names of compounds A, B, C. ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 61, "question_text": "
Complete the following reactions:
\n
\t(i) C6H5NH2 + CHCl3 + Alcoholic KOH →
\n
(ii)\tC6H5N2Cl + H3PO2 + H2O →
\n
(iii) C6H5NH2 + H2SO4 (Concentrated) →
\n
(iv) C6H5N2Cl + C2H5OH →
\n
(v) C6H5NH2 + Br2(aq) →
\n
(vi) C6H5NH2 + (CH3CO)2 O →
\n
(vii) C6H5N2Cl \"\"
", "answer_text": "
(i) C6H5NH2 + CHCl3 + 3KOH(alc) \"\" C6H5N+ ≡ C– + 3KCl + 3H2O
\n
(ii) C6H5N2Cl + H3PO2 + H2O \"\" C6H6 + N2 + H3PO3 + HCl
\n
(iii) \"\"
\n
(iv) C6H5N2Cl + C2H5OH \"\" C6H6 + CH3CHO + N2 + HCl
\n
(v) \"\"
\n
(vi) C6H5NH2 + CH3CO – O – COCH3 \"\" C6H5NHCOCH3 + CH3COOH
\n
(vii) C6H5N2Cl \"\" C6H5N2+BF4–
\n
C6H5NO2 + N2 + NaBF4
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/253.png", "position": "stem", "context": "(vii) C 6 H 5 N 2 Cl" }, { "id": "img-1", "path": "Chapter9/255.png", "position": "answer", "context": "(i) C 6 H 5 NH 2 + CHCl 3 + 3KOH(alc) C 6 H 5 N + ≡ C – + 3K…" }, { "id": "img-2", "path": "Chapter9/256.png", "position": "answer", "context": "(ii) C 6 H 5 N 2 Cl + H 3 PO 2 + H 2 O C 6 H 6 + N 2 + H 3 P…" }, { "id": "img-3", "path": "Chapter9/257.png", "position": "answer", "context": "(iii)" }, { "id": "img-4", "path": "Chapter9/258.png", "position": "answer", "context": "(iv) C 6 H 5 N 2 Cl + C 2 H 5 OH C 6 H 6 + CH 3 CHO + N 2 + …" }, { "id": "img-5", "path": "Chapter9/259.png", "position": "answer", "context": "(v)" }, { "id": "img-6", "path": "Chapter9/260.png", "position": "answer", "context": "(vi) C 6 H 5 NH 2 + CH 3 CO – O – COCH 3 C 6 H 5 NHCOCH 3 + …" }, { "id": "img-7", "path": "Chapter9/261.png", "position": "answer", "context": "(vii) C 6 H 5 N 2 Cl C 6 H 5 N 2 + BF 4 –" } ], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "11", "original_raw_text": " Complete the following reactions:\n\t(i) C6H5NH2 + CHCl3 + Alcoholic KOH →\n (ii)\tC6H5N2Cl + H3PO2 + H2O →\n (iii) C6H5NH2 + H2SO4 (Concentrated) →\n (iv) C6H5N2Cl + C2H5OH →\n (v) C6H5NH2 + Br2(aq) →\n (vi) C6H5NH2 + (CH3CO)2 O →\n (vii) C6H5N2Cl ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 62, "question_text": "
Why can not aromatic primary amines be prepared by Gabriel phthalimide synthesis? \t
", "answer_text": "
The success of the Gabriel phthalimide synthesis rests on the nucleophilic attack of phthalimide ion on the organic halide compound.
\n
Aryl halides can not be converted to aryl amines by Gabriel synthesis because they do not undergo nucleophilic substitution with potassium phthalimide. So, aromatic primary amines can not be prepared by this method.
\n
\"\"
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/264.png", "position": "answer", "context": "" } ], "tables": [], "metadata": { "source_class": "Quest", "marks": 2, "source_number": "12", "original_raw_text": " Why can not aromatic primary amines be prepared by Gabriel phthalimide synthesis? \t", "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 63, "question_text": "
Write the reactions of
\n
\t(i) aromatic and
\n
\t(ii) aliphatic primary amines with nitrous acid.
\n
Or
\n
\tExplain the reaction of primary aliphatic amine and aromatic amine compounds with nitrous acid with necessary equations.
", "answer_text": "
Refer Que. no. 24 Page no. 248
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-89", "source_number": "13", "marks": 2, "boundary_log": [ "or_alt→stem" ], "original_raw_text": " Write the reactions of \n\t(i) aromatic and\n\t(ii) aliphatic primary amines with nitrous acid. \nOr\n\tExplain the reaction of primary aliphatic amine and aromatic amine compounds with nitrous acid with necessary equations.", "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } }, { "sequence_no": 64, "question_text": "
Give plausible explanation for each of the following:
\n
\t(i) Why are amines less acidic than alcohols of comparable molecular masses?
\n
\t(ii) Why do primary amines have higher boiling point than tertiary amines?
\n
\t(iii) Why are aliphatic amines stronger bases than aromatic amines?
", "answer_text": "
(i)\tAmine compounds are less acidic than alcohol compounds of the same molecular masses because an N-H bond is less polar than an O-N bond, so amines liberate H+ more difficulty than alcohols.
\n
(ii)\tPrimary amines have two hydrogen atoms on the N–atom and so, form intermolecular hydrogen bonding. Tertiary amines do not have hydrogen atoms on the N–atom and so these do not form hydrogen bonds. As a result of hydrogen bonding in primary amines, they have higher boiling points than tertiary amines.
\n
(iii)\tBecause of the following reason aliphatic amines are stronger bases than aromatic amines.
\n
\t(a)\tBoth arylamines and alkyl amines are basic in nature due to the presence of pair on N-atom. But arylamines are less basic than alkyl amines. less basic character of aromatic amines are due to resonating structures.
\n
\t(b)\tAs a result of resonating structures the pair of electrons become less available for protonation. Hence aromatic amines is less basic than aliphatic amines.
\n
Class 12 Chemistry (Part 2) 017
", "type": "SUB", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Quest idf8a19c05b-ParaOverride-3", "source_number": "14", "original_raw_text": " Give plausible explanation for each of the following:\n\t(i) Why are amines less acidic than alcohols of comparable molecular masses?\n\t(ii) Why do primary amines have higher boiling point than tertiary amines?\n\t(iii) Why are aliphatic amines stronger bases than aromatic amines? ", "marks": 0, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Exercise Q & A", "section_id": "4.5" } } ] }, { "section_id": "4.7", "section_title": "Multiple Choice Questions (MCQs)", "heading_text": "Multiple Choice Questions (MCQs)", "detected_type": "MCQ", "match_confidence": 1.0, "questions": [ { "sequence_no": 65, "question_text": "
(I) CH3CH2CH2NH2\t
\n
(II) (CH3)3N
\n
(III) \"\"
\n
(IV) CH3CH2CH3
\n
27.\tWhich of the following compounds is the weakest Bronsted base?
\n
1.\tWhat is the number of isomers of primary amine having molecular formula C4H11N?
\n
2.\tWhich of the following is a secondary amine?
\n
3.\tC7H9N has ________ isomers.
\n
4.\tMethyl cyanide and methyl isocyanide show which type of isomerism?
\n
5.\tIdentify the IUPAC name of CH3CH2CH(CH3) NH2 .
\n
6.\tA secondary amine is a __________.
\n
7.\tWhich is a secondary amine?
\n
8.\tWhat is the IUPAC name of vinyl cyanide?
\n
9.\tWhich amine shows metamerism?
\n
10.\tReduction of which compound forms a secondary amine?\t
\n
11.\tIn (CH3)3N the state of hybridization of N-atom and the spatial rearrangement of methyl groups around it are respectively.
\n
12.\tWhat is the C–N–C bond angle in trimethyl aniline?
\n
13.\tWhich of the following is a secondary amine?
\n
14.\tWhat causes bond angles to decrease in amine compounds?
\n
15.\tDisplacement of the hydrogen of ammonia by hydrocarbon group form __________.
\n
16.\tIf one hydrogen atom of NH3 is replaced by an alkyl or aryl group, it is called __________ amine.
\n
17.\tIdentify the type of amine \"\"N – H
\n
18.\t_______ groups are same in simple amines.
\n
19.\tWhich of the following amines is a mixed amine?
\n
20.\tWhat does C3H9N represent?
\n
21.\tWhich of the following statements is false?
\n
22.\tWhat is the IUPAC name of \"\" compound?
\n
23.\tIdentify the correct IUPAC name of
CH2 = CH – CH2 – NH – CH3.
\n
24.\tIdentify the IUPAC name of the following:
\n
\"\"
\n
25.\tThe IUPAC name of \"\" is:
\n
26.\tIdentify the IUPAC name of isopropyl amine:
\n
27.\tWhich of the given processes differs from the others with respect to the formation of amine compounds?
\n
28.\tPrimary aromatic amines cannot be prepared by which of the following processes?
\n
29.\tWhich is the alkanamide compound that yields 1–phenyl ethyl amine by Hofmann reaction?
\n
30.\tThe reaction of an alkylhalide with KCN leads to the formation of product by the reduction of that product will get?
\n
31.\tReduction of the product obtained by dehydration of the amide gives a ________.
\n
32.\tWhich of the given nitrogen containing compound will give Hofmann reaction?
\n
33.\tAcetamide treated independently with the following reagents, which of the reagents will yield methyl amine?
\n
34.\tWhich of the following substances can't be made by Gabriel phthalimide synthesis?
\n
35.\tWhich of the following reagents will convert nitromethane into methyl amine?
\n
36.\tA given nitrogen containing aromatic compound ‘A’ reacts with Sn/HCl‚ followed by HNO2 to give an unstable compound ‘B’ . ‘B’ on treatment with phenol, forms beautiful coloured compound 'C' with the molecular formula C12H10N2O. Identify the compound.
\n
37.\t_________ compound will give Hofmann bromamide reaction.
\n
38.\tWhich amine can not be made by gabriel synthesis?
\n
39.\tAceto nitrile reduction gives ________.
\n
40.\tWhich reagent is useful for the formation of methanamine from acetamide?
\n
41.\tWhat happens when nitro alkane is reduced?
\n
42.\tCH3CH2CONH2 \"\" main organic product [X]. what is X here?
\n
43.\tCH3 – CH2 – CH2 – NO2 \"\" X
\n
is given reaction = ________.
\n
44.\tWhy is Fe/HCl is more useful than Sn/HCl for the reduction of nitro compounds under present condition?
\n
45.\tFree amine is obtained by treating ammonium salt with whom?
\n
46.\t\"\" X, in given reaction
\n
X = \"\"
\n
47.\tWhich order of reactivity of a halide with an amine is correct?
\n
48.\tWhich of the aryl halide and alkyl halide is less reactive towards nucleophilic substitution reaction?
\n
49.\tHow primary amines can be obtained from the mixture of ammonium salts obtained during ammonolysis?
\n
50.\tAmide can be converted to amine by which process?
\n
51.\tBy which of the following does the process of LiAlH4 give a secondary amine (2°)?
\n
52.\tCH3C ≡ N \"\" in this
\n
reaction X = ________.
\n
53.\tR–X \"\" X \"\" Y
\n
\tin this reaction Y = ________.
\n
54.\tX \"\";
\n
\tIn the reaction X = ________.
\n
55.\tCH3NO2 \"\" CH3 – X
\n
\tIn this reaction X = ________.
\n
56.\tCH3 – CO – N\"\" \"\" ,
\n
\tProduct in this reaction is ________.
\n
57.\tIn Hofmann reaction, the amine formed has how many more carbon atoms than the present amide?
\n
58.\t\"\" + Br2 + 4NaOH \"\" ________.
\n
59.\tWhich of the following processes will not give a primary amine?
\n
60.\tGabriel phthalimide reaction is useful for the preparation of which of the following compounds?
\n
61.\tWhich of the following amines cannot be prepared by Gabriel phthalimide reaction?
\n
62.\tBenzyl amine can be produced by which of the following processes?
\n
63.\tGabriel phthalimide synthesis method is useful for whom?
\n
64.\tReduction of which amide yields \"\" compound?
\n
65.\tPropanoic acid \"\" X \"\"
Y \"\" Z, Z = ________.
\n
66.\tBy which reaction amine is not obtained?
\n
67.\t2-Bromopropane\"\" x \"\" y,
\n
then IUPAC name of y is:
\n
68.\tWhich of the following has the lowest boiling point?
\n
69.\tAniline is soluble in.
\n
70.\tWhich of the following will have the highest boiling point?
\n
71.\tWhat is the state of very low molecular weight aliphatic amines?
\n
72.\t(i) C2H6 (ii) CH3CH2NH2 (iii) C2H5OH Which is the correct ascending order of the boiling point for the given three compounds?
\n
73.\tWhich is the correct descending order of boiling point for amine compounds having the same molecular formula?
\n
74.\tWhich type of isomerism is present in 1-propane amine and 2-propane amine?
\n
75.\tWhich of the following types of amine compounds have metamerism isomerism?
\n
76.\tWhich of the following order is correct with respect to polarity?
\n
77.\tWhat is the difference between the electronegativity of O and N?
\n
78.\tWhich amine has the lowest boiling point among isomeric amines?
\n
79.\tWhich of the following has intermolecular
H bonding?
\n
80.\tAmong ethyl alcohol, ethyl amine and formic acid, which has the highest boiling point?
\n
81.\tHow do lower amine compounds smell?
\n
82.\tWhich compound has a bad odor?
\n
83.\tWhich compound is soluble in alkali?\t
\n
84.\tWhich compound does not react with Hinsberg's reagent?
\n
85.\tWhat is obtained by the reaction of aniline with acetyl chloride?
\n
86.\tWhich compound does not give carbyl amine test?
\n
87.\tWhich of the given amine compounds is most basic?
\n
88.\t\"\" X + Y + Z.
\n
\tIf X , Y and Z get 47%, 2% and 51% respectively then what will be the product respectively?
\n
4–Nitro aniline\t
\n
4–Nitro aniline
\n
3–Nitro aniline\t
\n
2–Nitro aniline
\n
89.\tWhich order of basicity is correct in aqueous solution?\t
\n
90.\tWhich compound does not react with Hinsberg's reagent?
\n
91.\tAlcohol is formed by the reaction of which compound with nitrous acid? \t
\n
92.\tAn organic compound ‘A’ on reduced gives compound 'B' which on reaction with chloroform and potassium hydroxide forms 'C'. The compound 'C' on catalytic reduction gives N-Methylaniline, The compound 'A' is:
\n
93.\tCH3CH2Cl \"\" X \"\" Y \"\" Z. In the given reaction identify the product 'Z'. \t
\n
94.\tState the end result of the given reaction series
\n
Ethanamine \"\" A \"\" B \"\" C.
\n
95.\tAn organic compound ‘A’ on reduction gave a ‘B’ compound‚ upon treatment with HNO2 gave ethanol, Identify the compound 'A'.
\n
96.\tWhich statement is false for primary amine compounds?
\n
97.\tWhat is the product of benzoylation of N-ethyl ethanamine?
\n
98.\tBenzanilide is produced by the process between which substances?
\n
99.\tWhich of the given functional group increases the basic strength of the aniline?
\n
100.\tWhich of the following reactions of aniline gives zwitterion?
\n
101.\tThe reaction of amine compound with benzene sulphonyl chloride yields a solid compound insoluble in alkali which amine compound would it be?
\n
102.\tCH3CH2NH2 contains basic NH2 group but CH3CONH2 does not contain basic NH2 group because,
\n
103.\tIdentify the main product 'C' in the following reaction:
\n
Aniline \"\" A \"\" B \"\" C.
\n
104.\tIn which of the following process will cyanide be obtained as the main product?
\n
105.\tEthyl amine and diethyl amine cannot be differentiated by which test?
\n
106.\tAniline when acetylated, the product on nitration followed by alkaline hydrolysis gives:
\n
107.\tWhich of the following compounds does not react with Hinsberg's reagent?
\n
108.\tWhich is a stronger base than amine?
\n
109.\tWhat is the reaction of ethanamine with chloroforms and alcoholic KOH?
\n
110.\tWhich method is not for the forming amines or separating amines?
\n
111.\tFind the strongest base.
\n
112.\tWhich of the following amine reacts with NaNO2 and HCl at 273-278 K–to give alcohol?
\n
113.\tWhich of the following is the correct order based on the amount of product produced by nitration of aniline?
\n
> m-Nitroaniline
\n
> p-Nitroaniline
\n
> o-Nitroaniline
\n
> o-Nitroaniline
\n
114.\tWhose pKb value is highest?
\n
115.\tBenzene sulphonyl chloride is called a_______.
\n
116.\t1° Amine are converted to 3° amine by_________.
\n
117.\tThe activating effect of the amino group in aniline is reduced by ________.
\n
118.\tWhich of the following will have the highest pKb?
\n
119.\tWhich of the following is a foul smelling and poisonous substance?
\n
120.\tWhich of the following compounds gives alcohol with NaNO2 and HCl?
\n
121.\tWhat is the relative basicity of alkanamine and ammonia?
\n
122.\tOn what does the basicity of an amine depends?
\n
123.\tWhich property makes amine compounds behave as Lewis base?
\n
124.\tWhat are amine compounds in water?
\n
125.\tBelow are the values of pKb for same bases, select the lowest base accordingly:
\n
126.\tWhich of the following is the correct ascending order of basicity of aqueous solution?
\n
127.\tChoose the correct order of basic strength in the vapour phase (non-aqueous solution) for the following amine compounds.
\n
128.\tWhich of the following is the strongest base in aqueous solution?
\n
129.\tWhich of the following is the most basic?
\n
130.\tWhich of the following is the most basic?
\n
131.\tWhich of the following is the strong base?
\n
132.\tWhich of the following is a weak base?
\n
133.\tWhich of the following is the correct order of basicity for ethyl substituted amine?
\n
134.\tWhat is the end product 'Y' in the following sequential reaction?
\n
CH3CH2CH2CONH2 \"\" X \"\" Y
\n
135.\t\"\"
\n
\tIn this reaction X = ________.
\n
136.\tC6H5 – NH2 + C6H5COCl \"\" Y
\n
\tIn this reaction Y = ________.
\n
137.\tR – NH2 + CHCl3 + 3KOH \"\" X
\n
\tIn this reaction X = ________.
\n
138.\tWhich of the following procedures is not useful in the preparation of amine compounds or separation of amine compounds?
\n
139.\tIn the given reaction, identify 'Z'.
\n
C6H5NH2 \"\" X \"\" Y \"\" Z
\n
140.\tp-toluidine \"\"?
\n
Identify the product in the given reaction.
\n
141.\tCH3CH2Cl \"\" X \"\" Y \"\" Z
\n
In the above reaction, identify the 'Z'.
\n
142.\t\"\"
\n
In this reaction X = ________.
\n
143.\tAcetanilide \"\" X \"\" Y
\n
In the given reaction Y = ________.
\n
144. C6H5NH2 \"\" X
\n
In this reaction X = ________.
\n
145.\tAniline does not undergo which of the following reactions?
\n
146.\tWhat is the used reagent for the separation of 1°, 2°, 3° amines?
\n
147.\tWhich of the following substance will react with benzene sulphonyl chloride?
\n
148.\tAniline \"\" X \"\" Y
\n
\tIn this reaction X = ________.
\n
149.\tWhich of the following amines does not react with acetyl chloride?
\n
150.\tIn below reaction identify the product:
\n
\"\"?
\n
151.\tWhy diazonium salts are used immediately?
\n
152.\tCH3CH2NH2 + CHCl3 + 3KOH → x + y + 3H2O.
In this reaction x and y compounds are?
\n
153.\tChemical reactions of propionic acid are given below. Identify the end product (D)?
\n
CH3CH2COOH \"\" B \"\" C
\n
D
\n
154.\tWhich of the following diazonium salts are stable at room temperature?
\n
155.\tWhat is the common formula of diazonium salt?
\n
156.\tWhat will be obtained by heating benzene diazonium chloride and hypo phosphorous acid at room temperature?
\n
157.\tWhich compound is not made by Sandmeyer's reaction?
\n
158.\tWhat is p-hydroxy azo benzene?
\n
159.\tWhich of the following compounds will give dye test?
\n
160.\t Aniline \"\" A \"\" B \"\" C \"\" In given reaction identify the product D and give its structure.
\n
161.\tHow many total isomers of organic compounds having molecular formula C7H9N will react with nitrous acid?
\n
162.\tIdentify the compound 'B' in the following conversion.
\n
Aniline \"\" A \"\" B
\n
163.\tC6H5NH2 \"\" A \"\" B.
\n
In this reaction product B _______.
\n
164.\tAniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in the presence of dilute hydrochloric acid. The compound so formed is reacted with a tetra fluoro borate which is subsequently heated. The final product is?
\n
165.\tC6H5N2+Cl – \"\" C6H5Cl + N2:
Identify the name of the reaction.
\n
166.\tC6H5N2+Cl – \"\" C6H5Cl + N2 + CuCl: Identify the name of the reaction.
\n
167.\tArN2+ Cl– \"\" ArCl + N2. Identify the name of the reaction _________.
\n
168.\tWhich of the following is a product of Gattermann reaction?
\n
169.\tWhich of the following is the structural formula of orange azo dye?
\n
(A)
\n
(B)
\n
(C) \"\"
\n
(D)
\n
170.\t________ is the Gattermann reagent?
\n
171.\t\"\" X
\n
In this reaction X = ________.
\n
172.\tBenzene diazonium chloride is a ________ solid.
\n
173.\tAt what temperature does benzene diazonium chloride become stable?
\n
174.\tWhich of the following diazonium salts is stable at room temperature?
\n
175.\tC6H5N2+Cl– \"\" X
\n
In this reaction X = ________.
\n
176.\tWhich of the following reagent is used in Gattermann reaction?
\n
177.\tThe reaction involving the treatment of benzene diazonium chloride with copper powder and HCl gives chlorobenzene or bromo benzene termed as:
\n
178.\tC6H5N2+Cl– \"\" X
\n
In this reaction X = ________.
\n
179.\tBenzene diazonium fluoroborate In this reaction X = ________.
\n
180.\t\"\" Y
\n
In the reaction Y = ________.
\n
181.\tBenzene diazonium chloride\"\"
\n
X In this reaction X = ________.
\n
182.\tC6H5N2+Cl– \"\" X
\n
In this reaction X = ________.
\n
183.\tWhich of the following is a light yellow azo dye?
\n
184.\tWhat product will be getting by the reaction of primary aliphatic amine and nitrous acid?
\n
185.\t________ reacts with phenol to give an azo dye.
\n
186.\tWhich of the following reaction is incorrect of Aryl diazonium salt?
\n
187. Identify the W, X, Y, Z in the given reaction:
\n
nitro be\tnzene \"\" W \"\" X
\n
\"\" Y \"\" Z
\n
X = 2, 4, 6-Tribromoaniline
\n
Y = 2, 4, 6-Tribromobenzene\t\t\tdiazonium chloride
\n
Z = 1, 3, 5-Tribromobenzene
\n
X = 2, 4, 6-Tribromobenzene
\n
Y = 2, 4, 6-Trichlorobenzene
\n
Z = 2, 4, 6-Trichlorophenol
\n
X = p-bromoaniline
\n
Y = p-bromobenzene diazonium chloride
\n
Z = p-bromophenol
\n
X = p-bromoaniline
\n
Y = p-bromobenzene diazonium chloride
\n
Z = bromobenzene
\n
188.\tIdentify the U in below reaction:
\n
\"\"
\n
189.\tIn below reaction which two products are same?
\n
\"\"
\n
190.\tAssertion\t: Aliphatic amines are more basic than aromatic amines.
\n
Reason\t: The lone pair of electrons on the nitrogen atom in aliphatic amines is delocalized over the aromatic ring through resonance.
\n
191. \tAssertion\t: Ortho-substituted aniline is less basic than aniline.
\n
\tReason\t:\tOrtho-substituted aniline experiences both electronic effects and steric hindrance, reducing its basicity.
\n
192. \tAssertion\t:\tElectron-releasing groups increase the basic strength of aniline derivatives.
\n
Reason\t:\tElectron-releasing groups donate electron density to the benzene ring, making the lone pair on nitrogen more available for protonation.
\n
193. \tAssertion\t:\tThe basic strength of methylamine is higher than ammonia in aqueous solutions.
\n
\tReason\t:\tMethylamine forms stronger hydrogen bonds with water compared to ammonia.
\n
194. \tAssertion\t:\tSecondary amines have lower boiling points than primary amines of similar molecular mass.
\n
Reason\t:\tSecondary amines cannot form intermolecular hydrogen bonds.
\n
195. \tAssertion\t:\tAniline reacts with bromine water to give 2,4,6-tribromoaniline.
\n
Reason\t:\tAniline is a strong electron-withdrawing group.
\n
196. \tAssertion\t: \tp-Nitroaniline is less basic than p-methoxyaniline.
\n
Reason\t: \tThe -NO2 group at the para position is an electron-withdrawing group, whereas -OCH3 is an electron-releasing group.
\n
197.\tAssertion\t:\tTertiary amines are less soluble in water compared to primary amines of similar molecular weight.
\n
Reason\t:\tTertiary amines lack hydrogen atoms for hydrogen bonding with water.
\n
198.\tAssertion\t:\tAniline is less basic than ammonia.
\n
Reason\t:\tThe lone pair of electrons on the nitrogen atom in aniline participates in resonance with the benzene ring, reducing its availability for protonation.
\n
199.\tAssertion\t:\tp-Toluidine is more basic than aniline.
\n
Reason\t:\tThe –CH3 group in p-toluidine donates electron density to the benzene ring, increasing the availability of the lone pair on nitrogen.
\n
200.\tAssertion\t:\tMethylamine has a higher boiling point than dimethylamine.
\n
Reason\t:\tMethylamine forms stronger hydrogen bonds compared to dimethylamine due to more hydrogen atoms on the nitrogen.
\n
201.\tAssertion\t:\tBenzenediazonium chloride is stable at low temperatures.
\n
Reason\t:\tAt low temperatures, the decomposition of benzenediazonium chloride is kinetically hindered.
\n
202.\tAssertion\t:\tThe boiling points of primary amines are higher than those of alcohols of similar molecular weight.
\n
Reason\t:\tHydrogen bonding in amines is stronger than in alcohols due to the higher electronegativity of nitrogen compared to oxygen.
\n
203.\tAssertion\t: The reaction of nitrous acid with primary aliphatic amines produce alcohols.
\n
Reason\t:\tPrimary aliphatic amines form unstable diazonium salts, which decompose to give alcohols.
\n
204.\tAssertion\t:\tAmines can be distinguished by the Hinsberg test.
\n
Reason\t:\tHinsberg’s reagent reacts differently with primary, secondary, and tertiary amines, forming distinguishable products.
\n
205. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tPrimary amines can form hydrogen bonds with water.
\n
(ii)\tSecondary amines have higher boiling points than primary amines.
\n
(iii)\tAniline reacts with bromine water to form 2,4,6-tribromoaniline.
\n
(iv)\tAromatic amines are less basic than aliphatic amines.
\n
206. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tAniline is a weaker base than ammonia.
\n
(ii)\tElectron-donating groups increase the basicity of aniline.
\n
(iii)\tThe –NO2 group at the meta position decreases the basicity of aniline.
\n
(iv)\tTertiary amines are less soluble in water than primary amines.
\n
207. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tBenzenediazonium chloride is stable at room temperature.
\n
(ii)\tDiazonium salts decompose to form alcohols in aqueous solutions.
\n
(iii)\tThe diazotization reaction occurs at
273–278 K.
\n
(iv)\tBenzenediazonium chloride reacts with phenol to form an azo compound.
\n
208. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tAmines can act as nucleophiles in organic reactions.
\n
(ii)\tTertiary amines cannot form hydrogen bonds.
\n
(iii)\tPrimary amines give positive Carbylamine tests.
\n
(iv)\tElectron-withdrawing groups increase the basicity of aniline.
\n
209.\tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tHinsberg’s reagent reacts with all types of amines.
\n
(ii)\tSecondary amines form N-alkyl sulphonamide with Hinsberg’s reagent.
\n
(iii)\tTertiary amines are insoluble in water.
\n
(iv)\tAniline is a primary aromatic amine.
\n
210. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tOrtho-substituted anilines are more basic than aniline.
\n
(ii)\tElectron-donating groups at the para position increase the basicity of aniline.
\n
(iii)\tMethylamine is a stronger base than ethylamine.
\n
(iv)\tAliphatic amines are generally stronger bases than aromatic amines.
\n
211. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tPrimary amines can be prepared by Gabriel phthalimide synthesis.
\n
(ii)\tGabriel synthesis can also produce secondary amines.
\n
(iii)\tReduction of nitriles yields primary amines.
\n
(iv)\tAmmonia reacts with alkyl halides to produce primary amines directly.
\n
212. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tTertiary amines have no N-H bonds.
\n
(ii)\tThe boiling point of an amine increases with molecular weight.
\n
(iii)\tAmines are less soluble in water than alcohols of similar molecular weight.
\n
(iv)\tAromatic amines exhibit a higher boiling point than aliphatic amines of similar size.
\n
213. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tAromatic amines undergo electrophilic substitution reactions.
\n
(ii)\tThe amino group in aniline is
meta-directing in electrophilic substitution reactions.
\n
(iii)\tBromination of aniline in aqueous solution forms 2,4,6-tribromoaniline.
\n
(iv)\tNitration of aniline produces predominantly para-nitroaniline.
\n
214. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tAmines can act as Bronsted bases.
\n
(ii)\tThe pKb value of aliphatic amines is higher than aromatic amines.
\n
(iii)\tEthylamine reacts with nitrous acid to give ethyl alcohol.
\n
(iv)\tTertiary amines react with nitrous acid to form alcohols.
\n
215. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tAmines are more basic in aqueous solution than in the gaseous state.
\n
(ii)\tAmmonia is less basic than methylamine.
\n
(iii)\tTertiary amines are always more basic than secondary amines.
\n
(iv)\tBenzylamine is an aromatic amine.
\n
216. \tSelect the correct option using T (True) or
F (False) symbol for the following statements.
\n
(i)\tDiazonium salts are used in azo dye synthesis.
\n
(ii)\tAliphatic diazonium salts are more stable than aromatic diazonium salts.
\n
(iii)\tPhenols react with diazonium salts to form coloured azo compounds.
\n
(iv)\tAzo coupling is an electrophilic substitution reaction.
\n
Class 12 Chemistry (Part 2) 018
", "answer_text": "", "type": "MCQ", "type_uncertain": false, "options": { "A": "TFTT", "B": "FTTT", "C": "TTFT", "D": "FTFT" }, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/298.png", "position": "stem", "context": "(III)" }, { "id": "img-1", "path": "Chapter9/299.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-2", "path": "Chapter9/300.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-3", "path": "Chapter9/301.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-4", "path": "Chapter9/302.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-5", "path": "Chapter9/307.png", "position": "stem", "context": "17. Identify the type of amine N – H" }, { "id": "img-6", "path": "Chapter9/308.png", "position": "option:C", "context": "(C) (D) (CH 3 CH 2 ) 2 NH" }, { "id": "img-7", "path": "Chapter9/309.png", "position": "stem", "context": "22. What is the IUPAC name of compound?" }, { "id": "img-8", "path": "Chapter9/310.png", "position": "stem", "context": "" }, { "id": "img-9", "path": "Chapter9/311.png", "position": "stem", "context": "25. The IUPAC name of is:" }, { "id": "img-10", "path": "Chapter9/313.png", "position": "stem", "context": "42. CH 3 CH 2 CONH 2 main organic product [X] . what is X h…" }, { "id": "img-11", "path": "Chapter9/314.png", "position": "stem", "context": "43. CH 3 – CH 2 – CH 2 – NO 2 X" }, { "id": "img-12", "path": "Chapter9/315.png", "position": "stem", "context": "46. X, in given reaction" }, { "id": "img-13", "path": "Chapter9/316.png", "position": "stem", "context": "X =" }, { "id": "img-14", "path": "Chapter9/317.png", "position": "stem", "context": "52. CH 3 C ≡ N in this" }, { "id": "img-15", "path": "Chapter9/318.png", "position": "stem", "context": "53. R–X X Y" }, { "id": "img-16", "path": "Chapter9/319.png", "position": "stem", "context": "53. R–X X Y" }, { "id": "img-17", "path": "Chapter9/320.png", "position": "stem", "context": "54. X ;" }, { "id": "img-18", "path": "Chapter9/321.png", "position": "stem", "context": "55. CH 3 NO 2 CH 3 – X" }, { "id": "img-19", "path": "Chapter9/322.png", "position": "stem", "context": "56. CH 3 – CO – N ," }, { "id": "img-20", "path": "Chapter9/323.png", "position": "stem", "context": "56. CH 3 – CO – N ," }, { "id": "img-21", "path": "Chapter9/324.png", "position": "stem", "context": "58. + Br 2 + 4NaOH ________ ." }, { "id": "img-22", "path": "Chapter9/325.png", "position": "stem", "context": "58. + Br 2 + 4NaOH ________ ." }, { "id": "img-23", "path": "Chapter9/326.png", "position": "option:A", "context": "(A) Acetamide" }, { "id": "img-24", "path": "Chapter9/327.png", "position": "option:B", "context": "(B) Ethane nitrile" }, { "id": "img-25", "path": "Chapter9/327.png", "position": "option:C", "context": "(C) Methyl iso cyanide" }, { "id": "img-26", "path": "Chapter9/327.png", "position": "option:D", "context": "(D) Acetamide" }, { "id": "img-27", "path": "Chapter9/330.png", "position": "option:A", "context": "(A) NH 2 (B) CH 2 – NH 2" }, { "id": "img-28", "path": "Chapter9/330.png", "position": "option:A", "context": "(A) NH 2 (B) CH 2 – NH 2" }, { "id": "img-29", "path": "Chapter9/332.png", "position": "option:C", "context": "(C) CH 3 – NH – CH 3 (D)" }, { "id": "img-30", "path": "Chapter9/333.png", "position": "option:A", "context": "(A) C 6 H 5 CONH 2" }, { "id": "img-31", "path": "Chapter9/334.png", "position": "option:B", "context": "(B) C 6 H 5 CN" }, { "id": "img-32", "path": "Chapter9/335.png", "position": "option:C", "context": "(C) phthalimide" }, { "id": "img-33", "path": "Chapter9/336.png", "position": "stem", "context": "64. Reduction of which amide yields compound?" }, { "id": "img-34", "path": "Chapter9/337.png", "position": "stem", "context": "65. Propanoic acid X Y Z, Z = ________ ." }, { "id": "img-35", "path": "Chapter9/338.png", "position": "stem", "context": "65. Propanoic acid X Y Z, Z = ________ ." }, { "id": "img-36", "path": "Chapter9/339.png", "position": "stem", "context": "65. Propanoic acid X Y Z, Z = ________ ." }, { "id": "img-37", "path": "Chapter9/340.png", "position": "option:B", "context": "(B) RCH = N – OH + [H]" }, { "id": "img-38", "path": "Chapter9/341.png", "position": "option:C", "context": "(C) RCN + H 2 O" }, { "id": "img-39", "path": "Chapter9/342.png", "position": "option:D", "context": "(D) RCONH 2 + 4H" }, { "id": "img-40", "path": "Chapter9/343.png", "position": "stem", "context": "67. 2- Bromopropane x y," }, { "id": "img-41", "path": "Chapter9/344.png", "position": "stem", "context": "67. 2- Bromopropane x y," }, { "id": "img-42", "path": "Chapter9/347.png", "position": "stem", "context": "88. X + Y + Z." }, { "id": "img-43", "path": "Chapter9/348.png", "position": "stem", "context": "93. CH 3 CH 2 Cl X Y Z. In the given reaction identify the p…" }, { "id": "img-44", "path": "Chapter9/349.png", "position": "stem", "context": "93. CH 3 CH 2 Cl X Y Z. In the given reaction identify the p…" }, { "id": "img-45", "path": "Chapter9/350.png", "position": "stem", "context": "93. CH 3 CH 2 Cl X Y Z. In the given reaction identify the p…" }, { "id": "img-46", "path": "Chapter9/351.png", "position": "stem", "context": "Ethanamine A B C ." }, { "id": "img-47", "path": "Chapter9/352.png", "position": "stem", "context": "Ethanamine A B C ." }, { "id": "img-48", "path": "Chapter9/353.png", "position": "stem", "context": "Ethanamine A B C ." }, { "id": "img-49", "path": "Chapter9/354.png", "position": "stem", "context": "Aniline A B C." }, { "id": "img-50", "path": "Chapter9/355.png", "position": "stem", "context": "Aniline A B C." }, { "id": "img-51", "path": "Chapter9/356.png", "position": "stem", "context": "Aniline A B C." }, { "id": "img-52", "path": "Chapter9/357.png", "position": "option:A", "context": "(A) C 6 H 5 CONH 2" }, { "id": "img-53", "path": "Chapter9/360.png", "position": "option:D", "context": "(D) C 6 H 5 COOH" }, { "id": "img-54", "path": "Chapter9/361.png", "position": "option:D", "context": "(D) C 6 H 5 COOH" }, { "id": "img-55", "path": "Chapter9/362.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-56", "path": "Chapter9/363.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-57", "path": "Chapter9/364.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-58", "path": "Chapter9/365.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-59", "path": "Chapter9/366.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-60", "path": "Chapter9/367.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-61", "path": "Chapter9/368.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-62", "path": "Chapter9/369.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-63", "path": "Chapter9/370.png", "position": "stem", "context": "CH 3 CH 2 CH 2 CONH 2 X Y" }, { "id": "img-64", "path": "Chapter9/371.png", "position": "stem", "context": "CH 3 CH 2 CH 2 CONH 2 X Y" }, { "id": "img-65", "path": "Chapter9/372.png", "position": "stem", "context": "135." }, { "id": "img-66", "path": "Chapter9/373.png", "position": "stem", "context": "136. C 6 H 5 – NH 2 + C 6 H 5 COCl Y" }, { "id": "img-67", "path": "Chapter9/374.png", "position": "stem", "context": "137. R – NH 2 + CHCl 3 + 3KOH X" }, { "id": "img-68", "path": "Chapter9/375.png", "position": "stem", "context": "C 6 H 5 NH 2 X Y Z" }, { "id": "img-69", "path": "Chapter9/376.png", "position": "stem", "context": "C 6 H 5 NH 2 X Y Z" }, { "id": "img-70", "path": "Chapter9/377.png", "position": "stem", "context": "C 6 H 5 NH 2 X Y Z" }, { "id": "img-71", "path": "Chapter9/378.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-72", "path": "Chapter9/379.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-73", "path": "Chapter9/380.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-74", "path": "Chapter9/381.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-75", "path": "Chapter9/382.png", "position": "stem", "context": "140. p -toluidine ?" }, { "id": "img-76", "path": "Chapter9/383.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-77", "path": "Chapter9/384.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-78", "path": "Chapter9/385.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-79", "path": "Chapter9/386.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-80", "path": "Chapter9/387.png", "position": "stem", "context": "141. CH 3 CH 2 Cl X Y Z" }, { "id": "img-81", "path": "Chapter9/388.png", "position": "stem", "context": "141. CH 3 CH 2 Cl X Y Z" }, { "id": "img-82", "path": "Chapter9/389.png", "position": "stem", "context": "141. CH 3 CH 2 Cl X Y Z" }, { "id": "img-83", "path": "Chapter9/390.png", "position": "stem", "context": "142." }, { "id": "img-84", "path": "Chapter9/391.png", "position": "stem", "context": "143. Acetanilide X Y" }, { "id": "img-85", "path": "Chapter9/392.png", "position": "stem", "context": "143. Acetanilide X Y" }, { "id": "img-86", "path": "Chapter9/393.png", "position": "stem", "context": "144. C 6 H 5 NH 2 X" }, { "id": "img-87", "path": "Chapter9/394.png", "position": "stem", "context": "148. Aniline X Y" }, { "id": "img-88", "path": "Chapter9/395.png", "position": "stem", "context": "148. Aniline X Y" }, { "id": "img-89", "path": "Chapter9/396.png", "position": "stem", "context": "?" }, { "id": "img-90", "path": "Chapter9/397.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-91", "path": "Chapter9/398.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-92", "path": "Chapter9/399.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-93", "path": "Chapter9/400.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-94", "path": "Chapter9/401.png", "position": "stem", "context": "CH 3 CH 2 COOH B C" }, { "id": "img-95", "path": "Chapter9/402.png", "position": "stem", "context": "CH 3 CH 2 COOH B C" }, { "id": "img-96", "path": "Chapter9/405.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-97", "path": "Chapter9/406.png", "position": "option:A", "context": "(A) (B)" }, { "id": "img-98", "path": "Chapter9/407.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-99", "path": "Chapter9/408.png", "position": "option:C", "context": "(C) (D)" }, { "id": "img-100", "path": "Chapter9/412.png", "position": "stem", "context": "160. Aniline A B C In given reaction identify the product D …" }, { "id": "img-101", "path": "Chapter9/413.png", "position": "stem", "context": "160. Aniline A B C In given reaction identify the product D …" }, { "id": "img-102", "path": "Chapter9/414.png", "position": "stem", "context": "160. Aniline A B C In given reaction identify the product D …" }, { "id": "img-103", "path": "Chapter9/415.png", "position": "stem", "context": "160. Aniline A B C In given reaction identify the product D …" }, { "id": "img-104", "path": "Chapter9/416.png", "position": "stem", "context": "Aniline A B" }, { "id": "img-105", "path": "Chapter9/417.png", "position": "stem", "context": "Aniline A B" }, { "id": "img-106", "path": "Chapter9/418.png", "position": "stem", "context": "163. C 6 H 5 NH 2 A B." }, { "id": "img-107", "path": "Chapter9/419.png", "position": "stem", "context": "163. C 6 H 5 NH 2 A B." }, { "id": "img-108", "path": "Chapter9/420.png", "position": "stem", "context": "165. 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(A) 142. (C) 143. (B) 144. (D) 145. (D) 146. (C) 147. (C) 148. (C) 149. (C) 150. (C)
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(C) 152. (B) 153. (A) 154. (D) 155. (B) 156. (A) 157. (B) 158.\t(C) 159. (B) 160. (C)
", "answer_text": "", "type": "MCQ", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Normal idf8a19c05b-ParaOverride-146", "source_number": "151", "original_raw_text": "(C) 152. (B) 153. (A) 154. (D) 155. (B) 156. (A) 157. (B) 158.\t(C) 159. (B) 160. (C)", "marks": 1, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Based MCQs", "section_id": "4.9", "needs_review": true, "needs_layout_review": true, "layout_review_reason": "question body is a consolidated answer key (NUMBER.(LETTER) pairs) — parse it into a number→letter map, not a question", "missing_answer": true, "needs_answer_review": true, "answer_review_reason": "options + correct option not detected" } }, { "sequence_no": 85, "question_text": "
(C)\t162. (A) 163. (B) 164. (D) 165. (C) 166. (D) 167. (C) 168. (C) 169. (B) 170. (B)
", "answer_text": "", "type": "MCQ", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Normal idf8a19c05b-ParaOverride-146", "source_number": "161", "original_raw_text": "(C)\t162. (A) 163. (B) 164. (D) 165. (C) 166. (D) 167. (C) 168. (C) 169. (B) 170. (B)", "marks": 1, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Based MCQs", "section_id": "4.9", "needs_review": true, "needs_layout_review": true, "layout_review_reason": "question body is a consolidated answer key (NUMBER.(LETTER) pairs) — parse it into a number→letter map, not a question", "missing_answer": true, "needs_answer_review": true, "answer_review_reason": "options + correct option not detected" } }, { "sequence_no": 86, "question_text": "
(B) 172. (D) 173. (C) 174. (C) 175. (B) 176. (C) 177. (B) 178. (B) 179. (B) 180. (A)
", "answer_text": "", "type": "MCQ", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Normal idf8a19c05b-ParaOverride-146", "source_number": "171", "original_raw_text": "(B) 172. (D) 173. (C) 174. (C) 175. (B) 176. (C) 177. (B) 178. (B) 179. (B) 180. (A)", "marks": 1, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Based MCQs", "section_id": "4.9", "needs_review": true, "needs_layout_review": true, "layout_review_reason": "question body is a consolidated answer key (NUMBER.(LETTER) pairs) — parse it into a number→letter map, not a question", "missing_answer": true, "needs_answer_review": true, "answer_review_reason": "options + correct option not detected" } }, { "sequence_no": 87, "question_text": "
(B) 182. (C) 183. (C) 184. (C) 185. (A) 186. (C) 187. (A) 188. (C) 189. (D) 190. (C)
", "answer_text": "", "type": "MCQ", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Normal idf8a19c05b-ParaOverride-146", "source_number": "181", "original_raw_text": "(B) 182. (C) 183. (C) 184. (C) 185. (A) 186. (C) 187. (A) 188. (C) 189. (D) 190. (C)", "marks": 1, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Based MCQs", "section_id": "4.9", "needs_review": true, "needs_layout_review": true, "layout_review_reason": "question body is a consolidated answer key (NUMBER.(LETTER) pairs) — parse it into a number→letter map, not a question", "missing_answer": true, "needs_answer_review": true, "answer_review_reason": "options + correct option not detected" } }, { "sequence_no": 88, "question_text": "
(A) 192.\t(A) 193.\t(B) 194. (C) 195. (C) 196.\t(A) 197. (A) 198. (A)\t199. (A)\t200. (A)
", "answer_text": "", "type": "MCQ", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Normal idf8a19c05b-ParaOverride-146", "source_number": "191", "original_raw_text": "(A) 192.\t(A) 193.\t(B) 194. (C) 195. (C) 196.\t(A) 197. (A) 198. (A)\t199. (A)\t200. (A)", "marks": 1, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Based MCQs", "section_id": "4.9", "needs_review": true, "needs_layout_review": true, "layout_review_reason": "question body is a consolidated answer key (NUMBER.(LETTER) pairs) — parse it into a number→letter map, not a question", "missing_answer": true, "needs_answer_review": true, "answer_review_reason": "options + correct option not detected" } }, { "sequence_no": 89, "question_text": "
(A)\t202. (D)\t203. (A) 204. (A) 205.\t(C)\t206. (A) 207. (A) 208.\t(A) 209.\t(A) 210. (A)
", "answer_text": "", "type": "MCQ", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Normal idf8a19c05b-ParaOverride-146", "source_number": "201", "original_raw_text": "(A)\t202. (D)\t203. (A) 204. (A) 205.\t(C)\t206. (A) 207. (A) 208.\t(A) 209.\t(A) 210. (A)", "marks": 1, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Based MCQs", "section_id": "4.9", "needs_review": true, "needs_layout_review": true, "layout_review_reason": "question body is a consolidated answer key (NUMBER.(LETTER) pairs) — parse it into a number→letter map, not a question", "missing_answer": true, "needs_answer_review": true, "answer_review_reason": "options + correct option not detected" } }, { "sequence_no": 90, "question_text": "
(D) 212.\t(C) 213.\t(B)\t214.\t(C)\t215.\t(D)\t216.\t(A)
", "answer_text": "", "type": "MCQ", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Normal idf8a19c05b-ParaOverride-146", "source_number": "211", "original_raw_text": "(D) 212.\t(C) 213.\t(B)\t214.\t(C)\t215.\t(D)\t216.\t(A)", "marks": 1, "deduction_level": 0, "source_html": "Chapter9", "section": "NCERT Textbook Based MCQs", "section_id": "4.9", "needs_review": true, "needs_layout_review": true, "layout_review_reason": "question body is a consolidated answer key (NUMBER.(LETTER) pairs) — parse it into a number→letter map, not a question", "missing_answer": true, "needs_answer_review": true, "answer_review_reason": "options + correct option not detected" } } ] }, { "section_id": "4.12", "section_title": "Case Study Based Q & A", "heading_text": "Case Study Based Questions and Answers", "detected_type": "CS", "match_confidence": 0.69, "questions": [ { "sequence_no": 91, "question_text": "
\tAmines are nitrogen-containing organic compounds categorized based on the number of alkyl or aryl groups attached to the nitrogen atom. Primary amines (R-NH2) have one alkyl/aryl group, secondary amines (R2-NH) have two, and tertiary amines (R3-N) have three. Amines are further classified as alkyl or aryl amines depending on whether the substituent is an alkyl group (e.g., CH3-NH2) or an aromatic ring
(e.g., C6H5-NH2). Their structural diversity makes the key intermediates in organic synthesis.
\n
(a)\tExplain the difference between primary and secondary amines using examples.
\n
(b)\tWhy are amines considered nucleophilic in nature?
\n
(c)\tWhat type of amine is aniline, and why?
\n
(d)\tHow does the electronic effect of aryl groups affect the basicity of amines?
", "answer_text": "
(a) Primary amines have one alkyl/aryl group
e.g., (CH3-NH2), while secondary amines have two (e.g., (CH3)2-NH).
\n
(b) Due to the lone pair of electrons on the nitrogen atom, which can donate electrons.
\n
(c) Aniline (C6H5-NH2) is a primary aromatic amine as it has one aromatic group attached to nitrogen.
\n
(d) The electron-withdrawing resonance effect in aryl groups decreases the availability of the lone pair on nitrogen, reducing basicity.
", "type": "CS", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Question_S2-to-S4_Que_Casestudy_01", "marks": 0, "deduction_level": 0, "original_raw_text": "\tAmines are nitrogen-containing organic compounds categorized based on the number of alkyl or aryl groups attached to the nitrogen atom. Primary amines (R-NH2) have one alkyl/aryl group, secondary amines (R2-NH) have two, and tertiary amines (R3-N) have three. Amines are further classified as alkyl or aryl amines depending on whether the substituent is an alkyl group (e.g., CH3-NH2) or an aromatic ring (e.g., C6H5-NH2). Their structural diversity makes the key intermediates in organic synthesis.\n(a)\tExplain the difference between primary and secondary amines using examples.\n(b)\tWhy are amines ", "source_html": "Chapter9", "sub_questions": [ { "label": "(a)", "question": "Explain the difference between primary and secondary amines using examples.", "answer": "Primary amines have one alkyl/aryl group\ne.g., (CH 3 -NH 2 ), while secondary amines have two (e.g., (CH 3 ) 2 -NH)." }, { "label": "(b)", "question": "Why are amines considered nucleophilic in nature?", "answer": "Due to the lone pair of electrons on the nitrogen atom, which can donate electrons." }, { "label": "(c)", "question": "What type of amine is aniline, and why?", "answer": "Aniline (C 6 H 5 -NH 2 ) is a primary aromatic amine as it has one aromatic group attached to nitrogen." }, { "label": "(d)", "question": "How does the electronic effect of aryl groups affect the basicity of amines?", "answer": "The electron-withdrawing resonance effect in aryl groups decreases the availability of the lone pair on nitrogen, reducing basicity." } ], "section": "Case Study Based Q & A", "section_id": "4.12" } }, { "sequence_no": 92, "question_text": "
\tAmines can be prepared through various methods, such as the reduction of nitro compounds, alkylation of ammonia, and the Gabriel phthalimide synthesis. For example, nitrobenzene (C6H5-NO2) can be reduced to aniline (C6H5-NH2) using Sn/HCl or catalytic hydrogenation. The Gabriel phthalimide synthesis is specifically used for preparing primary amines using potassium phthalimide as an intermediate.
\n
(a)\tWhat is the role of Sn/HCl in the preparation of aniline from nitrobenzene?
\n
(b)\tWhy is the Gabriel phthalimide synthesis suitable only for primary amines?
\n
(c)\tWrite the chemical reaction for the reduction of nitrobenzene using Sn/HCl.
\n
(d)\tHow does catalytic hydrogenation differ from Sn/HCl reduction in terms of application?
", "answer_text": "
(a) It acts as a reducing agent to convert nitrobenzene into aniline.
\n
(b) The reaction mechanism ensures the production of a single alkyl group attached to nitrogen.
\n
(c) C6H5NO2+6[H] \"\" C6H5NH2+2H2O.
\n
(d) Catalytic hydrogenation is preferred for industrial-scale reactions due to its efficiency and cleaner by-products.
", "type": "CS", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/595.png", "position": "answer", "context": "(c) C 6 H 5 NO 2 +6[H] C 6 H 5 NH 2 +2H 2 O." } ], "tables": [], "metadata": { "source_class": "Question_S2-to-S4_Que_Casestudy_01", "marks": 0, "deduction_level": 0, "original_raw_text": "\tAmines can be prepared through various methods, such as the reduction of nitro compounds, alkylation of ammonia, and the Gabriel phthalimide synthesis. For example, nitrobenzene (C6H5-NO2) can be reduced to aniline (C6H5-NH2) using Sn/HCl or catalytic hydrogenation. The Gabriel phthalimide synthesis is specifically used for preparing primary amines using potassium phthalimide as an intermediate.\n(a)\tWhat is the role of Sn/HCl in the preparation of aniline from nitrobenzene?\n(b)\tWhy is the Gabriel phthalimide synthesis suitable only for primary amines?\n(c)\tWrite the chemical reaction for the r", "source_html": "Chapter9", "sub_questions": [ { "label": "(a)", "question": "What is the role of Sn/HCl in the preparation of aniline from nitrobenzene?", "answer": "It acts as a reducing agent to convert nitrobenzene into aniline." }, { "label": "(b)", "question": "Why is the Gabriel phthalimide synthesis suitable only for primary amines?", "answer": "The reaction mechanism ensures the production of a single alkyl group attached to nitrogen." }, { "label": "(c)", "question": "Write the chemical reaction for the reduction of nitrobenzene using Sn/HCl.", "answer": "C 6 H 5 NO 2 +6[H] C 6 H 5 NH 2 +2H 2 O." }, { "label": "(d)", "question": "How does catalytic hydrogenation differ from Sn/HCl reduction in terms of application?", "answer": "Catalytic hydrogenation is preferred for industrial-scale reactions due to its efficiency and cleaner by-products." } ], "section": "Case Study Based Q & A", "section_id": "4.12", "needs_review": true, "needs_optsplit_review": true, "optsplit_review_reason": "answer body is an option list (A/B/C/D) — options mis-routed into the answer; they belong to the question" } }, { "sequence_no": 93, "question_text": "
\tAmines are basic in nature, and their basic strength is expressed through the dissociation constant Kb or its logarithmic form pKb. The reaction can be represented as:
\n
\tRNH2 + H2O ↔ RNH3+ + OH–
\n
\tKb = [RNH+3][OH–] / [RNH2] and pKb = –logKb
\n
A higher Kb value or a smaller pKb value indicates stronger basicity. Aliphatic amines are more basic than aryl amines like aniline because the lone pair of electrons on the nitrogen atom in aniline participates in resonance with the benzene ring, reducing its availability for protonation. Substituents also influence the basicity of aniline. Electron-releasing groups increase basic strength, while electron-withdrawing groups decrease it. The effect of substituents is more pronounced at the para (p) position than at the meta (m) position. Additionally, ortho (o) substituted anilines are less basic due to the combined effects of electronic and steric hindrance, known as the ortho effect.
\n
(a)\tWhy are aliphatic amines more basic than aromatic amines like aniline?
\n
(b)\tWhat is the relationship between Kb, pKb and basic strength of amines?
\n
(c)\tHow do substituents at the para position affect the basicity of aniline derivatives?
\n
(d)\tWhat causes the ortho effect in o-substituted anilines?
", "answer_text": "
(a) The lone pair on nitrogen in aniline participates in resonance with the benzene ring, reducing its availability for protonation.
\n
(b) Higher Kb or lower pKb indicates stronger basicity.
\n
(c) Electron-releasing groups increase basicity, while electron-withdrawing groups decrease it, with a stronger effect at the para position.
\n
(d)\tThe ortho effect arises from a combination of electronic effects and steric hindrance, decreasing the basicity.
", "type": "CS", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Question_S2-to-S4_Que_Casestudy_01", "marks": 0, "deduction_level": 0, "original_raw_text": "\tAmines are basic in nature, and their basic strength is expressed through the dissociation constant Kb or its logarithmic form pKb. The reaction can be represented as:\n\tRNH2 + H2O ↔ RNH3+ + OH–\n\tKb = [RNH+3][OH–] / [RNH2] and pKb = –logKb\n A higher Kb value or a smaller pKb value indicates stronger basicity. Aliphatic amines are more basic than aryl amines like aniline because the lone pair of electrons on the nitrogen atom in aniline participates in resonance with the benzene ring, reducing its availability for protonation. Substituents also influence the basicity of aniline. Electron-releas", "source_html": "Chapter9", "sub_questions": [ { "label": "(a)", "question": "Why are aliphatic amines more basic than aromatic amines like aniline?", "answer": "The lone pair on nitrogen in aniline participates in resonance with the benzene ring, reducing its availability for protonation." }, { "label": "(b)", "question": "What is the relationship between K b , p K b and basic strength of amines?", "answer": "Higher K b or lower pK b indicates stronger basicity." }, { "label": "(c)", "question": "How do substituents at the para position affect the basicity of aniline derivatives?", "answer": "Electron-releasing groups increase basicity, while electron-withdrawing groups decrease it, with a stronger effect at the para position." }, { "label": "(d)", "question": "What causes the ortho effect in o-substituted anilines?", "answer": "The ortho effect arises from a combination of electronic effects and steric hindrance, decreasing the basicity." } ], "section": "Case Study Based Q & A", "section_id": "4.12" } }, { "sequence_no": 94, "question_text": "
\tAmines undergo diverse chemical reactions, including alkylation, acylation, and diazotization. In diazotization, primary aromatic amines react with nitrous acid to form diazonium salts, which are key intermediates in azo dye synthesis. The Carbylamine test is used to identify primary amines by producing isocyanides with a characteristic foul odour.
\n
(a)\tWhy is diazotization specific to primary aromatic amines?
\n
(b)\tWrite the chemical equation for the Carbylamine test.
\n
(c)\tWhat product is formed when aniline reacts with bromine water?
\n
(d)\tHow can diazonium salts be used in the synthesis of azo dyes?
", "answer_text": "
(a)\tOnly primary aromatic amines can form stable diazonium salts under reaction conditions.
\n
(b)\tR–NH2+CHCl3 + 3KOH \"\" R–N≡C + 3KCl
+ 3H2O
\n
(c)\t2,4,6-Tribromoaniline is formed due to electrophilic substitution at ortho and para positions.
\n
(d)\tThey react with phenols or aromatic amines to form azo compounds through electrophilic coupling.
", "type": "CS", "type_uncertain": false, "options": {}, "correct_option": null, "images": [ { "id": "img-0", "path": "Chapter9/598.png", "position": "answer", "context": "(b) R–NH 2 +CHCl 3 + 3KOH R–N ≡ C + 3KCl + 3H 2 O" } ], "tables": [], "metadata": { "source_class": "Question_S2-to-S4_Que_Casestudy_01", "marks": 0, "deduction_level": 0, "original_raw_text": "\tAmines undergo diverse chemical reactions, including alkylation, acylation, and diazotization. In diazotization, primary aromatic amines react with nitrous acid to form diazonium salts, which are key intermediates in azo dye synthesis. The Carbylamine test is used to identify primary amines by producing isocyanides with a characteristic foul odour.\n(a)\tWhy is diazotization specific to primary aromatic amines?\n(b)\tWrite the chemical equation for the Carbylamine test.\n(c)\tWhat product is formed when aniline reacts with bromine water?\n(d)\tHow can diazonium salts be used in the synthesis of azo d", "source_html": "Chapter9", "sub_questions": [ { "label": "(a)", "question": "Why is diazotization specific to primary aromatic amines?", "answer": "Only primary aromatic amines can form stable diazonium salts under reaction conditions." }, { "label": "(b)", "question": "Write the chemical equation for the Carbylamine test.", "answer": "R–NH 2 +CHCl 3 + 3KOH R–N ≡ C + 3KCl\n+ 3H 2 O" }, { "label": "(c)", "question": "What product is formed when aniline reacts with bromine water?", "answer": "2,4,6-Tribromoaniline is formed due to electrophilic substitution at ortho and para positions." }, { "label": "(d)", "question": "How can diazonium salts be used in the synthesis of azo dyes?", "answer": "They react with phenols or aromatic amines to form azo compounds through electrophilic coupling." } ], "section": "Case Study Based Q & A", "section_id": "4.12", "needs_review": true, "needs_optsplit_review": true, "optsplit_review_reason": "answer body is an option list (A/B/C/D) — options mis-routed into the answer; they belong to the question" } }, { "sequence_no": 95, "question_text": "
A pharmaceutical lab synthesizes several aromatic and aliphatic amines used in drug intermediates.
\n
\tTo optimise reaction yields, chemist study:
\n
Basicity of amines.
\n
Aromatic Vs aliphatic reactivity.
\n
Electrophilic substitution on aniline.
\n
Acylation and alkylation reaction.
\n
Distinguishing tests for amines.
\n
They perform the following experiments:
\n
\t1.\tAniline reacts with nitrous acid at 273K to give diazonium salt.
\n
\t2.\tEthylamine reacts with nitrous acid to give ethanol (clear solution)
\n
\t3.\tAniline reacts with bromine water to give 2, 4, 6 - tribromoaniline (white ppt)
\n
\t4.\tBasicity order observed (in aqueous solution)
\n
\t\tEthylamine > Ammonia > Aniline
\n
\t5.\tAcetanilide is less reactive than aniline towards bromination
\n
(a) Explain why aniline is less basic than ethylamine in aqueous solution.
\n
(b) Why does aniline react with nitrous acid to give diazonium salt, but ethylaminc give alcohol?
\n
(c) Why does aniline undergo bromination very quickly with Br2 water?
\n
(d) Why is acetanilide less reactive than aniline toward electrophilic substitution?
", "answer_text": "
(a) Basicity order is:
\n
Ethylamine > Ammonia > Aniline
\n
\tReason:
\n
In aniline, the lone pair on nitrogen is delocalised into the benzene ring through resonance.
\n
Therefore, it is less available for protonation.
\n
In ethylamine, the +I effect of the alkyl group increases electron density.
\n
(b) Different reaction with nitrous acid:
\n
Aniline (Aromatic amine):
\n
\t\tC6H5NH2 + HNO2 → C6H5N+2 Cl–
\n
Aromatic amine forms stable diazonium salt.
\n
Ethylamine (Aliphatic amine):
\n
\t\tC2H5NH2 + HNO2 → C2H5 OH + N2 + H2O
\n
Aliphatic diazonium salts are unstable.
\n
\t\tSo, the decompose → So alcohol form.
\n
(c) In Aniline, –NH2 group is strongly activating,
+M effect.
\n
Electron density increases at ortho and para positions.
\n
Br2 water reacts violently.
\n
(d) In acetanilide, –NHCOCH3 group is less reactive.
\n
Reason:
\n
Less activating
\n
Resonance reduces lone pair availability
\n
Weaker electron - donating than - NH2
", "type": "CS", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Question_S2-to-S4_Que_Casestudy_01", "marks": 0, "deduction_level": 0, "original_raw_text": " A pharmaceutical lab synthesizes several aromatic and aliphatic amines used in drug intermediates.\n\tTo optimise reaction yields, chemist study:\nBasicity of amines.\nAromatic Vs aliphatic reactivity.\nElectrophilic substitution on aniline.\nAcylation and alkylation reaction.\nDistinguishing tests for amines.\n They perform the following experiments:\n\t1.\tAniline reacts with nitrous acid at 273K to give diazonium salt.\n\t2.\tEthylamine reacts with nitrous acid to give ethanol (clear solution)\n\t3.\tAniline reacts with bromine water to give 2, 4, 6 - tribromoaniline (white ppt)\n\t4.\tBasicity order observed", "source_html": "Chapter9", "sub_questions": [ { "label": "(a)", "question": "Explain why aniline is less basic than ethylamine in aqueous solution.", "answer": "Basicity order is:\nEthylamine > Ammonia > Aniline\nReason:\nIn aniline, the lone pair on nitrogen is delocalised into the benzene ring through resonance.\nTherefore, it is less available for protonation.\nIn ethylamine, the +I effect of the alkyl group increases electron density." }, { "label": "(b)", "question": "Why does aniline react with nitrous acid to give diazonium salt, but ethylaminc give alcohol?", "answer": "Different reaction with nitrous acid:\nAniline (Aromatic amine):\nC 6 H 5 NH 2 + HNO 2 → C 6 H 5 N + 2 Cl –\nAromatic amine forms stable diazonium salt.\nEthylamine (Aliphatic amine):\nC 2 H 5 NH 2 + HNO 2 → C 2 H 5 OH + N 2 + H 2 O\nAliphatic diazonium salts are unstable.\nSo, the decompose → So alcohol form." }, { "label": "(c)", "question": "Why does aniline undergo bromination very quickly with Br 2 water?", "answer": "In Aniline, –NH 2 group is strongly activating,\n+M effect.\nElectron density increases at ortho and para positions.\nBr 2 water reacts violently." }, { "label": "(d)", "question": "Why is acetanilide less reactive than aniline toward electrophilic substitution?", "answer": "In acetanilide, –NHCOCH 3 group is less reactive.\nReason:\nLess activating\nResonance reduces lone pair availability\nWeaker electron - donating than - NH 2" } ], "section": "Case Study Based Q & A", "section_id": "4.12", "needs_review": true, "needs_layout_review": true, "layout_review_reason": "question body has 5 sequential numbered stems (1/2/3/4/5…) — a numbered run merged into one item; split per number" } }, { "sequence_no": 96, "question_text": "
Thus, electrophilic substitution slows down.
\n
A due manufacturing company uses diazonium salts to prepare azo dyes.
\n
\tTo improve the brightness of dye and its stability, they conducted the following experiment:
\n
Diazonium salt formation
\n
Coupling reaction with phenols and anilines.
\n
Stability of diazonium salts.
\n
Reduction reaction
\n
Substitution on aromatic rings via diazonium intermediates.
\n
Results:
\n
(i)\tBezenediazonium chloride is stable at 273K, but decomposes above 283K.
\n
(ii)\tIt couples with phenol to produce p-hydroxyazobenzene (orange dye)
\n
(iii)\tReduction with Sn / HCl converts diazonium salt to aniline.
\n
(iv)\tDiazonium salts can be replaced by:
\n
Br (using CuBr)
\n
CN (using CuCN)
\n
H (using hypophosphorous acid)
\n
(v)\tElectron-donating groups on phenol increases coupling rate
\n
(a) Why are diazonium salts stable only at low temperature?
\n
(b) Explain why phenol react strongly with diazonium salt in the para position.
\n
(c) Give the reaction when benzene diazonium chloride reacts with CuBr.
\n
(d) Why does reduction of diazonium salt with
Sn / HCl regenerate aniline?
", "answer_text": "
(a) Diazonium salt decompose to N2 gas at higher temperature.
\n
Low temperature (273K) prevent decomposition, stabilises N ≡ N+ bond and maintains aromatic diazonium cation.
\n
(b) Phenol has –OH group: So,
\n
Strong electron - donating (+M)
\n
Increases electron density at ortho and para location.
\n
Para position is less sterically hindered → coupling occurs predominantly at para position.
\n
(c) Sandmeyer reaction:
\n
C6H5N+2 Cl– + CuBr → C6H5Br + N2 + CuCl
\n
(d) Sn / HCl reduces diazonium group:
\n
\tC6H5N+2 Cl– → C6H5NH2
\n
\tReason:
\n
Sn / HCl donates Hydrogen
\n
Converts – N+2 into –NH2
\n
Restores aniline.
\n
Amine: Derivative of ammonia where one or more hydrogens are replaced by alkyl or aryl groups.
\n
Primary / Secondary / Tertiary Amine: Amines
containing one, two, or three organic groups attached to nitrogen (RNH2, R2NH, R3N).
\n
Quaternary Ammonium Salt: Nitrogen bonded to four organic groups forming a permanently charged cation (R4N+X–).
\n
Benzylic / Allylic / Vinylic Amine: Benzylic = attached next to benzene; allylic = next to C=C; vinylic = directly on C=C (least reactive).
\n
Basicity (of Amines): Ability of nitrogen to donate its lone pair; influenced by inductive effects, resonance, and solvation.
\n
pKb / Kb: Quantitative measure of amine basic strength; smaller pKb means a stronger base.
\n
Ammonolysis: Reaction of alkyl halides with ammonia to form amines; gives mixtures unless NH3 is in excess.
\n
Gabriel Synthesis: Method to prepare primary aliphatic amines using phthalimide alkylation followed by hydrolysis.
\n
Hofmann Bromamide Reaction: Converts amides to amines with one carbon less using Br2 and base.
\n
Reduction Methods: Conversion of nitro compounds, nitriles, or amides intoamines using reducing agents (H2/Pd, Sn/HCl, LiAlH4, etc.).
\n
Alkylation of Amines: Reaction with alkyl halides forming higher amines; may lead to quaternary salts.
\n
Acylation of Amines: Formation of amides by reacting amines with acyl chlorides or anhydrides.
\n
Hinsberg Test: Differentiates 1°, 2°, and 3° amines based on solubility patterns with benzene sulfonyl chloride.
\n
Carbylamine Test: Test for primary amines producing foul-smelling isocyanides with CHCl3 and KOH.
\n
Diazotization: Formation of diazonium salts when 1° aromatic amines react with nitrous acid in cold conditions.
\n
Diazonium Salt: Highly reactive intermediate (Ar–N+2X–) used for aromatic substitutions and dye formation.
\n
Sandmeyer Reaction: Conversion of diazonium salts to halo-/cyano-arenes using Cu(I) salts.
\n
Azo Coupling: Reaction of diazonium salts with activated aromatics to form colourful azo dyes.
\n
Electrophilic Substitution on Aniline: Aniline strongly activates the benzene ring; protection (acylation) is often required to control substitution.
\n
Solubility & Boiling Points: Low-molecular-weight amines are water-soluble due to H-bonding; boiling points lie between alcohols and alkanes.
", "type": "CS", "type_uncertain": false, "options": {}, "correct_option": null, "images": [], "tables": [], "metadata": { "source_class": "Question_S2-to-S4_Que_Casestudy_01", "marks": 0, "deduction_level": 0, "original_raw_text": " Thus, electrophilic substitution slows down.\n A due manufacturing company uses diazonium salts to prepare azo dyes.\n\tTo improve the brightness of dye and its stability, they conducted the following experiment:\nDiazonium salt formation\nCoupling reaction with phenols and anilines.\nStability of diazonium salts.\nReduction reaction\nSubstitution on aromatic rings via diazonium intermediates.\nResults:\n(i)\tBezenediazonium chloride is stable at 273K, but decomposes above 283K.\n(ii)\tIt couples with phenol to produce p-hydroxyazobenzene (orange dye)\n(iii)\tReduction with Sn / HCl converts diazonium salt ", "source_html": "Chapter9", "sub_questions": [ { "label": "(i)", "question": "Bezenediazonium chloride is stable at 273K, but decomposes above 283K.", "answer": "" }, { "label": "(ii)", "question": "It couples with phenol to produce p-hydroxyazobenzene (orange dye)", "answer": "" }, { "label": "(iii)", "question": "Reduction with Sn / HCl converts diazonium salt to aniline.", "answer": "" }, { "label": "(iv)", "question": "Diazonium salts can be replaced by:\nBr (using CuBr)\nCN (using CuCN)\nH (using hypophosphorous acid)", "answer": "" }, { "label": "(v)", "question": "Electron-donating groups on phenol increases coupling rate\n(a) Why are diazonium salts stable only at low temperature?\n(b) Explain why phenol react strongly with diazonium salt in the para position.\n(c) Give the reaction when benzene diazonium chloride reacts with CuBr.\n(d) Why does reduction of diazonium salt with\nSn / HCl regenerate aniline?", "answer": "" } ], "section": "Case Study Based Q & A", "section_id": "4.12" } } ] } ], "unassigned": [], "warnings": [ "[answer-key] 25 consolidated answer-key block(s) matched no MCQ run: 1-10, 11-20, 21-27, 1-10, 11-20, 21-30, 31-40, 41-50, 51-60, 61-70, 71-80, 81-90, 91-100, 101-110, 111-120, 121-130, 131-140, 141-150, 151-160, 161-170, 171-180, 181-190, 191-200, 201-210, 211-216 — an MCQ run may be missing its answers; see ANSWER-DETECTION.md", "Removed noise images: 49 section banners, 71 marks/year/topic badges, 24 note/clarification/puzzle callouts", "[figure] 34 figure(s) detected in the source but NOT assigned to any question: 291.png, 449.png, 450.png, 453.png, 455.png, 458.png, 463.png, 464.png … — a figure was dropped (question OR answer side); do not publish until every figure is attached", "[section] index section 'Quick Find: Previous Board Questions' (4.6) has no matching region in the chapter — verify its questions were captured", "[section] index section 'Assertion and Reason MCQs' (4.10) has no matching region in the chapter — verify its questions were captured", "[section] index section 'True and False Statement Type MCQs' (4.11) has no matching region in the chapter — verify its questions were captured", "[section] index section 'Previous Year BOARD and GUJCET Exam MCQs' (4.15) has no matching region in the chapter — verify its questions were captured", "[section] index section 'Previous Year NEET Exam MCQs' (4.16) has no matching region in the chapter — verify its questions were captured", "[section] index section 'Previous Year JEE-Main Exam MCQs' (4.17) has no matching region in the chapter — verify its questions were captured", "[section] index section 'Booster MCQs' (4.18) has no matching region in the chapter — verify its questions were captured", "[section] parsed region 'NCERT Intext Questions and Answers' (9 q) did not reconcile to any index section — unexpected/unlabelled banner", "Q#4 (Topic-wise Questions and Answers): [qa-boundary] answer has 1 content line(s) before its answer marker ('Ans. 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{\n\tbackground-color:#d8e3d6;\n\tborder-bottom-color:#76aa80;\n\tborder-bottom-style:solid;\n\tborder-bottom-width:1px;\n\tborder-left-color:#76aa80;\n\tborder-left-style:solid;\n\tborder-left-width:1px;\n\tborder-right-color:#76aa80;\n\tborder-right-style:solid;\n\tborder-right-width:1px;\n\tborder-top-color:#76aa80;\n\tborder-top-style:solid;\n\tborder-top-width:1px;\n\tpadding-bottom:5px;\n\tpadding-top:5px;\n}\ntd.CellOverride-2 {\n\tbackground-color:#eff3ee;\n\tborder-bottom-color:#76aa80;\n\tborder-bottom-style:solid;\n\tborder-bottom-width:1px;\n\tborder-left-color:#76aa80;\n\tborder-left-style:solid;\n\tborder-left-width:1px;\n\tborder-right-color:#76aa80;\n\tborder-right-style:solid;\n\tborder-right-width:1px;\n\tborder-top-color:#76aa80;\n\tborder-top-style:solid;\n\tborder-top-width:1px;\n\tpadding-bottom:5px;\n\tpadding-top:5px;\n}\ntd.CellOverride-3 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{\n\tbackground-color:#eff3ee;\n\tborder-bottom-color:#76aa80;\n\tborder-bottom-style:solid;\n\tborder-bottom-width:1px;\n\tborder-left-color:#76aa80;\n\tborder-left-style:solid;\n\tborder-left-width:1px;\n\tborder-right-color:#76aa80;\n\tborder-right-style:solid;\n\tborder-right-width:1px;\n\tborder-top-color:#76aa80;\n\tborder-top-style:solid;\n\tborder-top-width:1px;\n\tpadding-bottom:3px;\n\tpadding-top:6px;\n}\ntd.CellOverride-6 {\n\tbackground-color:#d8e3d6;\n\tborder-bottom-color:#76aa80;\n\tborder-bottom-style:solid;\n\tborder-bottom-width:1px;\n\tborder-left-color:#76aa80;\n\tborder-left-style:solid;\n\tborder-left-width:1px;\n\tborder-right-color:#76aa80;\n\tborder-right-style:solid;\n\tborder-right-width:1px;\n\tborder-top-color:#76aa80;\n\tborder-top-style:solid;\n\tborder-top-width:1px;\n\tpadding-bottom:6px;\n\tpadding-top:6px;\n}\ntd.CellOverride-7 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{\n\tborder-bottom-color:#9bbfe5;\n\tborder-bottom-style:solid;\n\tborder-bottom-width:1px;\n\tborder-left-color:#9bbfe5;\n\tborder-left-style:solid;\n\tborder-left-width:1px;\n\tborder-right-color:#9bbfe5;\n\tborder-right-style:solid;\n\tborder-right-width:1px;\n\tborder-top-color:#9bbfe5;\n\tborder-top-style:solid;\n\tborder-top-width:1px;\n\tpadding-bottom:3px;\n\tpadding-top:3px;\n\tvertical-align:middle;\n}\ntd.CellOverride-18 {\n\tbackground-color:#f3f6fc;\n\tborder-bottom-color:#9bbfe5;\n\tborder-bottom-style:solid;\n\tborder-bottom-width:1px;\n\tborder-left-color:#9bbfe5;\n\tborder-left-style:solid;\n\tborder-left-width:1px;\n\tborder-right-color:#9bbfe5;\n\tborder-right-style:solid;\n\tborder-right-width:1px;\n\tborder-top-color:#9bbfe5;\n\tborder-top-style:solid;\n\tborder-top-width:1px;\n\tpadding-bottom:6px;\n\tpadding-top:6px;\n}\ntd.CellOverride-19 {\n\tbackground-color:#f3f6fc;\n\tborder-bottom-color:#9bbfe5;\n\tborder-bottom-style:solid;\n\tborder-bottom-width:1px;\n\tborder-left-color:#9bbfe5;\n\tborder-left-style:solid;\n\tborder-left-width:1px;\n\tborder-right-color:#9bbfe5;\n\tborder-right-style:solid;\n\tborder-right-width:1px;\n\tborder-top-color:#9bbfe5;\n\tborder-top-style:solid;\n\tborder-top-width:1px;\n\tpadding-bottom:3px;\n\tpadding-top:3px;\n}\ntd.CellOverride-20 {\n\tborder-bottom-color:#000000;\n\tborder-bottom-style:solid;\n\tborder-bottom-width:1px;\n\tborder-left-color:#000000;\n\tborder-left-style:solid;\n\tborder-left-width:1px;\n\tborder-right-color:#000000;\n\tborder-right-style:solid;\n\tborder-right-width:1px;\n\tborder-top-color:#000000;\n\tborder-top-style:solid;\n\tborder-top-width:1px;\n\tpadding-bottom:5px;\n\tpadding-top:5px;\n}\np.idf8a19c05b-ParaOverride-1 {\n\tmargin-left:31px;\n\tmargin-right:3px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-2 {\n\tmargin-top:9px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-3 {\n\tmargin-top:3px;\n}\nli.idf8a19c05b-ParaOverride-4 {\n\ttext-indent:0px;\n}\np.idf8a19c05b-ParaOverride-5 {\n\tmargin-bottom:14px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-6 {\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-7 {\n\tmargin-bottom:17px;\n}\np.idf8a19c05b-ParaOverride-8 {\n\tmargin-bottom:45px;\n}\np.idf8a19c05b-ParaOverride-9 {\n\tmargin-bottom:3px;\n}\np.idf8a19c05b-ParaOverride-10 {\n\tmargin-top:0px;\n}\np.idf8a19c05b-ParaOverride-11 {\n\tmargin-left:0px;\n\tmargin-top:6px;\n\ttext-indent:0px;\n}\np.idf8a19c05b-ParaOverride-12 {\n\tmargin-left:0px;\n\ttext-align:center;\n\ttext-indent:0px;\n}\np.idf8a19c05b-ParaOverride-13 {\n\tmargin-bottom:9px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-14 {\n\tmargin-bottom:14px;\n\tmargin-top:11px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-15 {\n\tmargin-bottom:6px;\n}\np.idf8a19c05b-ParaOverride-16 {\n\tmargin-top:3px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-17 {\n\tmargin-top:3px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-18 {\n\tmargin-bottom:17px;\n\tmargin-top:6px;\n\ttext-align:right;\n}\np.idf8a19c05b-ParaOverride-19 {\n\tmargin-bottom:9px;\n\tmargin-top:3px;\n}\np.idf8a19c05b-ParaOverride-20 {\n\tmargin-bottom:28px;\n\tmargin-top:6px;\n\ttext-align:right;\n}\np.idf8a19c05b-ParaOverride-21 {\n\tmargin-bottom:54px;\n}\np.idf8a19c05b-ParaOverride-22 {\n\tmargin-bottom:0px;\n\tmargin-top:3px;\n}\np.idf8a19c05b-ParaOverride-23 {\n\tmargin-bottom:0px;\n\tmargin-top:3px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-24 {\n\tmargin-bottom:26px;\n\tmargin-left:23px;\n\tmargin-top:6px;\n\ttext-indent:-23px;\n}\np.idf8a19c05b-ParaOverride-25 {\n\tmargin-bottom:9px;\n\tmargin-left:23px;\n\ttext-align:right;\n\ttext-indent:-23px;\n}\np.idf8a19c05b-ParaOverride-26 {\n\tmargin-bottom:122px;\n\tmargin-left:23px;\n\ttext-align:right;\n\ttext-indent:-23px;\n}\np.idf8a19c05b-ParaOverride-27 {\n\tmargin-bottom:4px;\n\tmargin-top:6px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-28 {\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-29 {\n\tmargin-bottom:11px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-30 {\n\tmargin-bottom:6px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-31 {\n\tmargin-top:0px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-32 {\n\tmargin-bottom:14px;\n\tmargin-top:9px;\n}\np.idf8a19c05b-ParaOverride-33 {\n\tmargin-bottom:3px;\n\tmargin-top:9px;\n}\nli.idf8a19c05b-ParaOverride-34 {\n\tmargin-bottom:6px;\n\ttext-indent:0px;\n}\np.idf8a19c05b-ParaOverride-35 {\n\tmargin-bottom:6px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-36 {\n\tmargin-top:3px;\n\ttext-align:justify;\n\ttext-align-last:justify;\n}\np.idf8a19c05b-ParaOverride-37 {\n\tmargin-bottom:31px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-38 {\n\tmargin-bottom:74px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-39 {\n\tmargin-bottom:0px;\n\tmargin-left:0px;\n\tmargin-top:3px;\n\ttext-align:center;\n\ttext-indent:0px;\n}\np.idf8a19c05b-ParaOverride-40 {\n\tmargin-bottom:11px;\n\tmargin-top:6px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-41 {\n\tmargin-left:20px;\n\tmargin-top:6px;\n\ttext-indent:-20px;\n}\nli.idf8a19c05b-ParaOverride-42 {\n\tmargin-bottom:9px;\n\ttext-indent:0px;\n}\nli.idf8a19c05b-ParaOverride-43 {\n\tmargin-bottom:3px;\n\ttext-indent:0px;\n}\np.idf8a19c05b-ParaOverride-44 {\n\tmargin-bottom:6px;\n\tmargin-top:6px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-45 {\n\tmargin-bottom:3px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-46 {\n\tmargin-bottom:6px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-47 {\n\tmargin-bottom:6px;\n\tmargin-left:3px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-48 {\n\tmargin-top:3px;\n\ttext-align:right;\n}\np.idf8a19c05b-ParaOverride-49 {\n\ttext-align:justify;\n\ttext-align-last:justify;\n}\np.idf8a19c05b-ParaOverride-50 {\n\tmargin-left:51px;\n\ttext-indent:-51px;\n}\np.idf8a19c05b-ParaOverride-51 {\n\ttext-align:right;\n}\np.idf8a19c05b-ParaOverride-52 {\n\tmargin-top:9px;\n}\np.idf8a19c05b-ParaOverride-53 {\n\tmargin-bottom:6px;\n\tmargin-left:28px;\n}\np.idf8a19c05b-ParaOverride-54 {\n\tmargin-bottom:16px;\n\tmargin-top:3px;\n}\np.idf8a19c05b-ParaOverride-55 {\n\tmargin-bottom:9px;\n}\np.idf8a19c05b-ParaOverride-56 {\n\tmargin-bottom:0px;\n}\np.idf8a19c05b-ParaOverride-57 {\n\tmargin-bottom:26px;\n\tmargin-top:9px;\n}\np.idf8a19c05b-ParaOverride-58 {\n\tmargin-bottom:20px;\n}\np.idf8a19c05b-ParaOverride-59 {\n\tmargin-bottom:0px;\n\tmargin-left:51px;\n\tmargin-top:0px;\n\ttext-indent:-51px;\n}\np.idf8a19c05b-ParaOverride-60 {\n\tmargin-bottom:26px;\n\tmargin-top:3px;\n}\np.idf8a19c05b-ParaOverride-61 {\n\tmargin-bottom:40px;\n\tmargin-top:3px;\n}\np.idf8a19c05b-ParaOverride-62 {\n\tmargin-bottom:48px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-63 {\n\tmargin-bottom:60px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-64 {\n\tmargin-bottom:43px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-65 {\n\tmargin-bottom:45px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-66 {\n\tmargin-left:48px;\n\ttext-indent:-48px;\n}\np.idf8a19c05b-ParaOverride-67 {\n\tmargin-bottom:6px;\n\tmargin-left:48px;\n\ttext-indent:-48px;\n}\np.idf8a19c05b-ParaOverride-68 {\n\tmargin-bottom:31px;\n}\np.idf8a19c05b-ParaOverride-69 {\n\tmargin-bottom:99px;\n\tmargin-top:6px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-70 {\n\tmargin-bottom:74px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-71 {\n\tmargin-left:51px;\n\tmargin-top:0px;\n\ttext-indent:-51px;\n}\np.idf8a19c05b-ParaOverride-72 {\n\tmargin-bottom:6px;\n\tmargin-left:51px;\n\tmargin-top:0px;\n\ttext-indent:-51px;\n}\np.idf8a19c05b-ParaOverride-73 {\n\tmargin-left:48px;\n\tmargin-top:3px;\n\ttext-indent:-48px;\n}\np.idf8a19c05b-ParaOverride-74 {\n\tmargin-bottom:3px;\n\tmargin-left:48px;\n\ttext-align:right;\n\ttext-indent:-48px;\n}\np.idf8a19c05b-ParaOverride-75 {\n\tmargin-bottom:14px;\n}\np.idf8a19c05b-ParaOverride-76 {\n\tmargin-left:48px;\n\ttext-align:right;\n\ttext-indent:-48px;\n}\np.idf8a19c05b-ParaOverride-77 {\n\tmargin-bottom:201px;\n}\np.idf8a19c05b-ParaOverride-78 {\n\tmargin-bottom:51px;\n}\np.idf8a19c05b-ParaOverride-79 {\n\tmargin-top:20px;\n}\np.idf8a19c05b-ParaOverride-80 {\n\tmargin-left:0px;\n\ttext-indent:0px;\n}\np.idf8a19c05b-ParaOverride-81 {\n\tmargin-left:0px;\n\tmargin-top:3px;\n\ttext-indent:0px;\n}\np.idf8a19c05b-ParaOverride-82 {\n\tmargin-bottom:0px;\n\tmargin-top:0px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-83 {\n\tmargin-bottom:9px;\n\tmargin-top:3px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-84 {\n\tmargin-top:7px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-85 {\n\tmargin-top:6px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-86 {\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-87 {\n\tmargin-bottom:0px;\n\tmargin-left:57px;\n\tmargin-top:0px;\n\ttext-indent:-57px;\n}\np.idf8a19c05b-ParaOverride-88 {\n\tmargin-bottom:6px;\n\tmargin-top:3px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-89 {\n\tmargin-bottom:0px;\n\tmargin-top:3px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-90 {\n\tmargin-bottom:1px;\n\tmargin-top:3px;\n}\np.idf8a19c05b-ParaOverride-91 {\n\tmargin-bottom:0px;\n\tmargin-top:0px;\n}\np.idf8a19c05b-ParaOverride-92 {\n\tmargin-bottom:1px;\n\tmargin-top:1px;\n}\np.idf8a19c05b-ParaOverride-93 {\n\tmargin-top:1px;\n}\np.idf8a19c05b-ParaOverride-94 {\n\tmargin-left:48px;\n\tmargin-top:6px;\n\ttext-indent:-48px;\n}\np.idf8a19c05b-ParaOverride-95 {\n\tmargin-bottom:3px;\n\tmargin-top:10px;\n}\np.idf8a19c05b-ParaOverride-96 {\n\tmargin-bottom:3px;\n\tmargin-left:31px;\n\tmargin-top:14px;\n}\np.idf8a19c05b-ParaOverride-97 {\n\tmargin-bottom:3px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-98 {\n\tmargin-bottom:3px;\n\tmargin-top:3px;\n}\np.idf8a19c05b-ParaOverride-99 {\n\tmargin-bottom:0px;\n\tmargin-top:0px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-100 {\n\tmargin-top:0px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-101 {\n\tmargin-bottom:1px;\n\tmargin-top:3px;\n\ttext-align:center;\n}\nli.idf8a19c05b-ParaOverride-102 {\n\ttext-align:justify;\n\ttext-align-last:justify;\n\ttext-indent:0px;\n}\np.idf8a19c05b-ParaOverride-103 {\n\tmargin-bottom:1px;\n}\np.idf8a19c05b-ParaOverride-104 {\n\tmargin-bottom:6px;\n\tmargin-top:3px;\n}\np.idf8a19c05b-ParaOverride-105 {\n\tmargin-bottom:3px;\n\tmargin-top:9px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-106 {\n\tmargin-bottom:6px;\n\tmargin-top:9px;\n\ttext-align:center;\n}\np.idf8a19c05b-ParaOverride-107 {\n\tmargin-bottom:0px;\n\tmargin-top:11px;\n}\np.idf8a19c05b-ParaOverride-108 {\n\tmargin-bottom:0px;\n\tmargin-top:6px;\n}\np.idf8a19c05b-ParaOverride-109 {\n\tmargin-bottom:3px;\n\tmargin-top:1px;\n}\np.idf8a19c05b-ParaOverride-110 {\n\tmargin-bottom:7px;\n\tmargin-top:6px;\n\ttext-align:left;\n}\np.idf8a19c05b-ParaOverride-111 {\n\tmargin-left:51px;\n\tmargin-top:3px;\n\ttext-indent:-51px;\n}\np.idf8a19c05b-ParaOverride-112 {\n\tmargin-left:51px;\n\tmargin-top:3px;\n\ttext-align:right;\n\ttext-indent:-51px;\n}\np.idf8a19c05b-ParaOverride-113 {\n\tmargin-bottom:128px;\n\tmargin-top:3px;\n}\np.idf8a19c05b-ParaOverride-114 {\n\tmargin-left:51px;\n\tmargin-top:0px;\n\ttext-align:right;\n\ttext-indent:-51px;\n}\np.idf8a19c05b-ParaOverride-115 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skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:17.58px;\n\tz-index:0;\n}\n#_idContainer003, #_idContainer172, #_idContainer218, #_idContainer355, #_idContainer696 {\n\t-ms-transform:translate(3.244px,10.458px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(3.244px,10.458px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:9.41px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(3.244px,10.458px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(3.244px,10.458px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:11.09px;\n\tz-index:1;\n}\n#_idContainer004, #_idContainer173, #_idContainer219, #_idContainer356, #_idContainer697 {\n\t-ms-transform:translate(6.062px,3.121px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(6.062px,3.121px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.46px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(6.062px,3.121px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(6.062px,3.121px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:17.58px;\n\tz-index:1;\n}\n#_idContainer005, #_idContainer174, #_idContainer220, #_idContainer357, #_idContainer698 {\n\t-ms-transform:translate(0.000px,-0.001px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,-0.001px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:29.70px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,-0.001px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,-0.001px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:29.70px;\n\tz-index:1;\n}\n#_idContainer006 {\n\t-ms-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.95px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:267.58px;\n\tz-index:0;\n}\n#_idContainer007 {\n\t-ms-transform:translate(122.054px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(122.054px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:29.70px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(122.054px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(122.054px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:274.63px;\n\tz-index:1;\n}\n#_idContainer008, #_idContainer177, #_idContainer223, #_idContainer360, #_idContainer701 {\n\tdisplay:inline-block;\n\theight:38px;\n\tposition:relative;\n\twidth:519px;\n}\n#_idContainer175 {\n\t-ms-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.95px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:284.30px;\n\tz-index:0;\n}\n#_idContainer176 {\n\t-ms-transform:translate(113.692px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(113.692px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:29.70px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(113.692px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(113.692px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:291.35px;\n\tz-index:1;\n}\n#_idContainer221 {\n\t-ms-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.95px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:366.13px;\n\tz-index:0;\n}\n#_idContainer222 {\n\t-ms-transform:translate(72.779px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(72.779px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:29.70px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(72.779px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(72.779px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:373.18px;\n\tz-index:1;\n}\n#_idContainer358 {\n\t-ms-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.95px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:264.10px;\n\tz-index:0;\n}\n#_idContainer359 {\n\t-ms-transform:translate(123.792px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(123.792px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:29.70px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(123.792px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(123.792px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:271.16px;\n\tz-index:1;\n}\n#_idContainer524 {\n\t-ms-transform:translate(0.000px,9.609px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,9.609px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:392.30px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,9.609px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,9.609px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:512.74px;\n\tz-index:0;\n}\n#_idContainer525 {\n\t-ms-transform:translate(7.370px,26.220px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(7.370px,26.220px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:371.14px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(7.370px,26.220px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(7.370px,26.220px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:504.00px;\n\tz-index:2;\n}\n#_idContainer526 {\n\t-ms-transform:translate(229.731px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(229.731px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:20.30px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(229.731px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(229.731px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:59.53px;\n\tz-index:1;\n}\n#_idContainer527 {\n\tdisplay:inline-block;\n\theight:408px;\n\tposition:relative;\n\twidth:519px;\n}\n#_idContainer528 {\n\t-ms-transform:translate(0.000px,11.175px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,11.175px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:0.00px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,11.175px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,11.175px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:517.74px;\n\tz-index:0;\n}\n#_idContainer529 {\n\t-ms-transform:translate(202.677px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(202.677px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:22.85px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(202.677px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(202.677px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:113.39px;\n\tz-index:1;\n}\n#_idContainer530 {\n\tdisplay:inline-block;\n\theight:23px;\n\tposition:relative;\n\twidth:519px;\n}\n#_idContainer682 {\n\tdisplay:inline-block;\n\theight:675px;\n\tposition:relative;\n\twidth:0px;\n}\n#_idContainer683, #_idContainer685, #_idContainer687, #_idContainer689, #_idContainer692 {\n\tdisplay:inline-block;\n\theight:708px;\n\tposition:relative;\n\twidth:0px;\n}\n#_idContainer684, #_idContainer686, #_idContainer688, #_idContainer691 {\n\tdisplay:inline-block;\n\theight:707px;\n\tposition:relative;\n\twidth:0px;\n}\n#_idContainer699 {\n\t-ms-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.95px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(7.051px,2.771px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:313.22px;\n\tz-index:0;\n}\n#_idContainer700 {\n\t-ms-transform:translate(99.236px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(99.236px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:29.70px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(99.236px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(99.236px,2.898px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:320.27px;\n\tz-index:1;\n}\n#_idContainer711 {\n\tdisplay:inline-block;\n\theight:397px;\n\tposition:relative;\n\twidth:0px;\n}\n#_idContainer712 {\n\t-ms-transform:translate(0.000px,11.338px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,11.338px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:470.26px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,11.338px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,11.338px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:517.74px;\n\tz-index:0;\n}\n#_idContainer713 {\n\t-ms-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.95px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:94.02px;\n\tz-index:0;\n}\n#_idContainer714 {\n\t-ms-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:17.69px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:17.69px;\n\tz-index:0;\n}\n#_idContainer715 {\n\t-ms-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:15.55px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:11.65px;\n\tz-index:0;\n}\n#_idContainer716 {\n\t-ms-transform:translate(2.150px,6.932px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(2.150px,6.932px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:6.24px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(2.150px,6.932px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(2.150px,6.932px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:7.35px;\n\tz-index:1;\n}\n#_idContainer717 {\n\t-ms-transform:translate(4.018px,2.069px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(4.018px,2.069px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:15.55px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(4.018px,2.069px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(4.018px,2.069px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:11.65px;\n\tz-index:1;\n}\n#_idContainer718 {\n\t-ms-transform:translate(4.655px,2.334px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(4.655px,2.334px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:19.69px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(4.655px,2.334px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(4.655px,2.334px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:19.69px;\n\tz-index:1;\n}\n#_idContainer719 {\n\t-ms-transform:translate(213.068px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(213.068px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.95px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(213.068px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(213.068px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:94.02px;\n\tz-index:1;\n}\n#_idContainer720 {\n\t-ms-transform:translate(259.370px,37.145px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(259.370px,37.145px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:434.73px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(259.370px,37.145px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(259.370px,37.145px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:0.00px;\n\tz-index:2;\n}\n#_idContainer721 {\n\tdisplay:inline-block;\n\theight:483px;\n\tposition:relative;\n\twidth:519px;\n}\n#_idContainer722 {\n\t-ms-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:39.69px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:39.69px;\n\tz-index:0;\n}\n#_idContainer723 {\n\t-ms-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:27.44px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:27.25px;\n\tz-index:0;\n}\n#_idContainer724 {\n\t-ms-transform:translate(11.049px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(11.049px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.26px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(11.049px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(11.049px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:10.15px;\n\tz-index:2;\n}\n#_idContainer725 {\n\t-ms-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.26px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:10.15px;\n\tz-index:0;\n}\n#_idContainer726 {\n\t-ms-transform:translate(10.693px,3.197px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(10.693px,3.197px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:16.30px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(10.693px,3.197px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(10.693px,3.197px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:8.25px;\n\tz-index:3;\n}\n#_idContainer727 {\n\t-ms-transform:translate(0.753px,3.197px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.753px,3.197px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:16.30px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.753px,3.197px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.753px,3.197px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:8.25px;\n\tz-index:1;\n}\n#_idContainer728 {\n\t-ms-transform:translate(3.023px,2.091px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(3.023px,2.091px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:23.26px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(3.023px,2.091px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(3.023px,2.091px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:21.20px;\n\tz-index:1;\n}\n#_idContainer729 {\n\t-ms-transform:translate(6.218px,5.984px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(6.218px,5.984px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:27.44px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(6.218px,5.984px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(6.218px,5.984px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:27.25px;\n\tz-index:1;\n}\n#_idContainer730 {\n\t-ms-transform:translate(0.000px,417.429px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,417.429px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:39.69px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,417.429px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,417.429px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:39.69px;\n\tz-index:1;\n}\n#_idContainer731 {\n\t-ms-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:30.05px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:117.82px;\n\tz-index:0;\n}\n#_idContainer732 {\n\t-ms-transform:translate(20.143px,6.586px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(20.143px,6.586px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:18.66px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(20.143px,6.586px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(20.143px,6.586px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:91.98px;\n\tz-index:1;\n}\n#_idContainer733 {\n\t-ms-transform:translate(9.637px,397.587px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(9.637px,397.587px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:30.05px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(9.637px,397.587px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(9.637px,397.587px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:117.82px;\n\tz-index:0;\n}\n#_idContainer734 {\n\t-ms-transform:translate(50.781px,404.882px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(50.781px,404.882px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:60.19px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(50.781px,404.882px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(50.781px,404.882px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:50.56px;\n\tz-index:3;\n}\n#_idContainer743 {\n\t-ms-transform:translate(50.781px,689.766px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(50.781px,689.766px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:309.25px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(50.781px,689.766px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(50.781px,689.766px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:227.81px;\n\tz-index:11;\n}\n#_idContainer745 {\n\t-ms-transform:translate(54.445px,246.614px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(54.445px,246.614px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:25.93px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(54.445px,246.614px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(54.445px,246.614px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:245.61px;\n\tz-index:7;\n}\n#_idContainer746 {\n\t-ms-transform:translate(56.287px,319.438px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(56.287px,319.438px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:21.96px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(56.287px,319.438px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(56.287px,319.438px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:54.37px;\n\tz-index:8;\n}\n#_idContainer747 {\n\t-ms-transform:translate(68.843px,264.066px) rotate(180.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(68.843px,264.066px) rotate(180.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:16.45px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(68.843px,264.066px) rotate(180.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(68.843px,264.066px) rotate(180.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 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0%;\n\theight:16.26px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(82.624px,404.382px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\ttransform:translate(82.624px,404.382px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:0.00px;\n\tz-index:14;\n}\n#_idContainer750 {\n\t-ms-transform:translate(119.096px,420.637px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(119.096px,420.637px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:35.72px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(119.096px,420.637px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(119.096px,420.637px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 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scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:42.32px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(154.502px,289.264px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(154.502px,289.264px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:1.00px;\n\tz-index:9;\n}\n#_idContainer760 {\n\t-ms-transform:translate(187.035px,257.952px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(187.035px,257.952px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:310.29px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(187.035px,257.952px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(187.035px,257.952px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:256.95px;\n\tz-index:31;\n}\n#_idContainer761 {\n\t-ms-transform:translate(197.822px,319.938px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(197.822px,319.938px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:46.42px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(197.822px,319.938px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(197.822px,319.938px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:50.56px;\n\tz-index:24;\n}\n#_idContainer762 {\n\t-ms-transform:translate(238.151px,347.942px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(238.151px,347.942px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:202.39px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(238.151px,347.942px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(238.151px,347.942px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:44.29px;\n\tz-index:25;\n}\n#_idContainer763 {\n\t-ms-transform:translate(245.238px,289.264px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(245.238px,289.264px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:106.23px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(245.238px,289.264px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(245.238px,289.264px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:1.00px;\n\tz-index:32;\n}\n#_idContainer764 {\n\t-ms-transform:translate(352.469px,321.801px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(352.469px,321.801px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:21.96px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(352.469px,321.801px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(352.469px,321.801px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:45.40px;\n\tz-index:34;\n}\n#_idContainer765 {\n\t-ms-transform:translate(364.949px,275.404px) rotate(180.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(364.949px,275.404px) rotate(180.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:16.45px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(364.949px,275.404px) rotate(180.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(364.949px,275.404px) rotate(180.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:1.00px;\n\tz-index:35;\n}\n#_idContainer766 {\n\t-ms-transform:translate(370.188px,469.825px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(370.188px,469.825px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:21.45px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(370.188px,469.825px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(370.188px,469.825px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:46.19px;\n\tz-index:12;\n}\n#_idContainer767 {\n\t-ms-transform:translate(382.414px,402.049px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(382.414px,402.049px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:19.59px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(382.414px,402.049px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\ttransform:translate(382.414px,402.049px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:1.00px;\n\tz-index:15;\n}\n#_idContainer768 {\n\t-ms-transform:translate(422.960px,464.293px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(422.960px,464.293px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:29.32px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(422.960px,464.293px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(422.960px,464.293px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:1.00px;\n\tz-index:17;\n}\n#_idContainer769 {\n\t-ms-transform:translate(403.374px,404.441px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(403.374px,404.441px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:89.55px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(403.374px,404.441px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(403.374px,404.441px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:128.27px;\n\tz-index:26;\n}\n#_idContainer770 {\n\t-ms-transform:translate(415.107px,396.757px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(415.107px,396.757px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:69.90px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(415.107px,396.757px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(415.107px,396.757px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:113.39px;\n\tz-index:27;\n}\n#_idContainer772 {\n\t-ms-transform:translate(422.960px,689.766px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(422.960px,689.766px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:68.97px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(422.960px,689.766px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(422.960px,689.766px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:239.54px;\n\tz-index:16;\n}\n#_idContainer773 {\n\t-ms-transform:translate(633.334px,402.049px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(633.334px,402.049px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:18.45px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(633.334px,402.049px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(633.334px,402.049px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:0.00px;\n\tz-index:36;\n}\n#_idContainer774 {\n\t-ms-transform:translate(616.431px,471.639px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(616.431px,471.639px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:32.31px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(616.431px,471.639px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(616.431px,471.639px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:50.37px;\n\tz-index:18;\n}\n#_idContainer775 {\n\t-ms-transform:translate(634.084px,402.549px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(634.084px,402.549px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:17.22px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(634.084px,402.549px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\ttransform:translate(634.084px,402.549px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:1.00px;\n\tz-index:19;\n}\n#_idContainer776 {\n\t-ms-transform:translate(662.021px,444.952px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(662.021px,444.952px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:11.78px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(662.021px,444.952px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(662.021px,444.952px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:1.00px;\n\tz-index:23;\n}\n#_idContainer781 {\n\t-ms-transform:translate(662.021px,687.451px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(662.021px,687.451px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:160.06px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(662.021px,687.451px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(662.021px,687.451px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:323.57px;\n\tz-index:20;\n}\n#_idContainer782 {\n\t-ms-transform:translate(792.519px,170.290px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(792.519px,170.290px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:52.54px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(792.519px,170.290px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(792.519px,170.290px) rotate(90.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:1.00px;\n\tz-index:22;\n}\n#_idContainer783 {\n\t-ms-transform:translate(739.479px,171.290px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(739.479px,171.290px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:190.59px;\n\tleft:0px;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(739.479px,171.290px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\ttransform:translate(739.479px,171.290px) rotate(180.000deg) skew(0.000deg) scale(1.000,-1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:0.00px;\n\tz-index:37;\n}\n#_idContainer786 {\n\t-ms-transform:translate(792.519px,333.573px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(792.519px,333.573px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:316.88px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(792.519px,333.573px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(792.519px,333.573px) rotate(270.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:323.57px;\n\tz-index:21;\n}\n#_idContainer787 {\n\tdisplay:inline-block;\n\theight:690px;\n\tposition:relative;\n\twidth:1110px;\n}\n#_idContainer788 {\n\t-ms-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:27.63px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,0.000px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:517.61px;\n\tz-index:0;\n}\n#_idContainer789 {\n\t-ms-transform:translate(0.000px,38.534px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-ms-transform-origin:0% 0%;\n\t-webkit-transform:translate(0.000px,38.534px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\t-webkit-transform-origin:0% 0%;\n\theight:670.13px;\n\tleft:0px;\n\toverflow:hidden;\n\tposition:absolute;\n\ttop:0px;\n\ttransform:translate(0.000px,38.534px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform:translate(0.000px,38.534px) rotate(0.000deg) skew(0.000deg) scale(1.000,1.000);\n\ttransform-origin:0% 0%;\n\ttransform-origin:0% 0%;\n\twidth:518.74px;\n\tz-index:1;\n}\n#_idContainer790 {\n\tdisplay:inline-block;\n\theight:709px;\n\tposition:relative;\n\twidth:519px;\n}\nimg._idGenObjectAttribute-1 {\n\theight:100.00%;\n\tmin-width:100%;\n\twidth:100.00%;\n}\nimg._idGenObjectAttribute-2 {\n\theight:24px;\n\twidth:253px;\n}\nimg._idGenObjectAttribute-3 {\n\theight:17px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-4 {\n\theight:37px;\n\twidth:42px;\n}\nimg._idGenObjectAttribute-5 {\n\theight:17px;\n\twidth:34px;\n}\nimg._idGenObjectAttribute-6 {\n\theight:126px;\n\twidth:171px;\n}\nimg._idGenObjectAttribute-7 {\n\theight:43px;\n\twidth:60px;\n}\nimg._idGenObjectAttribute-8 {\n\theight:17px;\n\twidth:75px;\n}\nimg._idGenObjectAttribute-9 {\n\theight:37px;\n\twidth:82px;\n}\nimg._idGenObjectAttribute-10 {\n\theight:57px;\n\twidth:120px;\n}\nimg._idGenObjectAttribute-11 {\n\theight:17px;\n\twidth:79px;\n}\nimg._idGenObjectAttribute-12 {\n\theight:36px;\n\twidth:94px;\n}\nimg._idGenObjectAttribute-13 {\n\theight:39px;\n\twidth:78px;\n}\nimg._idGenObjectAttribute-14 {\n\theight:46px;\n\twidth:153px;\n}\nimg._idGenObjectAttribute-15 {\n\theight:27px;\n\twidth:101px;\n}\nimg._idGenObjectAttribute-16 {\n\theight:54px;\n\twidth:30px;\n}\nimg._idGenObjectAttribute-17 {\n\theight:54px;\n\twidth:55px;\n}\nimg._idGenObjectAttribute-18 {\n\theight:54px;\n\twidth:47px;\n}\nimg._idGenObjectAttribute-19 {\n\theight:38px;\n\twidth:55px;\n}\nimg._idGenObjectAttribute-20 {\n\theight:34px;\n\twidth:47px;\n}\nimg._idGenObjectAttribute-21 {\n\theight:39px;\n\twidth:180px;\n}\nimg._idGenObjectAttribute-22 {\n\theight:13px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-23 {\n\theight:54px;\n\twidth:198px;\n}\nimg._idGenObjectAttribute-24 {\n\theight:66px;\n\twidth:221px;\n}\nimg._idGenObjectAttribute-25 {\n\theight:35px;\n\twidth:200px;\n}\nimg._idGenObjectAttribute-26 {\n\theight:38px;\n\twidth:89px;\n}\nimg._idGenObjectAttribute-27 {\n\theight:30px;\n\twidth:56px;\n}\nimg._idGenObjectAttribute-28 {\n\theight:38px;\n\twidth:82px;\n}\nimg._idGenObjectAttribute-29 {\n\theight:30px;\n\twidth:58px;\n}\nimg._idGenObjectAttribute-30 {\n\theight:38px;\n\twidth:54px;\n}\nimg._idGenObjectAttribute-31 {\n\theight:40px;\n\twidth:79px;\n}\nimg._idGenObjectAttribute-32 {\n\theight:63px;\n\twidth:196px;\n}\nimg._idGenObjectAttribute-33 {\n\theight:292px;\n\twidth:522px;\n}\nimg._idGenObjectAttribute-34 {\n\theight:13px;\n\twidth:77px;\n}\nimg._idGenObjectAttribute-35 {\n\theight:89px;\n\twidth:224px;\n}\nimg._idGenObjectAttribute-36 {\n\theight:13px;\n\twidth:119px;\n}\nimg._idGenObjectAttribute-37 {\n\theight:169px;\n\twidth:225px;\n}\nimg._idGenObjectAttribute-38 {\n\theight:141px;\n\twidth:153px;\n}\nimg._idGenObjectAttribute-39 {\n\theight:13px;\n\twidth:78px;\n}\nimg._idGenObjectAttribute-40 {\n\theight:62px;\n\twidth:223px;\n}\nimg._idGenObjectAttribute-41 {\n\theight:40px;\n\twidth:134px;\n}\nimg._idGenObjectAttribute-42 {\n\theight:130px;\n\twidth:174px;\n}\nimg._idGenObjectAttribute-43 {\n\theight:377px;\n\twidth:256px;\n}\nimg._idGenObjectAttribute-44 {\n\theight:314px;\n\twidth:256px;\n}\nimg._idGenObjectAttribute-45 {\n\theight:79px;\n\twidth:165px;\n}\nimg._idGenObjectAttribute-46 {\n\theight:111px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-47 {\n\theight:101px;\n\twidth:204px;\n}\nimg._idGenObjectAttribute-48 {\n\theight:31px;\n\twidth:195px;\n}\nimg._idGenObjectAttribute-49 {\n\theight:13px;\n\twidth:73px;\n}\nimg._idGenObjectAttribute-50 {\n\theight:54px;\n\twidth:150px;\n}\nimg._idGenObjectAttribute-51 {\n\theight:53px;\n\twidth:149px;\n}\nimg._idGenObjectAttribute-52 {\n\theight:97px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-53 {\n\theight:53px;\n\twidth:116px;\n}\nimg._idGenObjectAttribute-54 {\n\theight:157px;\n\twidth:232px;\n}\nimg._idGenObjectAttribute-55 {\n\theight:75px;\n\twidth:112px;\n}\nimg._idGenObjectAttribute-56 {\n\theight:161px;\n\twidth:256px;\n}\nimg._idGenObjectAttribute-57 {\n\theight:152px;\n\twidth:256px;\n}\nimg._idGenObjectAttribute-58 {\n\theight:54px;\n\twidth:209px;\n}\nimg._idGenObjectAttribute-59 {\n\theight:17px;\n\twidth:38px;\n}\nimg._idGenObjectAttribute-60 {\n\theight:123px;\n\twidth:217px;\n}\nimg._idGenObjectAttribute-61 {\n\theight:134px;\n\twidth:218px;\n}\nimg._idGenObjectAttribute-62 {\n\theight:118px;\n\twidth:218px;\n}\nimg._idGenObjectAttribute-63 {\n\theight:50px;\n\twidth:249px;\n}\nimg._idGenObjectAttribute-64 {\n\theight:13px;\n\twidth:122px;\n}\nimg._idGenObjectAttribute-65 {\n\theight:165px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-66 {\n\theight:13px;\n\twidth:192px;\n}\nimg._idGenObjectAttribute-67 {\n\theight:19px;\n\twidth:33px;\n}\nimg._idGenObjectAttribute-68 {\n\theight:53px;\n\twidth:180px;\n}\nimg._idGenObjectAttribute-69 {\n\theight:137px;\n\twidth:171px;\n}\nimg._idGenObjectAttribute-70 {\n\theight:13px;\n\twidth:80px;\n}\nimg._idGenObjectAttribute-71 {\n\theight:22px;\n\twidth:111px;\n}\nimg._idGenObjectAttribute-72 {\n\theight:22px;\n\twidth:50px;\n}\nimg._idGenObjectAttribute-73 {\n\theight:84px;\n\twidth:219px;\n}\nimg._idGenObjectAttribute-74 {\n\theight:124px;\n\twidth:232px;\n}\nimg._idGenObjectAttribute-75 {\n\theight:115px;\n\twidth:197px;\n}\nimg._idGenObjectAttribute-76 {\n\theight:90px;\n\twidth:237px;\n}\nimg._idGenObjectAttribute-77 {\n\theight:200px;\n\twidth:249px;\n}\nimg._idGenObjectAttribute-78 {\n\theight:47px;\n\twidth:204px;\n}\nimg._idGenObjectAttribute-79 {\n\theight:91px;\n\twidth:247px;\n}\nimg._idGenObjectAttribute-80 {\n\theight:165px;\n\twidth:241px;\n}\nimg._idGenObjectAttribute-81 {\n\theight:189px;\n\twidth:231px;\n}\nimg._idGenObjectAttribute-82 {\n\theight:22px;\n\twidth:19px;\n}\nimg._idGenObjectAttribute-83 {\n\theight:29px;\n\twidth:52px;\n}\nimg._idGenObjectAttribute-84 {\n\theight:29px;\n\twidth:67px;\n}\nimg._idGenObjectAttribute-85 {\n\theight:150px;\n\twidth:177px;\n}\nimg._idGenObjectAttribute-86 {\n\theight:38px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-87 {\n\theight:21px;\n\twidth:62px;\n}\nimg._idGenObjectAttribute-88 {\n\theight:16px;\n\twidth:12px;\n}\nimg._idGenObjectAttribute-89 {\n\theight:12px;\n\twidth:8px;\n}\nimg._idGenObjectAttribute-90 {\n\theight:12px;\n\twidth:10px;\n}\nimg._idGenObjectAttribute-91 {\n\theight:15px;\n\twidth:21px;\n}\nimg._idGenObjectAttribute-92 {\n\theight:16px;\n\twidth:10px;\n}\nimg._idGenObjectAttribute-93 {\n\theight:64px;\n\twidth:202px;\n}\nimg._idGenObjectAttribute-94 {\n\theight:66px;\n\twidth:209px;\n}\nimg._idGenObjectAttribute-95 {\n\theight:15px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-96 {\n\theight:140px;\n\twidth:202px;\n}\nimg._idGenObjectAttribute-97 {\n\theight:13px;\n\twidth:85px;\n}\nimg._idGenObjectAttribute-98 {\n\theight:96px;\n\twidth:211px;\n}\nimg._idGenObjectAttribute-99 {\n\theight:91px;\n\twidth:207px;\n}\nimg._idGenObjectAttribute-100 {\n\theight:55px;\n\twidth:244px;\n}\nimg._idGenObjectAttribute-101 {\n\theight:120px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-102 {\n\theight:54px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-103 {\n\theight:38px;\n\twidth:253px;\n}\nimg._idGenObjectAttribute-104 {\n\theight:14px;\n\twidth:77px;\n}\nimg._idGenObjectAttribute-105 {\n\theight:11px;\n\twidth:40px;\n}\nimg._idGenObjectAttribute-106 {\n\theight:20px;\n\twidth:67px;\n}\nimg._idGenObjectAttribute-107 {\n\theight:11px;\n\twidth:46px;\n}\nimg._idGenObjectAttribute-108 {\n\theight:21px;\n\twidth:64px;\n}\nimg._idGenObjectAttribute-109 {\n\theight:11px;\n\twidth:39px;\n}\nimg._idGenObjectAttribute-110 {\n\theight:20px;\n\twidth:65px;\n}\nimg._idGenObjectAttribute-111 {\n\theight:11px;\n\twidth:45px;\n}\nimg._idGenObjectAttribute-112 {\n\theight:36px;\n\twidth:95px;\n}\nimg._idGenObjectAttribute-113 {\n\theight:124px;\n\twidth:522px;\n}\nimg._idGenObjectAttribute-114 {\n\theight:55px;\n\twidth:62px;\n}\nimg._idGenObjectAttribute-115 {\n\theight:54px;\n\twidth:78px;\n}\nimg._idGenObjectAttribute-116 {\n\theight:18px;\n\twidth:80px;\n}\nimg._idGenObjectAttribute-117 {\n\theight:54px;\n\twidth:62px;\n}\nimg._idGenObjectAttribute-118 {\n\theight:52px;\n\twidth:81px;\n}\nimg._idGenObjectAttribute-119 {\n\theight:18px;\n\twidth:76px;\n}\nimg._idGenObjectAttribute-120 {\n\theight:41px;\n\twidth:137px;\n}\nimg._idGenObjectAttribute-121 {\n\theight:55px;\n\twidth:164px;\n}\nimg._idGenObjectAttribute-122 {\n\theight:60px;\n\twidth:114px;\n}\nimg._idGenObjectAttribute-123 {\n\theight:81px;\n\twidth:164px;\n}\nimg._idGenObjectAttribute-124 {\n\theight:56px;\n\twidth:156px;\n}\nimg._idGenObjectAttribute-125 {\n\theight:56px;\n\twidth:176px;\n}\nimg._idGenObjectAttribute-126 {\n\theight:56px;\n\twidth:175px;\n}\nimg._idGenObjectAttribute-127 {\n\theight:14px;\n\twidth:122px;\n}\nimg._idGenObjectAttribute-128 {\n\theight:60px;\n\twidth:223px;\n}\nimg._idGenObjectAttribute-129 {\n\theight:113px;\n\twidth:219px;\n}\nimg._idGenObjectAttribute-130 {\n\theight:94px;\n\twidth:212px;\n}\nimg._idGenObjectAttribute-131 {\n\theight:14px;\n\twidth:114px;\n}\nimg._idGenObjectAttribute-132 {\n\theight:18px;\n\twidth:114px;\n}\nimg._idGenObjectAttribute-133 {\n\theight:33px;\n\twidth:204px;\n}\nimg._idGenObjectAttribute-134 {\n\theight:38px;\n\twidth:206px;\n}\nimg._idGenObjectAttribute-135 {\n\theight:18px;\n\twidth:75px;\n}\nimg._idGenObjectAttribute-136 {\n\theight:276px;\n\twidth:232px;\n}\nimg._idGenObjectAttribute-137 {\n\theight:209px;\n\twidth:201px;\n}\nimg._idGenObjectAttribute-138 {\n\theight:54px;\n\twidth:208px;\n}\nimg._idGenObjectAttribute-139 {\n\theight:34px;\n\twidth:207px;\n}\nimg._idGenObjectAttribute-140 {\n\theight:38px;\n\twidth:209px;\n}\nimg._idGenObjectAttribute-141 {\n\theight:13px;\n\twidth:89px;\n}\nimg._idGenObjectAttribute-142 {\n\theight:68px;\n\twidth:185px;\n}\nimg._idGenObjectAttribute-143 {\n\theight:67px;\n\twidth:195px;\n}\nimg._idGenObjectAttribute-144 {\n\theight:82px;\n\twidth:197px;\n}\nimg._idGenObjectAttribute-145 {\n\theight:84px;\n\twidth:204px;\n}\nimg._idGenObjectAttribute-146 {\n\theight:14px;\n\twidth:73px;\n}\nimg._idGenObjectAttribute-147 {\n\theight:16px;\n\twidth:19px;\n}\nimg._idGenObjectAttribute-148 {\n\theight:33px;\n\twidth:105px;\n}\nimg._idGenObjectAttribute-149 {\n\theight:69px;\n\twidth:209px;\n}\nimg._idGenObjectAttribute-150 {\n\theight:22px;\n\twidth:84px;\n}\nimg._idGenObjectAttribute-151 {\n\theight:22px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-152 {\n\theight:21px;\n\twidth:65px;\n}\nimg._idGenObjectAttribute-153 {\n\theight:95px;\n\twidth:218px;\n}\nimg._idGenObjectAttribute-154 {\n\theight:22px;\n\twidth:74px;\n}\nimg._idGenObjectAttribute-155 {\n\theight:16px;\n\twidth:24px;\n}\nimg._idGenObjectAttribute-156 {\n\theight:13px;\n\twidth:121px;\n}\nimg._idGenObjectAttribute-157 {\n\theight:30px;\n\twidth:212px;\n}\nimg._idGenObjectAttribute-158 {\n\theight:5px;\n\twidth:27px;\n}\nimg._idGenObjectAttribute-159 {\n\theight:5px;\n\twidth:31px;\n}\nimg._idGenObjectAttribute-160 {\n\theight:89px;\n\twidth:244px;\n}\nimg._idGenObjectAttribute-161 {\n\theight:157px;\n\twidth:190px;\n}\nimg._idGenObjectAttribute-162 {\n\theight:13px;\n\twidth:41px;\n}\nimg._idGenObjectAttribute-163 {\n\theight:13px;\n\twidth:39px;\n}\nimg._idGenObjectAttribute-164 {\n\theight:17px;\n\twidth:122px;\n}\nimg._idGenObjectAttribute-165 {\n\theight:15px;\n\twidth:126px;\n}\nimg._idGenObjectAttribute-166 {\n\theight:22px;\n\twidth:62px;\n}\nimg._idGenObjectAttribute-167 {\n\theight:34px;\n\twidth:74px;\n}\nimg._idGenObjectAttribute-168 {\n\theight:22px;\n\twidth:60px;\n}\nimg._idGenObjectAttribute-169 {\n\theight:51px;\n\twidth:343px;\n}\nimg._idGenObjectAttribute-170 {\n\theight:23px;\n\twidth:48px;\n}\nimg._idGenObjectAttribute-171 {\n\theight:12px;\n\twidth:55px;\n}\nimg._idGenObjectAttribute-172 {\n\theight:23px;\n\twidth:43px;\n}\nimg._idGenObjectAttribute-173 {\n\theight:119px;\n\twidth:370px;\n}\nimg._idGenObjectAttribute-174 {\n\theight:86px;\n\twidth:465px;\n}\nimg._idGenObjectAttribute-175 {\n\theight:91px;\n\twidth:328px;\n}\nimg._idGenObjectAttribute-176 {\n\theight:19px;\n\twidth:48px;\n}\nimg._idGenObjectAttribute-177 {\n\theight:20px;\n\twidth:73px;\n}\nimg._idGenObjectAttribute-178 {\n\theight:20px;\n\twidth:47px;\n}\nimg._idGenObjectAttribute-179 {\n\theight:97px;\n\twidth:329px;\n}\nimg._idGenObjectAttribute-180 {\n\theight:14px;\n\twidth:75px;\n}\nimg._idGenObjectAttribute-181 {\n\theight:127px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-182 {\n\theight:114px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-183 {\n\theight:13px;\n\twidth:36px;\n}\nimg._idGenObjectAttribute-184 {\n\theight:13px;\n\twidth:178px;\n}\nimg._idGenObjectAttribute-185 {\n\theight:14px;\n\twidth:117px;\n}\nimg._idGenObjectAttribute-186 {\n\theight:14px;\n\twidth:116px;\n}\nimg._idGenObjectAttribute-187 {\n\theight:14px;\n\twidth:123px;\n}\nimg._idGenObjectAttribute-188 {\n\theight:13px;\n\twidth:75px;\n}\nimg._idGenObjectAttribute-189 {\n\theight:14px;\n\twidth:160px;\n}\nimg._idGenObjectAttribute-190 {\n\theight:13px;\n\twidth:82px;\n}\nimg._idGenObjectAttribute-191 {\n\theight:18px;\n\twidth:144px;\n}\nimg._idGenObjectAttribute-192 {\n\theight:171px;\n\twidth:223px;\n}\nimg._idGenObjectAttribute-193 {\n\theight:152px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-194 {\n\theight:133px;\n\twidth:243px;\n}\nimg._idGenObjectAttribute-195 {\n\theight:163px;\n\twidth:241px;\n}\nimg._idGenObjectAttribute-196 {\n\theight:71px;\n\twidth:249px;\n}\nimg._idGenObjectAttribute-197 {\n\theight:89px;\n\twidth:233px;\n}\nimg._idGenObjectAttribute-198 {\n\theight:13px;\n\twidth:83px;\n}\nimg._idGenObjectAttribute-199 {\n\theight:155px;\n\twidth:253px;\n}\nimg._idGenObjectAttribute-200 {\n\theight:134px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-201 {\n\theight:141px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-202 {\n\theight:19px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-203 {\n\theight:37px;\n\twidth:90px;\n}\nimg._idGenObjectAttribute-204 {\n\theight:22px;\n\twidth:63px;\n}\nimg._idGenObjectAttribute-205 {\n\theight:19px;\n\twidth:45px;\n}\nimg._idGenObjectAttribute-206 {\n\theight:24px;\n\twidth:50px;\n}\nimg._idGenObjectAttribute-207 {\n\theight:31px;\n\twidth:50px;\n}\nimg._idGenObjectAttribute-208 {\n\theight:32px;\n\twidth:46px;\n}\nimg._idGenObjectAttribute-209 {\n\theight:19px;\n\twidth:51px;\n}\nimg._idGenObjectAttribute-210 {\n\theight:35px;\n\twidth:50px;\n}\nimg._idGenObjectAttribute-211 {\n\theight:34px;\n\twidth:56px;\n}\nimg._idGenObjectAttribute-212 {\n\theight:21px;\n\twidth:55px;\n}\nimg._idGenObjectAttribute-213 {\n\theight:17px;\n\twidth:126px;\n}\nimg._idGenObjectAttribute-214 {\n\theight:39px;\n\twidth:9px;\n}\nimg._idGenObjectAttribute-215 {\n\theight:20px;\n\twidth:149px;\n}\nimg._idGenObjectAttribute-216 {\n\theight:100px;\n\twidth:218px;\n}\nimg._idGenObjectAttribute-217 {\n\theight:40px;\n\twidth:115px;\n}\nimg._idGenObjectAttribute-218 {\n\theight:17px;\n\twidth:123px;\n}\nimg._idGenObjectAttribute-219 {\n\theight:15px;\n\twidth:19px;\n}\nimg._idGenObjectAttribute-220 {\n\theight:14px;\n\twidth:32px;\n}\nimg._idGenObjectAttribute-221 {\n\theight:150px;\n\twidth:195px;\n}\nimg._idGenObjectAttribute-222 {\n\theight:18px;\n\twidth:63px;\n}\nimg._idGenObjectAttribute-223 {\n\theight:73px;\n\twidth:215px;\n}\nimg._idGenObjectAttribute-224 {\n\theight:21px;\n\twidth:63px;\n}\nimg._idGenObjectAttribute-225 {\n\theight:28px;\n\twidth:39px;\n}\nimg._idGenObjectAttribute-226 {\n\theight:29px;\n\twidth:63px;\n}\nimg._idGenObjectAttribute-227 {\n\theight:14px;\n\twidth:163px;\n}\nimg._idGenObjectAttribute-228 {\n\theight:156px;\n\twidth:173px;\n}\nimg._idGenObjectAttribute-229 {\n\theight:13px;\n\twidth:118px;\n}\nimg._idGenObjectAttribute-230 {\n\theight:18px;\n\twidth:126px;\n}\nimg._idGenObjectAttribute-231 {\n\theight:13px;\n\twidth:120px;\n}\nimg._idGenObjectAttribute-232 {\n\theight:55px;\n\twidth:245px;\n}\nimg._idGenObjectAttribute-233 {\n\theight:13px;\n\twidth:159px;\n}\nimg._idGenObjectAttribute-234 {\n\theight:13px;\n\twidth:102px;\n}\nimg._idGenObjectAttribute-235 {\n\theight:13px;\n\twidth:123px;\n}\nimg._idGenObjectAttribute-236 {\n\theight:13px;\n\twidth:76px;\n}\nimg._idGenObjectAttribute-237 {\n\theight:20px;\n\twidth:58px;\n}\nimg._idGenObjectAttribute-238 {\n\theight:22px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-239 {\n\theight:69px;\n\twidth:34px;\n}\nimg._idGenObjectAttribute-240 {\n\theight:32px;\n\twidth:53px;\n}\nimg._idGenObjectAttribute-241 {\n\theight:62px;\n\twidth:37px;\n}\nimg._idGenObjectAttribute-242 {\n\theight:34px;\n\twidth:68px;\n}\nimg._idGenObjectAttribute-243 {\n\theight:65px;\n\twidth:32px;\n}\nimg._idGenObjectAttribute-244 {\n\theight:19px;\n\twidth:15px;\n}\nimg._idGenObjectAttribute-245 {\n\theight:11px;\n\twidth:51px;\n}\nimg._idGenObjectAttribute-246 {\n\theight:50px;\n\twidth:28px;\n}\nimg._idGenObjectAttribute-247 {\n\theight:52px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-248 {\n\theight:51px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-249 {\n\theight:35px;\n\twidth:66px;\n}\nimg._idGenObjectAttribute-250 {\n\theight:53px;\n\twidth:32px;\n}\nimg._idGenObjectAttribute-251 {\n\theight:55px;\n\twidth:30px;\n}\nimg._idGenObjectAttribute-252 {\n\theight:56px;\n\twidth:30px;\n}\nimg._idGenObjectAttribute-253 {\n\theight:57px;\n\twidth:32px;\n}\nimg._idGenObjectAttribute-254 {\n\theight:19px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-255 {\n\theight:35px;\n\twidth:18px;\n}\nimg._idGenObjectAttribute-256 {\n\theight:58px;\n\twidth:95px;\n}\nimg._idGenObjectAttribute-257 {\n\theight:38px;\n\twidth:218px;\n}\nimg._idGenObjectAttribute-258 {\n\theight:76px;\n\twidth:32px;\n}\nimg._idGenObjectAttribute-259 {\n\theight:31px;\n\twidth:72px;\n}\nimg._idGenObjectAttribute-260 {\n\theight:40px;\n\twidth:73px;\n}\nimg._idGenObjectAttribute-261 {\n\theight:70px;\n\twidth:87px;\n}\nimg._idGenObjectAttribute-262 {\n\theight:17px;\n\twidth:52px;\n}\nimg._idGenObjectAttribute-263 {\n\theight:40px;\n\twidth:114px;\n}\nimg._idGenObjectAttribute-264 {\n\theight:33px;\n\twidth:78px;\n}\nimg._idGenObjectAttribute-265 {\n\theight:36px;\n\twidth:82px;\n}\nimg._idGenObjectAttribute-266 {\n\theight:66px;\n\twidth:169px;\n}\nimg._idGenObjectAttribute-267 {\n\theight:19px;\n\twidth:59px;\n}\nimg._idGenObjectAttribute-268 {\n\theight:34px;\n\twidth:25px;\n}\nimg._idGenObjectAttribute-269 {\n\theight:38px;\n\twidth:79px;\n}\nimg._idGenObjectAttribute-270 {\n\theight:52px;\n\twidth:52px;\n}\nimg._idGenObjectAttribute-271 {\n\theight:18px;\n\twidth:24px;\n}\nimg._idGenObjectAttribute-272 {\n\theight:22px;\n\twidth:57px;\n}\nimg._idGenObjectAttribute-273 {\n\theight:22px;\n\twidth:30px;\n}\nimg._idGenObjectAttribute-274 {\n\theight:38px;\n\twidth:73px;\n}\nimg._idGenObjectAttribute-275 {\n\theight:22px;\n\twidth:65px;\n}\nimg._idGenObjectAttribute-276 {\n\theight:33px;\n\twidth:119px;\n}\nimg._idGenObjectAttribute-277 {\n\theight:24px;\n\twidth:54px;\n}\nimg._idGenObjectAttribute-278 {\n\theight:22px;\n\twidth:49px;\n}\nimg._idGenObjectAttribute-279 {\n\theight:22px;\n\twidth:64px;\n}\nimg._idGenObjectAttribute-280 {\n\theight:37px;\n\twidth:50px;\n}\nimg._idGenObjectAttribute-281 {\n\theight:21px;\n\twidth:33px;\n}\nimg._idGenObjectAttribute-282 {\n\theight:43px;\n\twidth:55px;\n}\nimg._idGenObjectAttribute-283 {\n\theight:22px;\n\twidth:47px;\n}\nimg._idGenObjectAttribute-284 {\n\theight:73px;\n\twidth:96px;\n}\nimg._idGenObjectAttribute-285 {\n\theight:18px;\n\twidth:38px;\n}\nimg._idGenObjectAttribute-286 {\n\theight:19px;\n\twidth:38px;\n}\nimg._idGenObjectAttribute-287 {\n\theight:19px;\n\twidth:86px;\n}\nimg._idGenObjectAttribute-288 {\n\theight:22px;\n\twidth:42px;\n}\nimg._idGenObjectAttribute-289 {\n\theight:22px;\n\twidth:38px;\n}\nimg._idGenObjectAttribute-290 {\n\theight:21px;\n\twidth:32px;\n}\nimg._idGenObjectAttribute-291 {\n\theight:22px;\n\twidth:51px;\n}\nimg._idGenObjectAttribute-292 {\n\theight:24px;\n\twidth:33px;\n}\nimg._idGenObjectAttribute-293 {\n\theight:30px;\n\twidth:46px;\n}\nimg._idGenObjectAttribute-294 {\n\theight:30px;\n\twidth:44px;\n}\nimg._idGenObjectAttribute-295 {\n\theight:28px;\n\twidth:44px;\n}\nimg._idGenObjectAttribute-296 {\n\theight:18px;\n\twidth:33px;\n}\nimg._idGenObjectAttribute-297 {\n\theight:18px;\n\twidth:29px;\n}\nimg._idGenObjectAttribute-298 {\n\theight:76px;\n\twidth:36px;\n}\nimg._idGenObjectAttribute-299 {\n\theight:54px;\n\twidth:31px;\n}\nimg._idGenObjectAttribute-300 {\n\theight:54px;\n\twidth:59px;\n}\nimg._idGenObjectAttribute-301 {\n\theight:62px;\n\twidth:56px;\n}\nimg._idGenObjectAttribute-302 {\n\theight:24px;\n\twidth:88px;\n}\nimg._idGenObjectAttribute-303 {\n\theight:24px;\n\twidth:85px;\n}\nimg._idGenObjectAttribute-304 {\n\theight:24px;\n\twidth:93px;\n}\nimg._idGenObjectAttribute-305 {\n\theight:24px;\n\twidth:57px;\n}\nimg._idGenObjectAttribute-306 {\n\theight:36px;\n\twidth:37px;\n}\nimg._idGenObjectAttribute-307 {\n\theight:55px;\n\twidth:169px;\n}\nimg._idGenObjectAttribute-308 {\n\theight:35px;\n\twidth:47px;\n}\nimg._idGenObjectAttribute-309 {\n\theight:17px;\n\twidth:22px;\n}\nimg._idGenObjectAttribute-310 {\n\theight:22px;\n\twidth:29px;\n}\nimg._idGenObjectAttribute-311 {\n\theight:24px;\n\twidth:44px;\n}\nimg._idGenObjectAttribute-312 {\n\theight:75px;\n\twidth:65px;\n}\nimg._idGenObjectAttribute-313 {\n\theight:74px;\n\twidth:61px;\n}\nimg._idGenObjectAttribute-314 {\n\theight:74px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-315 {\n\theight:74px;\n\twidth:31px;\n}\nimg._idGenObjectAttribute-316 {\n\theight:41px;\n\twidth:95px;\n}\nimg._idGenObjectAttribute-317 {\n\theight:24px;\n\twidth:91px;\n}\nimg._idGenObjectAttribute-318 {\n\theight:24px;\n\twidth:75px;\n}\nimg._idGenObjectAttribute-319 {\n\theight:24px;\n\twidth:80px;\n}\nimg._idGenObjectAttribute-320 {\n\theight:23px;\n\twidth:33px;\n}\nimg._idGenObjectAttribute-321 {\n\theight:22px;\n\twidth:58px;\n}\nimg._idGenObjectAttribute-322 {\n\theight:55px;\n\twidth:110px;\n}\nimg._idGenObjectAttribute-323 {\n\theight:21px;\n\twidth:44px;\n}\nimg._idGenObjectAttribute-324 {\n\theight:49px;\n\twidth:74px;\n}\nimg._idGenObjectAttribute-325 {\n\theight:23px;\n\twidth:69px;\n}\nimg._idGenObjectAttribute-326 {\n\theight:20px;\n\twidth:78px;\n}\nimg._idGenObjectAttribute-327 {\n\theight:46px;\n\twidth:166px;\n}\nimg._idGenObjectAttribute-328 {\n\theight:61px;\n\twidth:70px;\n}\nimg._idGenObjectAttribute-329 {\n\theight:60px;\n\twidth:74px;\n}\nimg._idGenObjectAttribute-330 {\n\theight:54px;\n\twidth:72px;\n}\nimg._idGenObjectAttribute-331 {\n\theight:23px;\n\twidth:62px;\n}\nimg._idGenObjectAttribute-332 {\n\theight:34px;\n\twidth:38px;\n}\nimg._idGenObjectAttribute-333 {\n\theight:33px;\n\twidth:54px;\n}\nimg._idGenObjectAttribute-334 {\n\theight:53px;\n\twidth:39px;\n}\nimg._idGenObjectAttribute-335 {\n\theight:33px;\n\twidth:55px;\n}\nimg._idGenObjectAttribute-336 {\n\theight:31px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-337 {\n\theight:19px;\n\twidth:49px;\n}\nimg._idGenObjectAttribute-338 {\n\theight:16px;\n\twidth:30px;\n}\nimg._idGenObjectAttribute-339 {\n\theight:19px;\n\twidth:30px;\n}\nimg._idGenObjectAttribute-340 {\n\theight:19px;\n\twidth:28px;\n}\nimg._idGenObjectAttribute-341 {\n\theight:18px;\n\twidth:58px;\n}\nimg._idGenObjectAttribute-342 {\n\theight:16px;\n\twidth:48px;\n}\nimg._idGenObjectAttribute-343 {\n\theight:38px;\n\twidth:46px;\n}\nimg._idGenObjectAttribute-344 {\n\theight:19px;\n\twidth:58px;\n}\nimg._idGenObjectAttribute-345 {\n\theight:16px;\n\twidth:39px;\n}\nimg._idGenObjectAttribute-346 {\n\theight:33px;\n\twidth:52px;\n}\nimg._idGenObjectAttribute-347 {\n\theight:21px;\n\twidth:150px;\n}\nimg._idGenObjectAttribute-348 {\n\theight:20px;\n\twidth:150px;\n}\nimg._idGenObjectAttribute-349 {\n\theight:34px;\n\twidth:141px;\n}\nimg._idGenObjectAttribute-350 {\n\theight:20px;\n\twidth:174px;\n}\nimg._idGenObjectAttribute-351 {\n\theight:60px;\n\twidth:157px;\n}\nimg._idGenObjectAttribute-352 {\n\theight:20px;\n\twidth:69px;\n}\nimg._idGenObjectAttribute-353 {\n\theight:31px;\n\twidth:42px;\n}\nimg._idGenObjectAttribute-354 {\n\theight:34px;\n\twidth:64px;\n}\nimg._idGenObjectAttribute-355 {\n\theight:50px;\n\twidth:77px;\n}\nimg._idGenObjectAttribute-356 {\n\theight:40px;\n\twidth:69px;\n}\nimg._idGenObjectAttribute-357 {\n\theight:21px;\n\twidth:69px;\n}\nimg._idGenObjectAttribute-358 {\n\theight:30px;\n\twidth:37px;\n}\nimg._idGenObjectAttribute-359 {\n\theight:18px;\n\twidth:27px;\n}\nimg._idGenObjectAttribute-360 {\n\theight:7px;\n\twidth:34px;\n}\nimg._idGenObjectAttribute-361 {\n\theight:7px;\n\twidth:24px;\n}\nimg._idGenObjectAttribute-362 {\n\theight:36px;\n\twidth:53px;\n}\nimg._idGenObjectAttribute-363 {\n\theight:37px;\n\twidth:79px;\n}\nimg._idGenObjectAttribute-364 {\n\theight:22px;\n\twidth:67px;\n}\nimg._idGenObjectAttribute-365 {\n\theight:98px;\n\twidth:394px;\n}\nimg._idGenObjectAttribute-366 {\n\theight:96px;\n\twidth:459px;\n}\nimg._idGenObjectAttribute-367 {\n\theight:25px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-368 {\n\theight:21px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-369 {\n\theight:132px;\n\twidth:148px;\n}\nimg._idGenObjectAttribute-370 {\n\theight:59px;\n\twidth:126px;\n}\nimg._idGenObjectAttribute-371 {\n\theight:150px;\n\twidth:150px;\n}\nimg._idGenObjectAttribute-372 {\n\theight:44px;\n\twidth:239px;\n}\nimg._idGenObjectAttribute-373 {\n\theight:108px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-374 {\n\theight:35px;\n\twidth:160px;\n}\nimg._idGenObjectAttribute-375 {\n\theight:39px;\n\twidth:182px;\n}\nimg._idGenObjectAttribute-376 {\n\theight:63px;\n\twidth:194px;\n}\nimg._idGenObjectAttribute-377 {\n\theight:51px;\n\twidth:119px;\n}\nimg._idGenObjectAttribute-378 {\n\theight:70px;\n\twidth:209px;\n}\nimg._idGenObjectAttribute-379 {\n\theight:31px;\n\twidth:217px;\n}\nimg._idGenObjectAttribute-380 {\n\theight:76px;\n\twidth:182px;\n}\nimg._idGenObjectAttribute-381 {\n\theight:59px;\n\twidth:179px;\n}\nimg._idGenObjectAttribute-382 {\n\theight:32px;\n\twidth:243px;\n}\nimg._idGenObjectAttribute-383 {\n\theight:75px;\n\twidth:174px;\n}\nimg._idGenObjectAttribute-384 {\n\theight:158px;\n\twidth:223px;\n}\nimg._idGenObjectAttribute-385 {\n\theight:33px;\n\twidth:161px;\n}\nimg._idGenObjectAttribute-386 {\n\theight:28px;\n\twidth:96px;\n}\nimg._idGenObjectAttribute-387 {\n\theight:34px;\n\twidth:185px;\n}\nimg._idGenObjectAttribute-388 {\n\theight:148px;\n\twidth:236px;\n}\nimg._idGenObjectAttribute-389 {\n\theight:55px;\n\twidth:141px;\n}\nimg._idGenObjectAttribute-390 {\n\theight:58px;\n\twidth:134px;\n}\nimg._idGenObjectAttribute-391 {\n\theight:37px;\n\twidth:81px;\n}\nimg._idGenObjectAttribute-392 {\n\theight:119px;\n\twidth:202px;\n}\nimg._idGenObjectAttribute-393 {\n\theight:22px;\n\twidth:52px;\n}\nimg._idGenObjectAttribute-394 {\n\theight:49px;\n\twidth:197px;\n}\nimg._idGenObjectAttribute-395 {\n\theight:41px;\n\twidth:94px;\n}\nimg._idGenObjectAttribute-396 {\n\theight:75px;\n\twidth:130px;\n}\nimg._idGenObjectAttribute-397 {\n\theight:41px;\n\twidth:117px;\n}\nimg._idGenObjectAttribute-398 {\n\theight:46px;\n\twidth:80px;\n}\nimg._idGenObjectAttribute-399 {\n\theight:61px;\n\twidth:216px;\n}\nimg._idGenObjectAttribute-400 {\n\theight:33px;\n\twidth:51px;\n}\nimg._idGenObjectAttribute-401 {\n\theight:129px;\n\twidth:172px;\n}\nimg._idGenObjectAttribute-402 {\n\theight:19px;\n\twidth:53px;\n}\nimg._idGenObjectAttribute-403 {\n\theight:20px;\n\twidth:56px;\n}\nimg._idGenObjectAttribute-404 {\n\theight:47px;\n\twidth:31px;\n}\nimg._idGenObjectAttribute-405 {\n\theight:7px;\n\twidth:22px;\n}\nimg._idGenObjectAttribute-406 {\n\theight:98px;\n\twidth:211px;\n}\nimg._idGenObjectAttribute-407 {\n\theight:48px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-408 {\n\theight:57px;\n\twidth:223px;\n}\nimg._idGenObjectAttribute-409 {\n\theight:48px;\n\twidth:41px;\n}\nimg._idGenObjectAttribute-410 {\n\theight:48px;\n\twidth:27px;\n}\nimg._idGenObjectAttribute-411 {\n\theight:21px;\n\twidth:43px;\n}\nimg._idGenObjectAttribute-412 {\n\theight:34px;\n\twidth:190px;\n}\nimg._idGenObjectAttribute-413 {\n\theight:22px;\n\twidth:41px;\n}\nimg._idGenObjectAttribute-414 {\n\theight:92px;\n\twidth:218px;\n}\nimg._idGenObjectAttribute-415 {\n\theight:19px;\n\twidth:24px;\n}\nimg._idGenObjectAttribute-416 {\n\theight:130px;\n\twidth:212px;\n}\nimg._idGenObjectAttribute-417 {\n\theight:71px;\n\twidth:193px;\n}\nimg._idGenObjectAttribute-418 {\n\theight:53px;\n\twidth:215px;\n}\nimg._idGenObjectAttribute-419 {\n\theight:68px;\n\twidth:27px;\n}\nimg._idGenObjectAttribute-420 {\n\theight:48px;\n\twidth:48px;\n}\nimg._idGenObjectAttribute-421 {\n\theight:54px;\n\twidth:48px;\n}\nimg._idGenObjectAttribute-422 {\n\theight:44px;\n\twidth:175px;\n}\nimg._idGenObjectAttribute-423 {\n\theight:139px;\n\twidth:211px;\n}\nimg._idGenObjectAttribute-424 {\n\theight:51px;\n\twidth:213px;\n}\nimg._idGenObjectAttribute-425 {\n\theight:21px;\n\twidth:28px;\n}\nimg._idGenObjectAttribute-426 {\n\theight:22px;\n\twidth:34px;\n}\nimg._idGenObjectAttribute-427 {\n\theight:62px;\n\twidth:186px;\n}\nimg._idGenObjectAttribute-428 {\n\theight:95px;\n\twidth:187px;\n}\nimg._idGenObjectAttribute-429 {\n\theight:85px;\n\twidth:180px;\n}\nimg._idGenObjectAttribute-430 {\n\theight:85px;\n\twidth:213px;\n}\nimg._idGenObjectAttribute-431 {\n\theight:72px;\n\twidth:204px;\n}\nimg._idGenObjectAttribute-432 {\n\theight:67px;\n\twidth:178px;\n}\nimg._idGenObjectAttribute-433 {\n\theight:37px;\n\twidth:114px;\n}\nimg._idGenObjectAttribute-434 {\n\theight:116px;\n\twidth:252px;\n}\nimg._idGenObjectAttribute-435 {\n\theight:17px;\n\twidth:69px;\n}\nimg._idGenObjectAttribute-436 {\n\theight:49px;\n\twidth:41px;\n}\nimg._idGenObjectAttribute-437 {\n\theight:19px;\n\twidth:72px;\n}\nimg._idGenObjectAttribute-438 {\n\theight:49px;\n\twidth:62px;\n}\nimg._idGenObjectAttribute-439 {\n\theight:17px;\n\twidth:68px;\n}\nimg._idGenObjectAttribute-440 {\n\theight:47px;\n\twidth:215px;\n}\nimg._idGenObjectAttribute-441 {\n\theight:36px;\n\twidth:79px;\n}\nimg._idGenObjectAttribute-442 {\n\theight:68px;\n\twidth:99px;\n}\nimg._idGenObjectAttribute-443 {\n\theight:88px;\n\twidth:193px;\n}\nimg._idGenObjectAttribute-444 {\n\theight:162px;\n\twidth:210px;\n}\nimg._idGenObjectAttribute-445 {\n\theight:71px;\n\twidth:136px;\n}\nimg._idGenObjectAttribute-446 {\n\theight:37px;\n\twidth:8px;\n}\nimg._idGenObjectAttribute-447 {\n\theight:64px;\n\twidth:175px;\n}\nimg._idGenObjectAttribute-448 {\n\theight:166px;\n\twidth:215px;\n}\nimg._idGenObjectAttribute-449 {\n\theight:135px;\n\twidth:188px;\n}\nimg._idGenObjectAttribute-450 {\n\theight:52px;\n\twidth:90px;\n}\nimg._idGenObjectAttribute-451 {\n\theight:94px;\n\twidth:124px;\n}\nimg._idGenObjectAttribute-452 {\n\theight:45px;\n\twidth:61px;\n}\nimg._idGenObjectAttribute-453 {\n\theight:50px;\n\twidth:53px;\n}\nimg._idGenObjectAttribute-454 {\n\theight:50px;\n\twidth:106px;\n}\nimg._idGenObjectAttribute-455 {\n\theight:39px;\n\twidth:123px;\n}\nimg._idGenObjectAttribute-456 {\n\theight:33px;\n\twidth:48px;\n}\nimg._idGenObjectAttribute-457 {\n\theight:35px;\n\twidth:62px;\n}\nimg._idGenObjectAttribute-458 {\n\theight:33px;\n\twidth:90px;\n}\nimg._idGenObjectAttribute-459 {\n\theight:33px;\n\twidth:65px;\n}\nimg._idGenObjectAttribute-460 {\n\theight:33px;\n\twidth:62px;\n}\nimg._idGenObjectAttribute-461 {\n\theight:41px;\n\twidth:136px;\n}\nimg._idGenObjectAttribute-462 {\n\theight:33px;\n\twidth:44px;\n}\nimg._idGenObjectAttribute-463 {\n\theight:65px;\n\twidth:56px;\n}\nimg._idGenObjectAttribute-464 {\n\theight:67px;\n\twidth:156px;\n}\nimg._idGenObjectAttribute-465 {\n\theight:130px;\n\twidth:214px;\n}\nimg._idGenObjectAttribute-466 {\n\theight:49px;\n\twidth:34px;\n}\nimg._idGenObjectAttribute-467 {\n\theight:49px;\n\twidth:37px;\n}\nimg._idGenObjectAttribute-468 {\n\theight:47px;\n\twidth:25px;\n}\nimg._idGenObjectAttribute-469 {\n\theight:67px;\n\twidth:124px;\n}\nimg._idGenObjectAttribute-470 {\n\theight:33px;\n\twidth:36px;\n}\nimg._idGenObjectAttribute-471 {\n\theight:29px;\n\twidth:25px;\n}\nimg._idGenObjectAttribute-472 {\n\theight:39px;\n\twidth:127px;\n}\nimg._idGenObjectAttribute-473 {\n\theight:35px;\n\twidth:51px;\n}\nimg._idGenObjectAttribute-474 {\n\theight:7px;\n\twidth:14px;\n}\nimg._idGenObjectAttribute-475 {\n\theight:21px;\n\twidth:31px;\n}\nimg._idGenObjectAttribute-476 {\n\theight:37px;\n\twidth:54px;\n}\nimg._idGenObjectAttribute-477 {\n\theight:35px;\n\twidth:48px;\n}\nimg._idGenObjectAttribute-478 {\n\theight:51px;\n\twidth:63px;\n}\nimg._idGenObjectAttribute-479 {\n\theight:51px;\n\twidth:70px;\n}\nimg._idGenObjectAttribute-480 {\n\theight:51px;\n\twidth:56px;\n}\nimg._idGenObjectAttribute-481 {\n\theight:67px;\n\twidth:71px;\n}\nimg._idGenObjectAttribute-482 {\n\theight:47px;\n\twidth:64px;\n}\nimg._idGenObjectAttribute-483 {\n\theight:35px;\n\twidth:64px;\n}\nimg._idGenObjectAttribute-484 {\n\theight:29px;\n\twidth:48px;\n}\nimg._idGenObjectAttribute-485 {\n\theight:35px;\n\twidth:71px;\n}\nimg._idGenObjectAttribute-486 {\n\theight:37px;\n\twidth:86px;\n}\nimg._idGenObjectAttribute-487 {\n\theight:35px;\n\twidth:102px;\n}\nimg._idGenObjectAttribute-488 {\n\theight:35px;\n\twidth:81px;\n}\nimg._idGenObjectAttribute-489 {\n\theight:76px;\n\twidth:198px;\n}\nimg._idGenObjectAttribute-490 {\n\theight:35px;\n\twidth:60px;\n}\nimg._idGenObjectAttribute-491 {\n\theight:17px;\n\twidth:71px;\n}\nimg._idGenObjectAttribute-492 {\n\theight:16px;\n\twidth:18px;\n}\nimg._idGenObjectAttribute-493 {\n\theight:67px;\n\twidth:23px;\n}\nimg._idGenObjectAttribute-494 {\n\theight:29px;\n\twidth:16px;\n}\nimg._idGenObjectAttribute-495 {\n\theight:67px;\n\twidth:25px;\n}\nimg._idGenObjectAttribute-496 {\n\theight:48px;\n\twidth:25px;\n}\nimg._idGenObjectAttribute-497 {\n\theight:70px;\n\twidth:39px;\n}\nimg._idGenObjectAttribute-498 {\n\theight:19px;\n\twidth:7px;\n}\nimg._idGenObjectAttribute-499 {\n\theight:44px;\n\twidth:22px;\n}\nimg._idGenObjectAttribute-500 {\n\theight:249px;\n\twidth:299px;\n}\nimg._idGenObjectAttribute-501 {\n\theight:63px;\n\twidth:25px;\n}\nimg._idGenObjectAttribute-502 {\n\theight:19px;\n\twidth:26px;\n}\nimg._idGenObjectAttribute-503 {\n\theight:130px;\n\twidth:30px;\n}\nimg._idGenObjectAttribute-504 {\n\theight:288px;\n\twidth:35px;\n}\nimg._idGenObjectAttribute-505 {\n\theight:279px;\n\twidth:142px;\n}\nimg._idGenObjectAttribute-506 {\n\theight:273px;\n\twidth:148px;\n}\ndiv._idGenObjectStyleOverride-1 {\n\tbackground-color:#dae6f5;\n\tborder-width:0px;\n}\ndiv._idGenObjectStyleOverride-2 {\n\tbackground-color:#5aa0d7;\n\tborder-color:#ffffff;\n\tborder-style:solid;\n\tborder-width:2px;\n}\ndiv._idGenObjectStyleOverride-3 {\n\tbackground-color:#ffffff;\n\tborder-width:0px;\n}\ndiv._idGenObjectStyleOverride-4 {\n\tbackground-color:#cadbf1;\n\tborder-bottom-left-radius:4px;\n\tborder-bottom-right-radius:4px;\n\tborder-top-left-radius:4px;\n\tborder-top-right-radius:4px;\n\tborder-width:0px;\n}\ndiv._idGenObjectStyleOverride-5 {\n\tbackground-color:#f3f6fc;\n\tborder-color:#bad2ed;\n\tborder-style:solid;\n\tborder-width:3px;\n}\ndiv._idGenObjectStyleOverride-6 {\n\tbackground-color:#5aa0d7;\n\tborder-bottom-left-radius:3px;\n\tborder-bottom-right-radius:3px;\n\tborder-top-left-radius:3px;\n\tborder-top-right-radius:3px;\n}\ndiv._idGenObjectStyleOverride-7 {\n\tbackground-color:#ffffff;\n\tborder-color:#5aa0d7;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-8 {\n\tbackground-color:#5aa0d7;\n\tborder-bottom-left-radius:4px;\n\tborder-bottom-right-radius:4px;\n\tborder-top-left-radius:4px;\n\tborder-top-right-radius:4px;\n\tborder-width:0px;\n}\ndiv._idGenObjectStyleOverride-9 {\n\tbackground-color:#000000;\n\tborder-bottom-left-radius:0px;\n\tborder-bottom-right-radius:0px;\n\tborder-style:dotted;\n\tborder-top-left-radius:9px;\n\tborder-top-right-radius:1px;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-10 {\n\tbackground-color:#f3f6fc;\n\tborder-color:#5aa0d7;\n\tborder-style:solid;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-11 {\n\tbackground-color:#5aa0d7;\n\tborder-color:#ffffff;\n\tborder-style:solid;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-12 {\n\tborder-style:dotted;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-13 {\n\tbackground-color:#58595b;\n\tborder-width:0px;\n}\ndiv._idGenObjectStyleOverride-14 {\n\tbackground-color:#ffffff;\n\tborder-bottom-right-radius:2px;\n\tborder-top-right-radius:2px;\n\tborder-width:0px;\n}\ndiv._idGenObjectStyleOverride-15 {\n\tbackground-color:#4ec8eb;\n\tborder-width:0px;\n}\ndiv._idGenObjectStyleOverride-16 {\n\tbackground-color:#bd202e;\n\tborder-width:0px;\n}\ndiv._idGenObjectStyleOverride-17 {\n\tborder-bottom-left-radius:12px;\n\tborder-bottom-right-radius:12px;\n\tborder-color:#ffffff;\n\tborder-style:solid;\n\tborder-top-left-radius:12px;\n\tborder-top-right-radius:12px;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-18 {\n\tbackground-color:#0080c6;\n\tborder-bottom-left-radius:3px;\n\tborder-bottom-right-radius:3px;\n\tborder-color:#0080c6;\n\tborder-top-left-radius:3px;\n\tborder-top-right-radius:3px;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-19 {\n\tbackground-color:#e4ebf7;\n\tborder-bottom-left-radius:3px;\n\tborder-bottom-right-radius:3px;\n\tborder-color:#3f92cf;\n\tborder-top-left-radius:3px;\n\tborder-top-right-radius:3px;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-20 {\n\tbackground-color:#fde9f1;\n\tborder-bottom-left-radius:3px;\n\tborder-bottom-right-radius:3px;\n\tborder-color:#ef5ba1;\n\tborder-top-left-radius:3px;\n\tborder-top-right-radius:3px;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-21 {\n\tbackground-color:#fad5e5;\n\tborder-bottom-left-radius:3px;\n\tborder-bottom-right-radius:3px;\n\tborder-color:#ef5ba1;\n\tborder-top-left-radius:3px;\n\tborder-top-right-radius:3px;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-22 {\n\tbackground-color:#ededee;\n\tborder-color:#ec008c;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-23 {\n\tbackground-color:#ededee;\n\tborder-color:#0080c6;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-24 {\n\tborder-color:#0080c6;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-25 {\n\tbackground-color:#ccdbf1;\n\tborder-bottom-left-radius:3px;\n\tborder-bottom-right-radius:3px;\n\tborder-color:#3f92cf;\n\tborder-top-left-radius:3px;\n\tborder-top-right-radius:3px;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-26 {\n\tbackground-color:#ec008c;\n\tborder-bottom-left-radius:3px;\n\tborder-bottom-right-radius:3px;\n\tborder-color:#ec008c;\n\tborder-top-left-radius:3px;\n\tborder-top-right-radius:3px;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-27 {\n\tborder-color:#ec008c;\n\tborder-width:1px;\n}\ndiv._idGenObjectStyleOverride-28 {\n\tbackground-color:#ed1c24;\n\tborder-width:0px;\n}\ndiv._idGenObjectStyleOverride-29 {\n\tborder-bottom-left-radius:8px;\n\tborder-bottom-right-radius:8px;\n\tborder-top-left-radius:8px;\n\tborder-top-right-radius:8px;\n}\ndiv._idGenObjectLayout-1 {\n\ttext-align:center;\n}\n" }